Hi @anorlunda ,
So i know from the graph windage/friction losses constitute the power lost when the stator voltage=0V. I have actually reworked this question and got something I am more happy with. I've actually said the windage/friction loss is 220W from extending the graph to 0V. I know that...
So I've attached my graph and found that the windage/friction losses occur roughly around 230Watts. I just don't know how i further explain the magnetising current I0. I know I0 = input current on no load. So do i assumed from P = √3 x VL x IL x CosФ that CosФ=230/√3*220*6.8= 0.0849 or...
Homework Statement
Uploaded as image 1 I will show my workings for 2 if 1 are in the right direction
I also don't understand what is meant as I/O Designation charts (nowhere in my study notes)
Homework Equations
None
The Attempt at a Solution
Uploaded as image 2 is my attempt.
Apologies I think I've gotten myself confused... I think I am looking too deep into it. I'll be back when i have some form of graph! Thanks for your help @rude man
This is what I'm unsure of, if it mentioned one of the above i could work through it via my notes... I've only encountered step change input for second order systems. Thus i understand which ones are under-damped (a/b) and which are over-damped c if this is the case. But how do i draw this? only...
Homework Statement
Sketch, on a set of common axes, waveforms to represent the transient
response of circuits having transfer functions with the following parameters:
a) ζ = 0.5, ω = 1×10^3 rad s^-1
b) ζ = 0.2, ω = 2×10^3 rad s^-1
c) ζ = 2, ω = 1×10^3 rad s^-1
Homework Equations
wd=wo√(1-ζ^2)...
Apologies i didn't add the image. So are you saying to integrate the sine wave between T/4 & T? Sorry only thing i found in my notes was very little other than the statement above.
Homework Statement
a) If the firing angle is set for alpha=(pi/3) estimate the power dissipated in the bulb if it is rated at 100 W and the voltage source is 230 V @ 50 Hz.
b) An anomaly that can occur in controlled rectification is drift of the firing
angle on one half cycle, so causing an...
Oh yeah! So by shifting it to the right by T/2 you would get a regular square wave? and thus making it have only sine terms. With regards to to whether they have symmetry I actually cannot tell now, it doesn't look symmetrial about the y-axis so it's not an even function but it doesn't have...