Sketch the waveform to represent the transient response

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SUMMARY

This discussion focuses on sketching waveforms representing the transient response of second-order circuits with specific transfer function parameters: (a) ζ = 0.5, ω = 1×10^3 rad/s; (b) ζ = 0.2, ω = 2×10^3 rad/s; and (c) ζ = 2, ω = 1×10^3 rad/s. The calculations for the damped natural frequency (wd), time to peak overshoot, and overshoot are provided for cases (a) and (b), while case (c) is identified as over-damped with no oscillation. The discussion emphasizes the need for a step input to accurately draw the output graphs and suggests researching second-order system responses for visual representation.

PREREQUISITES
  • Understanding of second-order system dynamics
  • Familiarity with transfer functions and damping ratios (ζ)
  • Knowledge of overshoot and time to peak overshoot calculations
  • Ability to interpret and sketch waveforms based on mathematical equations
NEXT STEPS
  • Research "second-order system responses" for visual examples of under-damped and over-damped systems
  • Learn about the impact of different damping ratios on transient response waveforms
  • Study the relationship between natural frequency (ω) and damping ratio (ζ) in system behavior
  • Explore tools for graphing mathematical functions to visualize transient responses
USEFUL FOR

Students and professionals in electrical engineering, control systems, and circuit analysis who need to understand and visualize the transient responses of second-order systems.

Connorm1
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Homework Statement


Sketch, on a set of common axes, waveforms to represent the transient
response of circuits having transfer functions with the following parameters:

a) ζ = 0.5, ω = 1×10^3 rad s^-1
b) ζ = 0.2, ω = 2×10^3 rad s^-1
c) ζ = 2, ω = 1×10^3 rad s^-1

Homework Equations


wd=wo√(1-ζ^2)
Time to peak overshoot = π/wd
overshoot = e-(ζπ)/(√(1-ζ^2))

The Attempt at a Solution


So with this in mind for
a)
wd=(1*103)√(1-0.5^2) = 866.025
Time to peak overshoot = π/wd = 0.00363seconds
overshoot = e-(ζπ)/(√(1-ζ^2)) = 0.16303

b)
wd=(2*103)√(1-0.2^2) = 866.025
Time to peak overshoot = π/wd = 0.00363seconds
overshoot = e-(ζπ)/(√(1-ζ^2)) = 0.16303

c) will have no overshoot as ζ = 2>1 (which means no oscillation).

How do i actually draw these as graphs now? is there more info i need?

do i also need to use
70a65de9499e2ee26449ef7e0ef7f22b4158ae9f
?
 
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What's the input? Step? Delta? Ramp? ...
Given this you can solve your ODE but there are many places to look up under-damped, critically damped, and over-damped 2nd order systems.
 
This is what I'm unsure of, if it mentioned one of the above i could work through it via my notes... I've only encountered step change input for second order systems. Thus i understand which ones are under-damped (a/b) and which are over-damped c if this is the case. But how do i draw this? only thing i can see from the graph is y(t)=1 but how do i find x(t) & the time period...
 
Connorm1 said:
This is what I'm unsure of, if it mentioned one of the above i could work through it via my notes... I've only encountered step change input for second order systems. Thus i understand which ones are under-damped (a/b) and which are over-damped c if this is the case.
Assume step input then.
But how do i draw this? only thing i can see from the graph is y(t)=1
Say what? The output is a constant dc voltage? And what graph? You haven't provided one for us to look at.
You have the information you need to draw the output graphs. I suggest looking up the various possible graphs depending on ζ and ω for a step input. Widely available on the web.
 
rude man said:
Assume step input then.Say what? The output is a constant dc voltage? And what graph? You haven't provided one for us to look at.
Apologies I think I've gotten myself confused... I think I am looking too deep into it. I'll be back when i have some form of graph! Thanks for your help @rude man
 
Connorm1 said:
Apologies I think I've gotten myself confused... I think I am looking too deep into it. I'll be back when i have some form of graph! Thanks for your help @rude man
Good idea. Google "second order systems responses". The curves will all be there.
 
@rude man so after searching through second order system responses I have a graph that looks like this. How does it look?
 

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That's the idea.
Make sure yu understand which waveform corresponds to your values of ωn and ζ.

You should also understand how your ODE in your post 1 solves to those waveforms. That equation requires one or two initial conditions otherwise you get nothing from it.
 

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