Recent content by Erebus_Oneiros

Thanks for your great advice! Just a quick question: so I was thinking of letting the supervisor know about it in the worst case scenario in the future (as talking to him is out of question, tried once he had "I don't give a s**t attitude about it). But won't the supervisor interpret this as me...

I agree. I tried to say "standard exam problems" -> "usual plug n chug problems". Changed the question details to better reflect my point.

Advice before joining PhD research group, if I have a personal problem with one of the group members? One more student from my cohort wants to join the same research group as me. We will be doing our research rotation together. He has an overbearing attitude and is insolent towards anyone...

How do you effectively self-study physics using a textbook? Defining "effective" (in decreasing order of priority): - Understand the topics more at the conceptual level than "standard problem solving/plug n chug" level. Think final goal being to prepare for research in the field or like a...

I agree with you but then I was going more "complicated" cause I was still trying to preserve the conditions of electrostatics. You're right in restating the law but then the OP already mentions the E field being zero in electrostatic conditions. And in electrostatics the electric force on an...

If one can't ever know all the three components of (QM) angular momentum, then can it even be considered as a "vector"? Is it only cause it transforms as a vector in a coordinate transformation?

That's why I was careful to mention "in the classical realm". In reality, electric forces on an electron far outweigh any other kind of forces. Doing some rough order of magnitude calculations, gives you that the gravitational field will be at least 10^20 order of magnitude lesser than electric...

Electric field inside a conductor's cavity (in the classical realm atleast) will be zero, no matter what the shape of the cavity is. You will have an electric field only if you physically place a charge in the cavity (here inside the sphere). This directly follows from Gauss's Law.

I would bet few kinds of solid crystals should last a long time.

My solution is as follows: As charles too said, the flux through the superconducting ring must not change, i.e. it was initially zero so at any point of time it will be zero. $$ \phi_{external} = \mu_0 I \int_{0}^{R_2} r dr \int_{0}^{\pi} \frac{(R_1 - rcos(\theta))R_1 d\theta}{(r^2 + R_1^2 -...

What is your angle theta in the expression?

Check the attached image. Using c.o.p is fine but it isn't by first principles. Also if the center of pressure isn't already given then you need to integrate to find it.

That doesn't look right to me. F= ρg∫0r 2h * √(r2-h2) dh a simple substitution of variables solves this integral. Another way that this problem can be solved is to find the center of pressure and then multiply the area with the pressure at (c.o.p). Hope it helped.

Pressure is a function of depth, so is Force. To find the net force you need to write the expression for force for an elemental depth and then integrate from 0 to radius r.

When using the equations of motion listed you need to put the time interval that the particle has been under that constant acceleration. When Box B is released: Box A has already been traveling for "tr" time. Box B has traveled for "Zero" time. After 1...