Recent content by eri139

Thank you so much! that did it!

I thought you had it for a moment! That would make a lot of sense. But unfortunately I just tried it and it's still incorrect :(

I honestly have no idea why I'm getting this question wrong, because it seems fairly straightforward. I thought that treating the two blocks as one object would work, so 5 + 3 = 8. With Fg = Fs, ma = kx. Then, 8 x 9.8/1300 = x. x would be 0.06. That's been marked as an incorrect answer, though...

I found the amplitude of the simple harmonic motion that results (0.367, and I know this is correct because I entered it and it was marked as a correct answer), and assumed it would be the same value for the maximum compression since x(t) = Acos(wt). And, since the maximum value of cosine is 1...

I actually have 0 clue how to approach this. I'm thinking this might have to do something with the Stern-Gerlach experiment, but I don't know how that would help me test a spin-0 particle. If anyone could please help me with this, that would be great!

The ride started with the roller coaster going up on a steady incline. Then, at a higher height, it just stayed parallel to the ground as it moved on a flat track in a semicircular shape. Then, it went down. We just held the phone close to our laps so they wouldn't fall off the ride. So we...

Ooh, okay. So the gravitational force wouldn't change with such a small difference in height? But I can't think of any other accelerations that would be acting on the roller coaster besides the mechanisms that are making it move forward. Unless that acceleration was divided up into the z and y...

So, while we were going up the track, the z-direction gforce seemed to go up. It went from -1 to about -0.6. The x-direction seemed to be around 0, more or less? All x values were under 0.177. The y-direction decreased, more or less, from -0.4 to -0.9. I think if I understand how the force...

Google. I typed in "ice density" and the first value that popped up was that one. Unfortunately, I've just figured it out that this density is wrong and is the reason why my answers have been thrown off. Now I've finally gotten it...glad to see it wasn't an issue with my understanding, though!

Homework Statement A cube of ice whose edge is 17.0 mm is floating in a glass of ice-cold water with one of its faces parallel to the water surface. Ice-cold ethyl alcohol is gently poured onto the water surface to form a layer 5.00 mm thick above the water. When the ice cube attains...

Alright, I got it! Thank you for the help and putting up with me haha

Would it be KE = 1/2mv^2? Edit: okay, so now I've tried doing it like that. Would this be "correct"? : P 1&2 = P3 P3 = 1/2m3v^2 P1 &2 = 1/2m3V^2 1/2mV^2 = 1/2m3v^2 mV^2 = m3v^2 mV^2 = 3mv^2 v = V/√3 Enough to make some physics teachers turn red with rage? :biggrin:

Uh...forgive me if I sound really dumb, but I have no clue. I have NO idea where the root 3 could come from. I'm considering just saying it's an extra answer put in there just to trick the test-taker, since I can find no alternative.

Okay...I didn't include it because I didn't think it was necessary since the diagram itself isn't the issue. But I'll put it in the description above.

Homework Statement https://imgur.com/LYaudl1 Here is the question! Basically, we have to come up with a (reasonable) solution to all of the answer choices. It IS multiple choice, so only 1 answer is right (it is D), but we still have to find a way someone might have slipped up and made a...