Recent content by frogjg2003

True, but that's the undergrad method. I want to be able to transform wavefunctions that aren't the same in both spaces, and this would is a very good test case.

Homework Statement I'm trying to prove that the Harmonic oscillator wave function doesn't change (except a phase factor) when I convert from position to momentum space. \Phi_{nlm}(\vec p)=(-i)^{2n+l}\Psi_{nlm}(\vec p) Homework Equations \Phi_{nlm}(\vec p)=\frac{1}{(2\pi)^{3/2}}\int d^3r...

You have to solve Shroedinger's equation in all three regions. Then you need to apply the appropriate boundary conditions.

At t=0, A=0 and therefore dissolution and evaporation don't have an effect. Over time, the rate of change in surface area decreases as the area increases due to the second and third terms in dM/dt. You need to set up a differential equation and use the initial conditions to find the solution.

Charges create electric fields, moving or not. Charges are the sources of electric fields. Currents are the sources of magnetic fields. My question could be better stated as: What is the force of a Magnetic field on a charge? What is the force of an Electric field on a current?

You're doing everything right.

You have one wire with a constant charge density λ, and another with a constant current 3A. They are 3m apart. What is the force between them. What kind of field does a charge density create? What kind of field does a current create? What are the forces between one wire's field and another...

A couple implies there's something to couple with. How would equal and opposite forces create a coupling?

This is an elastic collision, so kinetic energy is conserved as well. There are two equations to solve, momentum and kinetic energy.

The tension of the rope is in a direction along the line of the rope, so yes, you're right.

There you go. You've got it.

The initial kinetic energy is not zero. The ball has some initial speed, namely 28 m/s. It's usually more convenient to have the starting, not final position have position and potential energy 0. This means that the final position is at y=37m and a potential energy of mgy. You know the initial...

Please show us the problem. We cannot figure out what to do unless we have some context. Also, mass times gravity is a force, in Newtons, not work or energy, in Joules.

You have to use potential and kinetic energy conservation to solve this problem.

The phase of a periodic function is the displacement the function has from some predefined 0 point. For example, sin(x) is 90° out of phase from cos(x). The question is just asking for \phi in x(t) = A\cos(\omega t+\phi).