Recent content by K Murty

I think I would have to read up significantly more on the posts made here, thank you.

For power systems prof DP Kotharis lectures are the best that I have found online: His published books are also excellent.

Hello IceSalmon, My apologies for not making the post clearer and more polite. As you know, it is not really practical for you to start learning such higher theories at first. I am an electrical engineering student and I would like for you to watch a brilliant video which explains what you...

First understand circuits. Then at the end will be transformers and basics of electromagnetism, make sure to understand these really well. Then move onto higher concepts. One book which bridges circuits and EM seemingly well is Fawaz Utaby fundamentals of applied electromagnetism.

I believe you would use some of the devices and methods mentioned in your post. I am having a hard time finding the correct material on how to minimise noise from small signal sources. I think the integrating A D converted is key here... I would think cooling!

I will reply in some time. :thumbup:

I am not measuring anything, but I am wondering how one would measure AC waveforms that are very small in magnitude, even smaller than the micro prefix. I know transformers are used to step down high voltages so they can be measured by voltmeters and for safety. So I was wondering if the...

Hello. How would this be done? Using a step up transformer?

Next time please post the curve and more information, it is not right to leave everyone guessing as to your intentions and with zero data provided. The units you mentioned, Siemens per meter, is this something related to transmission lines?

I recommend C as it is a low level language. I learned JAVA and OOP first, then C, but I think learning C is a good way to start. Enjoy!

Hi. Impedence is the complex number that captures the magnitude and phase of the quotient of the complex numbers of a sinusoidal voltage over a sinusoidal current. The units of impedence are Ohms. $$ v(t) = A \cos( \omega t) \,\, V \rightarrow A \angle{0} \,\, V \\ i(t) = B \cos(\omega t +...

Yes. Here is the solution that was realized through your insight: $$ V_{0} = \frac{{V} }{ s} \\ \\ i\dfrac{R}{L} + \dfrac{di}{dt} = \dfrac{ V_{0} t}{L} \\ \dfrac{R}{L} + r = 0 \\ r = - \dfrac{R}{L} $$ $$ i_{h}(t) = C_{0} e^{(- \dfrac{R}{L} t )} \\ \text{Particular solution:}$$ $$...

i will assume $$ t \,\, (V) $$ and solve it again for the source term as $$ \dfrac{t}{L} \,\, \frac{V}{H} $$

I made a mistake in my solution. The initial DE ACTUALLY given was: $$ iR + L\dfrac{di}{dt} = t $$ Multiplying the DE by $$ \dfrac{1}{L}$$ Gives: $$ i \dfrac{R}{L} + \dfrac{di}{dt} = \dfrac{t}{L} $$ I hurried the solution and forgot to multiply the source term by $$ \dfrac{1}{L} $$ But even...

Hello. This is the differential equation. $$ i \cdot \dfrac{R}{L} + \dfrac{di}{dt} = t $$ My solution path: Homogenous solution: $$ r + \dfrac{R}{L} = 0 \\ \\ r = -\dfrac{R}{L} \\ \\ i_{h}(t) = C_{0} e^{ -\dfrac{R}{L} t} \\ \\ $$ Particular solution: Try $$ y_{p} = at + b \\ \\ y_{p}...