Recent content by magnetpedro
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Help Me Find Thevenin's Equivallent for the Circuit Impaired
Nevermind, you're probably right. Thank you very much for your time!- magnetpedro
- Post #18
- Forum: Electrical Engineering
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Help Me Find Thevenin's Equivallent for the Circuit Impaired
Sorry to bother but let me clarify something. In the picture I've posted (#12), isn't VA suppose to be zero since it's a point before the source? And in point B, if I follow the current's path from A to B, we first have a voltage rise of 10 V (the source) and then a voltage drop of 10 V (in the...- magnetpedro
- Post #16
- Forum: Electrical Engineering
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Help Me Find Thevenin's Equivallent for the Circuit Impaired
What do you mean? Thanks!- magnetpedro
- Post #14
- Forum: Electrical Engineering
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Help Me Find Thevenin's Equivallent for the Circuit Impaired
I believe see it now, thanks a lot! Like this? The VBA equals the VTh and VB = 10 V and VA = 0 V, right? Now, I'll try to add the upper right loop.- magnetpedro
- Post #12
- Forum: Electrical Engineering
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Help Me Find Thevenin's Equivallent for the Circuit Impaired
Hum, let's see. In that isolated upper left loop, Vth is equal to VAB = VB - VA , right? ( B being the node above E4) I thought VAB would be the V of the 2 ohm resistor, but I'm clearly confused. I believe it's a matter of not being able to visualize it correctly. Sorry for the trouble, do you...- magnetpedro
- Post #6
- Forum: Electrical Engineering
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Help Me Find Thevenin's Equivallent for the Circuit Impaired
Adding the other right loop: Rth = 7,4 ohm Vth = [ 10 * ( 2 / ( 2+ 4 + 1) ) ] + [ 2 * ( 2 / ( 2,5 + 0,5 + 3 + 2 ) ] V ? Thanks once again for your awesome support.- magnetpedro
- Post #4
- Forum: Electrical Engineering
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Help Me Find Thevenin's Equivallent for the Circuit Impaired
Thanks a lot for your guidance. For the upper left loop wouldn't it be: Rth = 7 ohm Vth = 10* (2/(2+4+1) ) V ? (Unfortunately the "B" node got cutted from the print. It's the "R" (a B without the lower leg) under E1)- magnetpedro
- Post #3
- Forum: Electrical Engineering
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Help Me Find Thevenin's Equivallent for the Circuit Impaired
Hello guys, Can someone guide me through this problems solution? I need to find the Thevenin's Equivallent for this circuit, between A and B. I'm terrible at Circuits and I'm eager for some motivation and help. Thanks a lot in advance.- magnetpedro
- Thread
- Circuit Resistance Tension Thevenin
- Replies: 22
- Forum: Electrical Engineering
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Graduate Area of trapezoid formed by slicing a cylinder
Yes, it does!- magnetpedro
- Post #32
- Forum: General Math
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Graduate Magnetic Flux Through a Tilted Medium
Yes, inductance is a scalar quantity but I can make a projection of the ferromagnetic fiber along x and y, with a length and cross area also projected, calculate both Inductances Lx and Ly, and then the "final" inductance would be L = sqrt(Lx^2 + Ly^2).- magnetpedro
- Post #9
- Forum: Electromagnetism
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Graduate Area of trapezoid formed by slicing a cylinder
Thank you!- magnetpedro
- Post #30
- Forum: General Math
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Graduate Area of trapezoid formed by slicing a cylinder
This is awesome. Have you done it in Matlab? Would you be so kind to lend me the code you've used?- magnetpedro
- Post #28
- Forum: General Math
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Graduate Magnetic Flux Through a Tilted Medium
Yes I have. I'll try to explain this model. Imagine that a magnetomotive force is produced by a number of turns N and a current I, being Fmm=N*I. That magnetomotive force creates a magnetic flux ∅ that only crosses the ferromagnetic cylinder. The inductance of the ferromagnetic medium/fiber can...- magnetpedro
- Post #7
- Forum: Electromagnetism
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Graduate Magnetic Flux Through a Tilted Medium
My mistake, forgot to mention that the magnetomotive force is produced by a current I (constant). That's my current.- magnetpedro
- Post #5
- Forum: Electromagnetism
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Graduate Area of trapezoid formed by slicing a cylinder
Perhaps you were right, but in any case, how can I relate this area that is crossed by the flux with the angle a? Thanks a lot for your help once again.- magnetpedro
- Post #25
- Forum: General Math