Magnetic Flux Through a Tilted Medium

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The discussion centers on proving that the sum of inductances measured along the x-axis and y-axis of a tilted ferromagnetic cylinder is independent of the tilt angle. The approach involves using Hopkinson's Law to calculate reluctance and subsequently inductance, with the formulas provided for inductance in relation to magnetomotive force and reluctance. Participants clarify that inductance is a scalar quantity and cannot be directly broken into x and y components, although projections can be made. There is skepticism about the necessity of such projections since inductance is inherently independent of the angle by definition. The conversation highlights the complexities of understanding inductance in the context of a tilted ferromagnetic medium.
magnetpedro
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Imagine a ferromagnetic medium shaped as a cylinder (a ferromagnetic fiber) with a magnetic relative permeability of μr, tilted with an angle a, as shown in the picture.

220px-Cylinder_geometry.svg.png

I would like to prove analytically that the sum of the inductances measured along the x-axis (angle is a) and y-axis (angle is π/2 - a) is independent of the angle a. (Lsum = Lx + Ly independent of a).

Each case, Lx and Ly is also the sum of the inductance of the projections of the fiber in the x and y axis.
My approach consists in using Hopkinson's Law and first determining the Reluctance for each case, and then calculating the Inductance using L= N2/Reluctance, where N is a constant number of turns of a supposed magnetomotive force.

Do you think it's possible?

Thank you very much.
 
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Don't understand your post. What is the inductance of a cylinder?
 
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marcusl said:
Don't understand your post. What is the inductance of a cylinder?

It's the Inductance of a ferromagnetic medium shaped as a cylinder, that is crossed by a flux produced by a magnetomotive force.
At least was this that I meant to say. Beg your pardon if I wasn't clear.
 
Inductance is a quantity that relates energy stored in a magnetic field to the currents producung the field. It also relates an induced emf to a changing current. You have no currents, hence no inductance.
 
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marcusl said:
Inductance is a quantity that relates energy stored in a magnetic field to the currents producung the field. It also relates an induced emf to a changing current. You have no currents, hence no inductance.

My mistake, forgot to mention that the magnetomotive force is produced by a current I (constant). That's my current.
 
Your problem doesn't make sense as stated and suggests that you don't understand inductance. Have you had an undergrad E&M course?
 
marcusl said:
Your problem doesn't make sense as stated and suggests that you don't understand inductance. Have you had an undergrad E&M course?

Yes I have. I'll try to explain this model.
Imagine that a magnetomotive force is produced by a number of turns N and a current I, being Fmm=N*I.
That magnetomotive force creates a magnetic flux ∅ that only crosses the ferromagnetic cylinder.
The inductance of the ferromagnetic medium/fiber can be determined using the following expressions:

L = N× ∅ / I

∅ = Fmm/R

L = N2/R

where R is the reluctance of the ferromagnetic medium, given by:

R= l/(μ0r*A)

where l is the length of the path of the magnetic flux, μ0 is the magnetic constant (vacuum's permeability), μr is the relative magnetic permeabilty of the ferromagnetic cylinder and A is the area that is crossed by the flux.
 
These formulas are usually written in terms of the number of turns per unit length n, in which case L=\frac{n^2l}{R}. Furthermore, this applies to long solenoids. Since your core is short, this will be an approximation at best.

To your original question, however, inductance is a scalar quantity so you can't break it into x and y components.
 
marcusl said:
These formulas are usually written in terms of the number of turns per unit length n, in which case L=\frac{n^2l}{R}. Furthermore, this applies to long solenoids. Since your core is short, this will be an approximation at best.

To your original question, however, inductance is a scalar quantity so you can't break it into x and y components.

Yes, inductance is a scalar quantity but I can make a projection of the ferromagnetic fiber along x and y, with a length and cross area also projected, calculate both Inductances Lx and Ly, and then the "final" inductance would be L = sqrt(Lx^2 + Ly^2).
 
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Well yes, you could do that, but I don't see the value since L is already independent of your angle, by definition.
 
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