Recent content by Mango12

I'm not sure, what to do with this, but I just need Part C: The diameter of the A string is 0.229mm. What is the diameter of the D string if the tension of both string must be equal? I feel like tension cancels out somewhere?

Show that F = -constant * delta y This is what I have so far that we did in class. He said we needed to make a substitution somewhere but I don’t understand where 2F=[Kq^2/r^2]2 Fy = [2Kq^2/r^2] sin theta Sin theta = delta y/r Sin theta = delta y/(d/2)

Hey there! Thanks for replying, but I solved this problem on my own before I saw your post.

Hi! Thanks for replying, but I figured it out on my own before I saw your reply.

How much more heat is given off by heating 237mL of water with 216,000J than is used to start the car? I don't have the value of the energy to start the engine, but does anyone know how I could go about solving this if I did?

okay..I will. But a side note..he said in order to solve this I need to know 2 key properties of water...do you have an idea of what he means?

Yes..I have given all relevant information that I know. I know the charge in coulombs and the distance between the plates. Epsilon nought is a given number. And I need to solve for area.

my apologies. And I believe it was a car in a previous problem..but I don't have my paper with me to give the exact problem and it's very confusing.

Now let's find the area of the metal plates. We already know from a previous problem that there is a 3,000 coulomb charge on the plates. The plates are placed .5mm apart. (approximate answer is 250 miles, but give your answer in meters)

a) how much more heat is used to boil 237 mL of water as opposed to starting the car? b) what major concept/finding was overlooked while solving this problem? I think this has something to do with delta H = mc(delta t) but idk

Starting a car: the voltage drops from 12V to 7.2 V, it is 0 degrees out, and 150 amps are pulled from the car. What is the temperature coefficient of the resistor? I have NO idea how to do this. Help please!

I know C=Epsilon0(A)/delta x From the problem, C=3,000 Epsilon0 = 8.85 × 10^-12 and delta x is .5mm The answer is supposed to be given in meters and should be close to 40,000 but I got 1.6*10^11m...help please!

question: referencing ohm's law, why is the voltage in an ideal battery equal to that in an open circuit? I know ohm's law, and I know that an ideal battery has the same voltage no matter what it's connected to, but what does that have to do with an open circuit?

I kind of get it. I think I figured it out a different way though, because we never use integrals in class so he wouldn't want me to solve it that way outside of class :/

This makes a lot of sense. Thank you! I understand it a lot better now.