Recent content by maniacp08

Lenses/Images -- Find final image Two converging lenses, each having a focal length equal to 8 cm, are separated by 35 cm. An object is 30 cm to the left of the first lens. (a) Find the position of the final image using both a ray diagram and the thin-lens equation (c) What is the overall...

Heat/First Law of Thermodynamics/Calorimetry -- Have work done A calorimeter of negligible mass contains 920 g of water at 303 K and 48 g of ice at 273 K. Find the final temperature T. °C Solve the same problem if the mass of ice is 460 g. °C Formula I've used Mice * Lf + Mice * Cwater...

The period of an oscillating particle is 56 s, and its amplitude is 18 cm. At t = 0, it is at its equilibrium position. Find the distances traveled during these intervals. (a) t = 0 to t = 14 s cm (b) t = 14 s to t = 28 s cm (c) t = 0 to t = 7 s cm (d) t = 7 s to t = 14 s cm x =...

Water flows at 0.67 m/s through a 3.0 cm diameter hose that terminates in a 0.35 cm diameter nozzle. Assume laminar non-viscous steady-state flow. (a) At what speed does the water pass through the nozzle? 49.22 m/s (b) If the pump at one end of the hose and the nozzle at the other end are...

where/how would the density of mercury come in? Im not too sure about this. They want the height in cm. 10mmHg = 1.03 kg/m^3 * 9.81N/kg * h

Oh so the density is 1.03, then g would be 9.81m/s then. P = P0 + density * g * h 10mmHg = 1.03 * 9.81m/s * h and solve for h?

Fluids -- pressure Blood plasma flows from a bag through a tube into a patient's vein, where the blood pressure is 10 mmHg. The specific gravity of blood plasma at 37°C is 1.03. What is the minimum elevation the bag must have so the plasma flows into the vein? Prof gave this problem for us...

h = V^2R^2/(2*u - V^2*R) h = 13.69 * 40960000 / (800000 - 87616) h = 560742400 / 712384 h = 787.1350283 km h = .7871350283 m Do I add this to the Radius of the earth?

well the textbook has the same problem explained but different velocity and it uses that equations and same steps I posted. But I don't know what I did wrong mathematically to give me a negative height. I was wondering if someone can work it out and see if they get the same answer or diff.

This is the final equation: 1/radius_f = -Vi^2/2*G*M_e + 1/R_e then I solve for radius_f then I divide it by 1 then I subtract it from the Earth's radius to get the height but it gives me a negative height.

Gravity -- maximum height An object is projected upward from the surface of the Earth with an initial speed of 3.7 km/s. Find the maximum height it reaches. m Ive used the Energy conservation Kf + Uf = Ki + Ui 1/2 mvf^2 - G*M_e*m/rf = 1/2 mvi^2 - G*M_e*m/ri = 0 - G*M_e*m/rf = 1/2 mvi^2 -...

I found the speed from part b 2.15 km/s circumference of the orbit is 2Pi*(86.37 x 10^6) so time = 2Pi*(86.37 x 10^6) / 2.15 km/s

Yes, it makes sense, thanks for explaining. And I got what r is now that you related it as a circle. For part C: What you said earlier time = distance/speed where distance is the orbits circumference/distance covered It would be 2Pi*(86.37 x 10^6) / 2.15km I get a big answer of 252528.6976s...

Ok, I got the mass of the Earth 5.98 × 10^24 kilograms from the textbook. So the raidus of the Earth is 6.37 x 10^6m which my textbook says. So I add 8.00 x 10^7 m to it? So is 86,370,000 which is 86.37 x 10^6 gravitational Force = G*m1*m2 / r^2 G = 6.67 x 10^-11 Nm^2/kg^2 F = (6.67 x...

Gravity Problem -- satellite A satellite with a mass of 250 kg moves in a circular orbit 8.00 x 10^7 m above the Earth's surface. (a) What is the gravitational force on the satellite? N (b) What is the speed of the satellite? km/s (c) What is the period of the satellite? h Relevant Equations...