Lenses/Images -- Find final image Two converging lenses, each having a focal length equal to 8 cm, are separated by 35 cm. An object is 30 cm to the left of the first lens. (a) Find the position of the final image using both a ray diagram and the thin-lens equation (c) What is the overall lateral magnification? What I did: s1' = f1s1/(s1-f1) s1' = (8cm)(35cm)/(35cm-8cm) = 10.37cm m1 = - s1'/s = -10.37cm/35cm = -.296285cm s2' = f2s2/(s2-f2) s2 = 35cm-30cm = 5cm s2' = (8cm)(5cm)/(5cm-8cm) = -13.333cm m2 = - s2'/s = - (-13.333cm)/5cm = 2.666cm For question a isn't it 35cm+s1'+s2'=32.04cm or 32cm? This answer was marked wrong can anyone tell me what I did wrong? For question c - m = m1*m2 = -.296285cm*2.666cm = -.78989581cm but this is again wrong Please help, thanks!