(adsbygoogle = window.adsbygoogle || []).push({}); Heat/First Law of Thermodynamics/Calorimetry -- Have work done

A calorimeter of negligible mass contains 920 g of water at 303 K and 48 g of ice at 273 K. Find the final temperature T.

°C

Solve the same problem if the mass of ice is 460 g.

°C

Formula Ive used

Mice * Lf + Mice * Cwater * change in T icewater = Mwater * Cwater * change in T water

(.048kg)(79.7kcal/kg)+(.048kg)(1kcal/kgxK)(Tf - 273K) =

(.92kg)(1kcal/kgxK)(303K-Tf)

Ive gotten Tf to be 297.56K which is 24.41 C

and for part B Ive gotten the answer to be 266.433K which is -6.7167 C

Is this correct?

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# Homework Help: Heat/First Law of Thermodynamics/Calorimetry - Have work done

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