Water flows at 0.67 m/s through a 3.0 cm diameter hose that terminates in a 0.35 cm diameter nozzle. Assume laminar non-viscous steady-state flow.(adsbygoogle = window.adsbygoogle || []).push({});

(a) At what speed does the water pass through the nozzle?

49.22 m/s

(b) If the pump at one end of the hose and the nozzle at the other end are at the same height, and if the pressure at the nozzle is 1 atm, what is the pressure at the pump?

atm

I have found the answer for part A.

I have set up an equation for part B:

I have to find P1

P2 = 1 atm

v1 = .67 m/s

v2 = 49.22 m/s

let D = density of water = 1000kg/m^3

P1 + 1/2 D * V1^2 = P2 + 1/2 D * V2^2

P1 = P2 + 1/2 D * V2^2 - 1/2 D * V1^2

P1 = 1atm + 1/2(1000kg/m^3) * (2422.6084 m/s) - 1/2(1000kg/m^3) * (.4489m/s)

How do I convert this or get answer for P1 in terms of atm?

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Bernoulli's Equation on water hose

**Physics Forums | Science Articles, Homework Help, Discussion**