Recent content by MarieWynn

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    Calculating Reflected Light Displacement in Glass

    Homework Statement A beam of light makes an angle of 26 o with the normal of a mirror made of 2.4- mm-thick glass silvered on the back. If the index of refraction of the glass is 1.50, how far is the point at which the beam leaves the glass surface (after being reflected from the silver...
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    Magnitude of the magnetic field of a bar magnet that has a magnetic moment

    Homework Statement A slender, 200- g bar magnet 15.0 cm long has a magnetic moment of 5.50 A m2. It is held at an angle of 45 o to the direction of a uniform magnetic field. When released, it begins to rotate about its center with an initial angular acceleration of 8.40×103 rad/s2. What is the...
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    Calculating i5 Using Kirchoff's Junction Rule

    Thanks so much guys! 20 was correct and I understand why. :)
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    Calculating i5 Using Kirchoff's Junction Rule

    So for my particular example: Entering the node: i1, i4, and i3? i3 and i5 confuse me. When I add up the total, I get -i1+i2-i3-i4=-20. So i5 would have to be 20 for the total to equal zero. I feel like I am still missing something here.
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    Calculating i5 Using Kirchoff's Junction Rule

    Homework Statement Calculate the current i5 in the configuration. Use the following data: i1=8.65 A, i2=5 A, i3=7.85 A, and i4=8.5 A. Homework Equations Kirchoff's junction rule states that the sum of the currents meeting at a junction has to equal zero. The Attempt at a Solution...
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    Finding the energy field due to three positive point charges on a 4th negative charge

    Thank you so much! This was correct and you really helped me to understand what I did wrong. When I get this problem right on the test I will thank you again! :)
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    Finding the energy field due to three positive point charges on a 4th negative charge

    So r2=2d2=2*0.0482=0.004608 e=KQ/r2=(8.99x109)*(7x10-6)/0.004608=1.4x107 Then adding that to Eb would give us: E= 5.2x107 N/C Is that right? Which would bring us to part B, which would be: F=Eq=(5.2x107)(21x10-6)= 1092 N
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    Finding the energy field due to three positive point charges on a 4th negative charge

    Heh, I see the x2 button now. :) Thanks! 0.3098 is r, where r=sqrt(2d). I had originally kept the charge the same for that part where e=(8.99x109)(7x10-6)/r2 but the answer was still wrong. It gave me 6.6x105 and when adding that to Eb, I got 3.9x107 N/C, which is still incorrect.
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    Finding the energy field due to three positive point charges on a 4th negative charge

    Homework Statement Three equal positive point charge of magnitude Q=7.00uC are located at three corners of a square of edge length d=4.8cm. A negative charge of -21.00uC is placed on the fourth corner. A) At the position of the negative charge, what is the magnitude of the electric field due...
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    Vectors problem (part 2 with work)

    Got past part 2 but not understanding why part 3 isn't correct. To find the magnitude of A+B you first have to find the X and Y components of B. Ax is 5.34. Ay is 5.82. Bx is -8.83 and By is -5.82. So when you use the pythagorean theorem to find C, you get the square root of [(5.34 + -8.83)2 +...
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    Vectors problem (part 2 with work)

    Homework Statement The diagram below shows two vectors, A and B, and their angles relative to the coordinate axes as indicated. DATA: α= 47.5o β= 56.6o |A| = 7.9 cm. The vector A - B is parallel to the -x axis (points due West). A) Calculate the y-component of vector B. Answer: -5.82 cm...
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    Velocity problem set up (I think it is velocity)

    Homework Statement A boat capable of making 12.0 km/h in still water is used to cross a river flowing at speed of 2.0 km/h. The boat is directed (from the perpendicular to the shore) in such a way that its resulting motion is straight across the river. At what angle (in degrees) must the...
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    Calculating Y-Component of Vector B: Solve Vectors Question

    Homework Statement The diagram below shows two vectors, A and B, and their angles relative to the coordinate axes as indicated. DATA: α= 47.5o β= 56.6o |A| = 7.9 cm. The vector A - B is parallel to the -x axis (points due West). Calculate the y-component of vector B. Homework Equations...
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