Recent content by nomorenomore

Oh yes. 2*1.5*thickness=1/2λ=294.5, thickness=294.5/3=589/6nm?

1/2λ=1/2*589=294.5nm?

tanθ=thickness/horizontal distance, thickness=horizontal distance*tanθ?

But the path difference between they reflect changes continuously in part a)? How should I deal with this?

The equations are "For constructive interference, path difference = mλ, m = 0, ±1, ±2... For destructive interference, path difference = (m + 1/2)λ, m = 0, ±1, ±2..." ? And both the red ray and the blue ray has undergone phase change? Since SiO2's n=1.5> air's n =1, the blue ray has phase...

Homework Statement A beam of light comprises two wavelengths is passed through a transmission diffraction grating. When viewed at an angle of 21.1° to the incident direction, the second order maximum for one wavelength is overlapped with the third order maximum for the other wavelength. The...

Homework Statement 1. Referring to the picture, switch S1 is closed at t=0. a) What is the current in the circuit loop at t=0 and t=∞? b) What is the voltage on C at t=0 and t=∞? (4M) (Picture's Link: http://s29.postimg.org/bfsbw2hc5/physexam1q7.png) Homework Equations When charging, 1.) ε -...

Homework Statement In order to decide the thickness of a SiO2 layer(n=1.5) on Si, a wedge is prepared as shown in the picture. A total of 7 DARK fringes was observed, when light of wavelength 589nm shines prependicularly on the wedge. It is known that light reflected from the Si/SiO2 surface...

b) a = r*γ, a=g (ωf)^2 = (ωi)^2 + 2*γ*θ Oh, I'm sorry for this. I was trying to show that linear acceleration = radius * angular acceleration, where linear acceleration = gravitational acceleration, in this case (final angular velocity)^2 = (initial angular velocity)^2 + 2*angular...

In (a), because I thought N is always equal to mg... But just now I've thought it twice.. it's not true, a simple example is the Lift Case.. So N > 0 ; mg > m(ac) ; g > v^2/r ; v > sqrt(g*r) ? In (b), for both sides having the dimension of energy, I should use 1/2*k*x^2 instead of -kd...

In (a), i thought N + mg = m(ac) where N=mg therefore mg + mg = 2mg = m(ac) So... maybe I'm wrong? In (b), -kd=1/2m(vc)^2 + mgR + (μk)*mg*L d= (1/2m(vc)^2 + mgR + (μk)*mg*L )/-k Is this correct, please?

Homework Statement (a) Calculate the moment of inertia I of the disc when it rotates about the pivot as shown in the figure. (b) If the disc is released from rest, determine the angular speed, ω, of the disc at its lowest point. Homework Equations a) Id = Icm + md^2 Icm = 1/2*M*R^2...

Homework Statement A massless spring of constant k is fixed on the left side of a level track. A block of mass m is pressed against the spring and compresses it a distance d, as shown in the figure. The block (initially at rest) is then released and travels toward a circular...

And for the topic, I'm sorry it's not clear enough as I didn't quite have time to think for a better one. And you're right, I need something more...

Dear Bvu, Sorry for my bad work and thank you for your reminder. That was because my exam was near and I was afraid that the question posted would appear in the exam. That's why I asked in such a lazy way. I'm sorry for this and I admit that I did't start studying for the exam early enough...