Recent content by Pochen Liu

Question (These are incorrect values) Attempt I used and then found the respective change in temperature. However for the last question I have no idea, do I sum up the net change in temperature and use But then what is the work and how do we figure it out?

I got 0.00054996 Ohms (Which I hope is correct??). Thank you so much!

Is N = 1? Because we have only a single ring? And I chose A to be the cross section of the area because that's what the equation for B is. The magnetic flux density through the solenoid as it's within the ring, but we treat the ring like a solenoid, so N = 1.

Judging by this, A = pi * 0.0207^2 (Solenoids radius right?) And n (Not N) = 8230/m

To confirm, is this what you meant? I have played with the equations a little. Also, n is the density of coils/m However I am not provided with the length of the solenoid?

Sorry I don't follow, I can find the rate of change of these with regards to time, however I don't see anything I can do it with

Question: In Figure (a), a circular loop of wire is concentric with a solenoid and lies in a plane perpendicular to the solenoid's central axis.The loop has radius 6.13 cm. The solenoid has radius 2.07 cm, consists of 8230 turns/m, and has a current i_sol varying with time t as given in Figure...

In the figure ε = 9.89 V, R1 = 1150 Ω, R2 = 2890 Ω, and R3 = 4940 Ω. What are the potential differences (in V) (a) VA - VB, (b) VB - VC, (c) VC - VD, and (d) VA - VC?What I've tried I have derived the equation ε - i1R1 - i2R2 = 0 where i1 is the current running through R1 and vice...

What is the difference between time dilation (t is the stationary reference frame) t = Description: If two successive events occur at the same place in an inertial reference frame, the time interval 􏰋t0 between them, measured on a single clock And this equation for time, if we take t' as the...

It was accelerated over the course of 3.5km to reach 7000 m/s. Which is unrelated? we assume it leaves from the surface of the Earth not 3.5km out

E is conserved as the engine is not on as it leaves at 7000m/s till it reaches 970km. Once it hits 970km the engine will turn on and E is not conserved, however that is not our concern. We only need to determine how much extra speed it needs once its 970km? If I'm wrong, how else can we go...

So using conservation of energy where v0 = 7000 m/s $$ K_{i} + U_{i} = K_{f} + U_{f} $$ $$\frac{1}{2}mv^{2}_{0} - \frac{GMm}{R} = \frac{1}{2}mv^{2} - \frac{GMm}{r}$$ where R = the radius of the Earth and r = the distance from Earth's center plus the height its orbiting $$v =...

I have the equation $$\frac{d^2y}{dt^2} + 5y = 0$$ where I've worked out $$y = Acos(\sqrt5t) + Bsin(\sqrt 5 t)$$ $$y'' = -5Bsin(\sqrt 5 t) $$ using $$y = e^{\lambda x}$$ and using y(0) = 0 (the spring is released from equilibrium) so an external force $$Acos(\omega(t - \phi))$$ is applied so...

I see, so how would you put this formally? I understand that it's the force of gravity from its mass, but why does this work?

What are the steps to calculating the center of mass for this object? I don't want a numerical answer just the theory. I understand I need to calculate COM for all axis, we know in the Y axis it's dead centre because of symmetry but I don't know how to do it for the others. A hint would be...