Circular loop of wire is concentric with a solenoid

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Homework Help Overview

The discussion revolves around a circular loop of wire that is concentric with a solenoid, with the loop positioned perpendicular to the solenoid's axis. The problem involves determining the loop's resistance based on varying current in the solenoid and the energy transferred to thermal energy in the loop.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore how to find the magnetic flux density (B) and the electromotive force (EMF) in relation to the varying current (I) in the solenoid. There are discussions on using figures provided to derive functions for current and energy over time. Questions arise about the definitions of variables and the assumptions made regarding the solenoid's length and the areas involved in calculations.

Discussion Status

Participants are actively engaging with the problem, questioning assumptions, and clarifying definitions. Some have provided guidance on how to approach the calculations, while others are verifying their understanding of the equations involved. There is no explicit consensus on the final solution, but productive dialogue is ongoing.

Contextual Notes

Participants note the lack of information regarding the solenoid's length and discuss the implications of treating the solenoid as having a theoretically infinite length. There is also a focus on the definitions of area and the number of turns in the context of the equations being used.

Pochen Liu
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Homework Statement
Find the loops resistance
Relevant Equations
N/A
Question:
In Figure (a), a circular loop of wire is concentric with a solenoid and lies in a plane perpendicular to the solenoid's central axis.The loop has radius 6.13 cm. The solenoid has radius 2.07 cm, consists of 8230 turns/m, and has a current i_sol varying with time t as given in Figure (b), where the vertical axis scale is set by i_s = 1.03 A and the horizontal axis scale is set by ts = 4.6 s. Figure (c) shows, as a function of time, the energy E that is transferred to thermal energy of the loop; the vertical axis scale is set by Es = 101.6 nJ. What is the loop's resistance?

I want to find B, the magnetic flux density such that I can work out what the EMF is.
From the EMF I can use
$$ P = \frac{EMF^2}{R} $$

To work out R as I know what P is since that is J/s.

However how can I find B when:
$$ B = \frac{\mu N I}{2R}$$

and I don't know what the current (I) is? As the current varies over time.If someone could provide what is going on in terms of the physics and the required next steps that would be great!
 

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Look carefully at figures (b) and c. From (b) you can determine completely the function I(t) (that is the current as a function of time t) and from (c) you can determine completely the function E(t).
 
Delta2 said:
Look carefully at figures (b) and c. From (b) you can determine completely the function I(t) (that is the current as a function of time t) and from (c) you can determine completely the function E(t).
Sorry I don't follow, I can find the rate of change of these with regards to time, however I don't see anything I can do it with
 
Pochen Liu said:
Sorry I don't follow, I can find the rate of change of these with regards to time, however I don't see anything I can do it with
How can you find the rate of change of I and E w.r.t to time t?

And of course you can do many things with it, from the rate of change of current(which will be the same (up to some multiplicative constants) to rate of change of magnetic field B of the solenoid) and Faraday's law of induction you can calculate the EMF through the circular wire loop. From the rate of change of energy you can calculate the Power, due to the EMF and current, that is dissipate as heat in the resistance R of the loop.
 
Delta2 said:
How can you find the rate of change of I and E w.r.t to time t?

And of course you can do many things with it, from the rate of change of current(which will be the same (up to some multiplicative constants) to rate of change of magnetic field B of the solenoid) and Faraday's law of induction you can calculate the EMF through the circular wire loop. From the rate of change of energy you can calculate the Power, due to the EMF and current, that is dissipate as heat in the resistance R of the loop.
To confirm, is this what you meant? I have played with the equations a little. Also, n is the density of coils/m
69839783_777321356017894_5413346727992229888_n.jpg


However I am not provided with the length of the solenoid?
 
Your equations appear to be correct, but it all depends what A and N (the capital N in the last equation for emf) are. So please tell me what is A and what is N

And you don't need to know the length of the solenoid to answer the question. It seems to be that the solenoid is supposed to have very large length, theoretically infinite.
 
Delta2 said:
Your equations appear to be correct, but it all depends what A and N (the capital N in the last equation for emf) are. So please tell me what is A and what is N

And you don't need to know the length of the solenoid to answer the question. It seems to be that the solenoid is supposed to have very large length, theoretically infinite.

1568115345421.png

Judging by this, A = pi * 0.0207^2 (Solenoids radius right?) And n (Not N) = 8230/m
 
Well you are correct for A (and for n). But tell me why you chose A to be the cross section area of the solenoid and not the cross section area of the wire loop

And also tell me what is N
 
Delta2 said:
Well you are correct for A (and for n). But tell me why you chose A to be the cross section area of the solenoid and not the cross section area of the wire loop

And also tell me what is N
Is N = 1? Because we have only a single ring? And I chose A to be the cross section of the area because that's what the equation for B is. The magnetic flux density through the solenoid as it's within the ring, but we treat the ring like a solenoid, so N = 1.
 
  • #10
Pochen Liu said:
Is N = 1? Because we have only a single ring? And I chose A to be the cross section of the area because that's what the equation for B is. The magnetic flux density through the solenoid as it's within the ring, but we treat the ring like a solenoid, so N = 1.
yes you are correct N=1. So I guess all you have to do is plug in the numbers to the equations. You also can find ##P=\frac{dE}{dt}## from figure (c), so you can solve for the resistance of the loop.
 
  • #11
Delta2 said:
yes you are correct N=1. So I guess all you have to do is plug in the numbers to the equations. You also can find ##P=\frac{dE}{dt}## from figure (c), so you can solve for the resistance of the loop.
I got 0.00054996 Ohms (Which I hope is correct??). Thank you so much!
 
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