Recent content by psy

IEI = sqrt( Ey^2 + Ex^2) = 25435.2 N/C ?

So the half of the electrons from the neutral one are transferring to the charged ball. A new Equilibrium takes place, where the charges are +q/2 on both balls. So again they are pushing each other away, yet with smaller distance as the charges are smaller. As the Coulombs law F = k * q1 * q2 /...

So one ball gets decharged, so its neutral after that. Yet the positive Charge of the other ball "reorganizes" the charges in the neutral one, it attracts the unlike charges to the nearer side of the ball and "pushes" away the like charges. As the unlike charges are closer, distance is smaller...

Hello So i have made the following correction: r= 0,0707m E1 = E2 = 17985,4 N/C E1y = E1 * cos(-45°)= 12717,6 N/C E2y = E2 * cos(45°)=12717,6 N/C E1x = E1 * sin(-45°) = -12717,6 N/C E2x = E2* sin(45°) = 12717,6 N/C Ey = E1y+E2y = 25435.2 N/C Ex = E1x+ E2x = -12717,6 N/C+12717,6 N/C =...

Two positive point charges with a charge of 10nC each are 10cm apart. What is the electric field strength at point A? How is it directed? Which force acts on a charge of 100nC at point A? F = k * q1 * q2 / r^2 E = F/q r^2 = (l1/2)^2 + (l2)^2 => r = 0,707m Electric field strength : E1 = E2 =...

Well in case there is no Electrostatic force there is no electrostatic "push", so the only force left should be the gravitational. Is this correct?

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Hello! I have the following problem and attempt for solution. Two equal, small conductive balls hang on two long non-conductive threads attached to a hook. The balls are charged with the same charges and are located 5 cm apart. One of the balls will now be decharged. What is the new distance...

Hey How can i calculate the work done by a homogeneous electric field on a positive charge q = 7 × 10^-8 C when the charge moves from point 1 to point 2 . I have two cases: a) the charge is parallel to the Electric field; b) the displacement of the charge takes place at the angle α = 60 ° to...

r1 = 0.1m + r2 q1 / (0.1m + r2 )^2 = - q2 / r^2 q1/ (r2^2 + 0.2 * r2 + 0.01 m^2) = - q2 / r^2 8nC / r2^2 + 8nC / 0.2*r2 + 8nC/ 0.01 m^2 = 6nC / r^2 , multiplicating everything with r^2 gives 8nC + 40 nC * r2 + 8nC * r2^2 / (0.01 m^2) - 6 nC = 0 , rearranged 8nC * r2^2 / (0.01 m^2) + 40...

Hey, First I want to find the electric field strength from the middle between two point charges q1 = 8nC and q2 = -6nC. The distance between the two charges is 10 cm. Then i want to find out at which point of a straight line, which runs through the two charges is the electric field strength...

In the exercise I am doing its supposed that the electron moves in a circular orbit around the proton with the given velocity, so I am tryng the classical mechanics with the centripetal and electrostatic force,where i can plug in the velocity of 10^16 s^-1 . As the k I used 1/ 4*π*ε = 8,99...

Hey guys, The following thing got me a little bit messed up. I want to calculate the orbital radii of an Hydrogen atom if the angular velocity of the electron is 10^16 * s^-1. At first i set the centripetal force and the electrostatic force as equals. ( m * v^2 )/ r =k * (e^2) /...