Recent content by Rumplestiltskin

  1. Rumplestiltskin

    Why can't logs have a negative base?

    Syntax error on calculator. When typed into google, (-10)1.7 = 29.4590465 - 40.5468989 i. Woah. Still at a loss. Could you elaborate?
  2. Rumplestiltskin

    Why can't logs have a negative base?

    I understand that taking logs of a negative number isn't possible because no number to any power produces a negative number. But why not a negative base? Say, log-10(100) = 2. Rewritten, -102 = 100, which is accurate. You could suggest that you may as well just ignore the negative because -x2 =...
  3. Rumplestiltskin

    Amplitude and intensity

    Argh, I was considering it shining over a one-dimensional circle. 20 / (4 * pi * 122) = 0.011, correct answer. Thanks!
  4. Rumplestiltskin

    Amplitude and intensity

    1. Homework Statement The light from a bulb shines equally in all directions. If 20W of light is given off, what will the intensity be 12m from the lamp to 2 significant figures? (Consider the shape of the region illuminated if the light hits this surface after travelling 12m in all...
  5. Rumplestiltskin

    Felix Baumgartner's parachute jump from space -- forces and velocities...

    R.F/95 = 7ms-2. 95 * 7 = 655, so this was my resultant force downwards. 931 - 655 = 276N upwards?
  6. Rumplestiltskin

    Quadratic and linear Intersection

    What was your answer? What did you plug in for b2 - 4ac? Your approach is correct, but I'd draw a graph to be sure. (Hint: you know the parabola is negative, and you know the y-intercept is -10.)
  7. Rumplestiltskin

    Felix Baumgartner's parachute jump from space -- forces and velocities...

    Right. At 30s drag from air resistance is less than the force of weight, so Baumgartner is accelerating. At 45s drag = force of weight, terminal velocity. At 70s drag is greater than force of weight, hence deceleration. Not sure if that's exactly the right terminology. Area under graph =...
  8. Rumplestiltskin

    Felix Baumgartner's parachute jump from space -- forces and velocities...

    Right, sometimes the obvious answer is the right one. 95 * 7 = 665N. So questions that ask you something like this where you end up calculating mg for upwards force are neglecting air resistance.
  9. Rumplestiltskin

    Felix Baumgartner's parachute jump from space -- forces and velocities...

    1. Homework Statement a)ii) Calculate the upward force F acting on Baumgartner at this point. (3 marks) total mass of Baumgartner = 95 kg g = 9.8 ms-2 b) Describe the shape of the graph between 30s and 70s. Explain the velocity changes in terms of changes in the air through which Baumgartner...
  10. Rumplestiltskin

    Factorising cubic

    Argh... thanks. I went over that 4 or 5 times and didn't catch it out.
  11. Rumplestiltskin

    Factorising cubic

    1. Homework Statement The curve C with equation y = f(x) passes through the point (5, 65). Given that f'(x) = 6x2 -10x - 12, a) use integration to find f(x) b) Hence show that f(x) = x(2x+3)(x-4) 3. The Attempt at a Solution I have no problem with this question, except it seems the given...
  12. Rumplestiltskin

    Acceleration and displacement

    I've also already worked that out as 0.5 * 10 * 52 = 125m. I'd stand by that. Why do you ask? Huzzah!
  13. Rumplestiltskin

    Acceleration and displacement

    Helpful, thanks. This answers 1) and 2), still not sure about 3) because the final velocity would still be 15m/s. That wasn't questioned earlier. Also, I take it you're happy with my answer and working?
  14. Rumplestiltskin

    Distance / speed / time

    I'm familiar enough with suvat, I just wasn't expecting to use it in this question, partly because of its mark count and partly because this is the first instance I've needed to use it outside of projectile motion. Thanks for the explanation. It's beginning to make sense, though I'm still...
  15. Rumplestiltskin

    Acceleration and displacement

    I apologise in turn. I was cavalier about it, because I thought that this was getting seriously overblown for a 1 mark. But I've just learnt that this question has been taken from a practice guide, not an exam paper. It would probably pass for more in an exam. Anyway, I thought about this some...
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