# Recent content by rvnt

1. ### Newton's Law of Universal Gravitation

Wait...so as you said to use a=Gm1/r^2...for venus I got a=(6.67*10^-11)(4.8690*10^24)/(1.08*10^11)^2= 2.784*10^-8
2. ### Newton's Law of Universal Gravitation

But mass of the satellite isn't given..?
3. ### Newton's Law of Universal Gravitation

Homework Statement I am doing a lab-"Kepler's Laws and Newton's Law of Universal Gravitation". There is an image representing various positions, at equal intervals, of a satelitte in an elliptical orbit around the earth. A list of planets and their radi and periods are given. I have calculated...
4. ### Newton's Laws with Friction; Inclines

µk(mgCos13deg)+mgSin13deg=a (0.489)(9.8Cos13deg)+(9.8)(Sin13deg)=a 4.669+2.2045=6.87??
5. ### Newton's Laws with Friction; Inclines

Ffr=ma µsN=ma µsmg=ma µs=4.8/9.80=0.4897? Than Sin(13degrees)*0.4897...??
6. ### Newton's Laws with Friction; Inclines

Homework Statement A car can decelerate at -4.80m/s^2 without skidding when coming to rest on a level road. What would its deceleration be if the road were inclined at 13degrees uphill? Assume the same static friction coefficient. Homework Equations Ffr=µkFN The Attempt at a...
7. ### Collisions in two dimensions

vA is the velocity of the electron before the collsion. p=mv the mass of an electron is 9.11*10^-31kg so v=(9.30*10^-23)/(9.11*10^-31)=1.0208*10^8m/s so I think va= 2(1.0208*10^8m/s) CosΘ?
8. ### Collisions in two dimensions

Oh right! k now I got it thank-you
9. ### Collisions in two dimensions

I think the angles are both 45degrees...and maybe vA= v'A Cos (45degrees)+v'B Cos(45degrees)= 2v'A Cos(45degrees)??
10. ### Collisions in two dimensions

Could you help me out with where I have went wrong please? or are my whole calculations incorrect and I should start over? Also, should I try figuring out the angle first or the speed?
11. ### Collisions in two dimensions

Homework Statement A radioactive nucleus at rest decays into a second nucleus, an electron and a neutrino.The electron and neutrino are emitted at right angles and have momenta of 9.3x10^23kg*m/s and 5.40x10^23kg*m/s, respectively. What are the magnitude and direction of the momentum of the...
12. ### Collisions in two dimensions

Homework Statement Billiard ball A of mass mA= 0.400kg moving with speed vA=1.80m/s strikes ball B initially at erst, of mass mB=0.500kg.As a result of the collision,ball A is deflected off at an angle of 30.0degrees with a speed v'A=1.10m/s. Taking the x-axis as the original direction of...
13. ### Relative Velocity Vector question

I understand the vector diagram properly now but I still am troubled with a). I realize the answer 608.28km/h is too high but what am I doing wrong? Square root of 600km/h^2 + 100km/h^2 is the only way I can think of to approach this questions?
14. ### Relative Velocity Vector question

Homework Statement An airplane is heading due south at a speed of 600km/h. If the wind begins to blow from the southwest at a speed of 100km/h (average), calculate: a) The velocity (magnitude and direction) of the plane relative to the ground b) How far from its intended position will it be...