Recent content by shawshank

hey, this isn't really a homework problem but I have this integral that I can't solve cause i haven't studied techniques of integration. Any suggesstions \int\frac{1}{\sqrt{12x+0.02x^2}}

Data is kind of confusing man. Why angles. The redbelly is what came to my mind too.

thomas the idea is really simple. if you have y^2 then different as if it was x , you should have 2y. simple right? Now all you have to do is multiply the 2y by dy/dx. Just write 2y . dy/dx and that's the answer. So whenever you different with the letter y, do it as if it was x but just...

It just means x either has to be bigger than 2/3 or smaller than 0. Makes sense, for example 1/2 is smaller than 2/3, plug it in and u get 4, which is not smaller than 3. Now try 2 which is bigger than 2/3, u get 1 which is smaller than three. This is why 2/3 > x doesn't make sense. Now...

no it's the classic way of doing things, we do it in high school. Ok, so you have 3 equations: [1]. -2=a + b +c [2]. 10=9a -3b +c [3]. 31= 16a +4b +c Eliminate a by using 9 * [1] - [2] and then 16 * [1] - [3] (-18 = 9a + 9b + 9c) - (10 = 9a - 3b + c) ---> -28 = 12b + 8c [4] (-32 = 16a + 16b...

The second derivative can be found the same process, just d(whatever is on each other side) by dx. Let's say you have x^3 + y^3 = xy First derivative is : 3x^2 + 3y^2 . dy/dx = y + x . dy/dx Now if everything on left side is g(x) and the right side is n(x). Then just do dg(x) / dx and do dn(x)...

use leibniz notation d/dx everything. if you d(x^3)/dx , u get 3x^2. The implicit part is differentiating the ys.If you assumme sin (y) = u --> du/dx = d(sin(y))/dx , is that clear? now du/dx = du/dy . dy/dx because u is composed of the variable y. so if you do this you'll have du/dx =...

thanks everyone, it actually looks good here in Toronto too, just a lot of snow but the sun is well out.

Proper New Year, start of spring. Happy Spring everyone, lol.

wait it is just me being tired or that is wrong. Shouldn't it be 1/3 not 1/2(a+b). maybe i didn't real before it.

thanks i got it, it's 1000. What is the rule called the (a^n - b^n).

lim of x ---> 1 (x^1000)(x+1)/(x^2-1) hahah, lol just kidding. seriously, have no clue where to start.

limit of x --> 1 (x^1000 - 1 ) / (x-1)

u can re-write as: 0 = (2^x)^2 - 3* 2^X * 2^2 + 32

u is initial velocity, and R is the normal force.