Recent content by soopo

Other possible medicines which were probably in contact with Zinc ions: - 1 tablett MADOPARK QUICK MITE: Levodop. 50 mg, benserazid. hydrochlorid. 14,25 mg respond. benserazid. 12,5 mg, constit. q. s. - Brufen (ibuprofen) - Selegilin I managed to duplicate a similar experiment without Zinc...

I was giving today zinc -tablet to a patient directly to her stomach because she cannot move. The tube which I first used was not clean so it contained some medicine of the last use. The tube turned light blue like copper ion -blue after I inserted the zinc water to the tube. I have not...

There is no grounding in the house so the electricity could not escape and it went to the air. Ok. Probably, the micro-oven gives the given electric shock always with the full power. I do not want to test it. Probably, the shape or nature of the object does not affect the formation of the...

I put 1 litre of ice cube to the micro-oven which is age is about 30 years. The shape of the ice cube was a little bit circular. I set the power of the micro to the maximum. There were continuous white electric shocks inside the micro. The ice cube contained a little fish which contained some...

WOOT! Thank you! I did not get it that it is the monomer of the PGA. It seems that PGA does not have different monomers: only the one. I now see that the monomer really make the polymer an ester.

The form of the ester is right: http://en.wikipedia.org/wiki/Ester One part of PGA has the above form. I had only the given part of PGA in the exam. It was my first time to see PGA. I am trying to deduce somehow that PGA has an ester -part. PGA is poly glycosidic acid. This means that there is...

Esters have the form R-CO-OR'. PGA has the form [-O-CH3-CO-]. It is a polyester that means an ester according to Wikipedia. I cannot see why it is an ester. It does not have two oxygens bind to one carbon. Why is PGA an ester?

Homework Statement The series is at http://img203.imageshack.us/i/snapshot1g.png/ The Attempt at a Solution The LHS series diverges. However, the term 1/n seems to be make the series to converge. However, I am not completely sure how to proceed in proving that the series converges. I should...

My y -value [itex] obtained by differentiation is different from the one obtained by substitution that is (1, -e^(-t)) != (t^2 + 1, -2e^(-t))

I had a typo in my reply. I mean by "putting y to x" that you make y equals x in the last statement for x'. I differentiate the x by getting the same x' which I get by plugging in the x for the statement x'. How can you show that x(t) = (et, -t) is a solution of the differential equation?

I get x' = (e^t, -1) by putting x to x' and x' = (1,-e^t) by putting y to x'. This gives me t = -t that is 1 = -1 which is false.

Homework Statement Show that the vectors \overline{x}(t) = \begin{bmatrix} e^t \\ -t \end{bmatrix} and \overline{y}(t) = \begin{bmatrix} t \\ e^(-t) \end{bmatrix} are solutions for \overline{x}' = \frac {1} {1+t^2} \begin{bmatrix} 1+t & e^t(1-t) \\ -e^-(t) (1+t) & t-1...

Homework Statement How can you convert 212 in base-10 to base-9? The Attempt at a Solution There are holes in the sequence of figures when considering 212 in base-9. There are 21 holes in the line. There also holes from 90 to 99 and from 190 to 199. There are then 40 (= 23+10+10-1) holes in...

I get the following solution which gives me a Pythogoran triangle so the two vectors must be at 90 degree angle to each other. \frac {y - 0 } { x + R } = \frac {y} {x + R} and \frac {y - 0 } { x - R } = \frac { y} {x - R } which results in x^2 + y^2 = R^2 . So the two vectors are at 90...

The summation is to infinity. The sum is always positive so the range is always real. This would suggests me that x > 0 and y > 0. However, I am uncertain, since the solution should not be that easy.