How Do You Convert 212 from Decimal to Base-9?

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Homework Help Overview

The discussion revolves around converting the decimal number 212 into base-9. Participants explore the conversion process and the reasoning behind their calculations.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Some participants attempt to analyze the conversion by identifying "holes" in the sequence of base-9 figures and calculating the number of each power of 9 that fits into 212. Others question the validity of this approach and suggest a more straightforward method involving division to find the base-9 representation.

Discussion Status

There are differing interpretations of the conversion process, with some participants affirming the result of (255) in base-9 while others express confusion over the initial reasoning involving "holes." A few participants provide calculations that support the conversion, indicating a productive exploration of the topic.

Contextual Notes

Participants are navigating the complexities of base conversion, with some expressing uncertainty about the initial assumptions and calculations. There is mention of specific numerical relationships and remainders that are critical to the conversion process.

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Homework Statement


How can you convert 212 in base-10 to base-9?

The Attempt at a Solution



There are holes in the sequence of figures when considering 212 in base-9.
There are 21 holes in the line. There also holes from 90 to 99 and from 190 to 199.
There are then 40 (= 23+10+10-1) holes in the line, since 198 belongs to the previous sets already.
This suggests me that the figure in base-9 is at least 242.
However, the correct answer is 248.
 
Last edited:
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21210 = 2*102 + 1*101 + 2*100

What you want to do is write this number as the sum of multiples of powers of 9, which are 1, 9, 81, 243, and so on.

How many 81's (= 92) are there? That will be you digit in the 92 place.
If there's a remainder after subtracting of the 81's, how many 9's are there in that remainder? That will be your digit in the 9's place.
If there's a remainder (and it better be 5) that will be your 1's place.

If you're converting 21210 to its base-9 equivalent, 248 IS NOT the correct answer. I don't understand what you're talking about with holes in the line.
 
soopo said:

Homework Statement


How can you convert 212 in base-10 to base-9?

The Attempt at a Solution



There are holes in the sequence of figures when considering 212 in base-9.
There are 21 holes in the line. There also holes from 90 to 99 and from 190 to 199.
There are then 40 (= 23+10+10-1) holes in the line, since 198 belongs to the previous sets already.
This suggests me that the figure in base-9 is at least 242.
However, the correct answer is 248.

The answer should be (255)_{9} . Correct me if I'm wrong.
212=207+5=23*9+5
23=2*9+5
2=0*9+2

Combining all together,

212=9(2*9+5)+5=2*9²+5*9+5
Suggesting 212=(255)_{9}
 
Last edited:
Yes, 255 is right. That's easy enough to check: 2*9^2+5*9+5=212.
 
The quick way to do this is: divide 212 by 9. 9 divides into 212 23 times with remainder 5. 9 divides into 23 twice with remainder 5: 21210= 2559.

That is because saying that 9 divides into 212 23 times with remainder 5 means that 212= 9(23)+ 5. Since 9 divides into 23 twice with remainder 5, 212= 9(9(2)+ 5)+ 5= 2(92)+ 5(9)+ 5.
 

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