Rasalhague
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JesseM said:How is "moment" different from "surface of simultaneity"
They're synonymous as far as I know. That's how I intended them, anyway.
JesseM said:Again, time dilation isn't defined in terms of readings at one particular moment/surface of simultaneity, it's defined by the interval of time between two specified events.
...and length contraction isn't defined by a single worldline, it's defined by the distance between two worldlines.
Okay, perhaps I should have use the more general, more explicit forms of the equations with delta symbols, rather than incorporating an event at the mutual origin of the two frames into the definition (clock's being synchronised as they pass; rulers aligned as their zero ends pass).
JesseM said:But that would mean that in the exact same physical scenario you could call it either contraction of dilation depending on the whims of what variable your teacher gave you first. In any case, the convention is also that the time dilation and length contraction equations are written in a form where the observer's frame is the output of the equation, although of course you can rearrange to solve for the proper time/proper length if you wish.
Dilation means an increase, so why do you say it suggests the variable would take a smaller value in the observer's frame? I said several times that when I said it was defined "in terms of the observer's frame", I meant that you used the word "dilation" if the value was bigger in the observer's frame, and "contraction" if the value was smaller in the observer's frame. If you think it's better to describe this as defining it "in terms of the moving frame", I would find that very confusing, but go ahead and do so as long as we're clear on the previous sentence.
When I asked what does it signify to call one frame the "observer's frame" and the other the "clock frame", you said:
"It signifies that we are talking about the time intervals in each frame between events which have been specifically selected to occur on the clock's worldline (so they are colocated in the clock's frame but not the observer's). In any of these equations, the quantity we are dealing with takes a "special" value in one of the two frames--for example, if the quantity is the time interval between two events with a timelike separation, then this time interval is minimized in the frame where the two events are colocated, making that the "special" frame. The frame where the quantity does not take a special value is the one we have been calling the "observer's" frame."
But in #375, in response to my description of Michael Fowler's example in terms of your definition of the "temporal analogue for length contraction", you redefined special:
"Yes, that actually works, provided you here treat Jill as "the observer" rather than Jack. I hadn't thought of it like this, but you're right that the measurements involved in an ordinary time dilation experiment like this can be re-interpreted as a TAFLC measurement, just by switching who we call "the observer", and by switching what defines the "special" frame from the frame where the time between two events on Jill's worldline is minimized (i.e. her own frame) to the frame where two spacelike surfaces that Jill passes through are surfaces of simultaneity (i.e. Jack's frame, since we were already considering his surfaces of simultaneity when showing how he would measure the time elapsed on Jill's clock)."
I'm a bit confused by this switching. When you use "observer's frame" and "clock frame" now are you going by your original first definition, or should I take them to have the second meaning sometimes, depending on the problem to be solved?
Yes the same physical scenario could be described with value A as input and value B as output, or vice versa, but what's so whimsical about that? I thought this is just what you advised me the convention was with the terms unprimed and primed. Input and output are more explicit names than unprimed and primed, given the various different uses that prime symbols are put to in this context by different textbooks. I thought they might be handy terms to distinguish between kinds of frames when talking in the abstract about the kinds of questions that can be asked of the formulas, but I agree it would be impractical to switch back and forth in the middle of working on a complex problem. If we want to use fixed labels for frames that don't vary depending on the question, we need use some other names, like left and right, or something that expressed the idea of - would it be correct to say - "the rest frame of the (spacetime) interval"? (I.e. what you were describing in your first definition of "special frame".)
JesseM said:And again, the convention is that the moving frame is the "input", and in fact most problems will give you this first. But as I said I think it would be confusing to have the phrase dilation and contraction depend on the whims of which value a textbook or teacher provided you with first.
So what do you make of Doc Al's example in #385, equivalent to Michael Fowler's with Jack and Jill, where the moving frame is the output frame? Is that unconventional? How would you express the problem in conventional terms? Would you just swap the names of the frames? What if you were making a series of calculations of various qualities back and forth between too frames; would you switch labels every time you needed to divide by gamma in moving from a frame that you'd previously multiplied by gamma in order to find a time value for? That sounds even more complicated to me than continually switching which frame we call the primed or output frame.
Does your observer's frame equate with Doc Al's lab frame, and your clock frame equate with Doc Al's moving frame? And if so, is that your observer's frame and clock frame as originally defined, or as redefined in the example that involved dividing my gamma which we described in terms of "temporal analogue for length contraction"?
JesseM said:I understand the concern, but see above for why I think this alternate convention would be confusing. In any case, the issue of the convention is already decided for us.
But there is something inherently dilatory about the proper time between two events and something inherently contractory about the length of an object in its rest frame--do you agree? On the other hand, there is also something inherently dilatory about the proper distance between two spacelike-separated events, where "proper distance" refers to the distance between the events in the inertial frame where they're simultaneous (the distance in other frames will always be greater).
Yes and, to complete the picture, something inherently contractory about the time period (whatever we call it) which bears the same relation to time as the length of an object does to space. The convention of matching up time dilation with length contraction, as somehow representative of time and space respectively, seems like someone holding up a whole apple and the core of an eaten pear and saying, "Look, apples are a whole fruit, but pears are eaten." Of course, being whole is no more a defining feature of apples than being eaten is a defining feature of pears; they aren't a whole kind of fruit and an eaten kind; either can be whole or eaten. Okay, that's an absurd analogy: no one's going to think of fruit that way. But because relativity is so counterintuitive when we first meet it, we don't know what the distinguishing properties of time and space might be. We don't have everyday experience of passing macroscopic objects at "relativistic" speed. So when we meet this combination of equations and their associated names, it's easy get confused or jump to the (mistaken) conclusion that the pairing directly embodies some fundamental difference or asymmetry between how time and space behave in special relativity, when really it's a matter of convention (albeit there might be reasons motivating that convention). A different pairing (a different convention), one that compared like with like as the full Lorentz transformation does, might avert that problem and make a better mnemonic. There would be no loss in calculating convenience, since we could carry on - as now - inverting either equation as required.
JesseM said:What question did you give to Wolfram Alpha, exactly?
I didn't ask a specific question. I just typed "time dilation" then toggled between "moving time" and "stationary time" in the "calculate" menu directly under the input field. Likewise with "length contraction" ("moving length", "stationary length"). It takes as its default input 1 second, in the case of time, and 1 meter, in the case of length.