Dale
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Sorry about the confusion. Hopefully I can clear it up.GrayGhost said:Maybe you misunderstood my prior post? Your response suggested that I may not have known that the Minkowski metrics (-+++) and (+---) are both used. I must say though, I was unaware indeed that any (++++) Minkowski metric was ever used, and find that quite suprising ...
Here's what I was saying ...
Yuiop suggested the 4d euclidean length of the path along ict' would be ... ct' = sqrt[ (ct)2+(vt)2 ], ie the longest path, which stemmed from yuiop's assumption that (ct')2=(ct)2+(vt)2. That's a (++++) euclidean metric. This would be true if the time axes were not imaginary, however they are.
So I merely pointed out that applying Pathagorus' theorem to our particular complex systems cannot produce yuiop's (++++) metric, they can only produce the Minkowskian (-+++ or +---) metrics. Which itself means that one cannot say (ct')2=(ct)2+(vt)2 in the very first place, or equivalently ... one cannot say the longest path is ict'.
EDITED: On the other hand, if we ignore the fact that time is represented as imaginary, one can easily say (ct')2=(ct)2+(vt)2 resulting in the euclidean metric (++++). But then that is mathemaically improper. Nonetheless, this makes the paper length of ict' the longest, as yuiop pointed out. Are there more benefits to doing this, than not doing this? IMO, I don't think so. I suppose one could always try, see if they can find ways of avoiding any resultant confusion maybe. I have witness countless debates over many years as to whether the longest worldline length is the shortest proper time experienced, versus whether the shortet worldline length is the shortest proper time experienced. Few surrender their position. However, I'd also have to submit that most do not qualify as to whether the system is euclidean vs Minkowskian. IOM though the "complex" euclidean system we begin with IS a Minkowskian system from the start.
Am I incorrect on this reasoning?
We want to obtain the line element from the coordinates and the metric as follows:
ds^2=-c^2dt^2+dx^2+dy^2+dz^2=g_{\mu\nu}x^{\mu}x^{\nu}
To do this we can adopt one of three conventions:
x^{\mu}=(ict,x,y,z) and g_{\mu\nu}=\begin{pmatrix}1&0&0&0\\0&1&0&0\\0&0&1&0\\0&0&0&1\end{pmatrix}
or
x^{\mu}=(ct,x,y,z) and g_{\mu\nu}=\begin{pmatrix}-1&0&0&0\\0&1&0&0\\0&0&1&0\\0&0&0&1\end{pmatrix}
or
x^{\mu}=(t,x,y,z) and g_{\mu\nu}=\begin{pmatrix}-c^2&0&0&0\\0&1&0&0\\0&0&1&0\\0&0&0&1\end{pmatrix}
I was merely pointing out that the first convention, ict, fell out of use decades ago.