Whose Clock Slows Down in Relativity?

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The discussion centers on the effects of relativity on time perception between observers in different frames of reference, particularly involving a space station and a spacecraft. It highlights that while both observers perceive the other's clock as running slow due to their relative motion, the actual time experienced can differ significantly when they reunite. The key point is that the clock that remains inertial (not accelerating) will age more than the one that undergoes acceleration, leading to a measurable difference in elapsed time. The calculations presented clarify that gravitational effects and relative speeds contribute to time dilation, with the space station clock running slightly slower than a clock on Earth. Ultimately, the understanding of whose clock runs slow is resolved only when both clocks are compared at the same location.
  • #91
GrayGhost said:
Maybe you misunderstood my prior post? Your response suggested that I may not have known that the Minkowski metrics (-+++) and (+---) are both used. I must say though, I was unaware indeed that any (++++) Minkowski metric was ever used, and find that quite suprising ...

Here's what I was saying ...

Yuiop suggested the 4d euclidean length of the path along ict' would be ... ct' = sqrt[ (ct)2+(vt)2 ], ie the longest path, which stemmed from yuiop's assumption that (ct')2=(ct)2+(vt)2. That's a (++++) euclidean metric. This would be true if the time axes were not imaginary, however they are.

So I merely pointed out that applying Pathagorus' theorem to our particular complex systems cannot produce yuiop's (++++) metric, they can only produce the Minkowskian (-+++ or +---) metrics. Which itself means that one cannot say (ct')2=(ct)2+(vt)2 in the very first place, or equivalently ... one cannot say the longest path is ict'.

EDITED: On the other hand, if we ignore the fact that time is represented as imaginary, one can easily say (ct')2=(ct)2+(vt)2 resulting in the euclidean metric (++++). But then that is mathemaically improper. Nonetheless, this makes the paper length of ict' the longest, as yuiop pointed out. Are there more benefits to doing this, than not doing this? IMO, I don't think so. I suppose one could always try, see if they can find ways of avoiding any resultant confusion maybe. I have witness countless debates over many years as to whether the longest worldline length is the shortest proper time experienced, versus whether the shortet worldline length is the shortest proper time experienced. Few surrender their position. However, I'd also have to submit that most do not qualify as to whether the system is euclidean vs Minkowskian. IOM though the "complex" euclidean system we begin with IS a Minkowskian system from the start.

Am I incorrect on this reasoning?
Sorry about the confusion. Hopefully I can clear it up.

We want to obtain the line element from the coordinates and the metric as follows:

ds^2=-c^2dt^2+dx^2+dy^2+dz^2=g_{\mu\nu}x^{\mu}x^{\nu}

To do this we can adopt one of three conventions:

x^{\mu}=(ict,x,y,z) and g_{\mu\nu}=\begin{pmatrix}1&0&0&0\\0&1&0&0\\0&0&1&0\\0&0&0&1\end{pmatrix}

or

x^{\mu}=(ct,x,y,z) and g_{\mu\nu}=\begin{pmatrix}-1&0&0&0\\0&1&0&0\\0&0&1&0\\0&0&0&1\end{pmatrix}

or

x^{\mu}=(t,x,y,z) and g_{\mu\nu}=\begin{pmatrix}-c^2&0&0&0\\0&1&0&0\\0&0&1&0\\0&0&0&1\end{pmatrix}

I was merely pointing out that the first convention, ict, fell out of use decades ago.
 
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  • #92
yuiop said:
I would like to take the qualifiers one at a time.
In an introduction to SR and spacetime diagrams, this is as good a time as any, to demonstrate that velocities of real particles or clocks that are greater than the speed of light is incompatible with SR and causes contradictions.
That you can only move forward in coordinate time is a very natural intuition for any lay person that has not not yet been introduced to relativity. If a tutor wrote this problem on the board: The students would immediately object to your traveling from the paper shop to your work in minus one hour. The concept that coordinate time only advances is entirely natural and we have never measured anything that contradicts this and the thermodynamic arrow of time generally supports this.
I am not quite sure what you mean by this last qualifier. If by "comparing paths between different points" you mean comparing elapsed proper times between clocks that are initially co-located and finally co-located, then this is as good as time as any to introduce the students to the concept that you can not compare elapsed proper times of spatially separated clocks in meaningful invariant way. If two clocks are spatially separated, then different observers will disagree on which clock is ticking slower. Until the clocks are re-co-located any comparison of elapsed proper times is just a matter of opinion and is observer dependent.

To GrayGhost. I am not ignoring you. It is just that I believe that Dalespam is doing a better job in responding to your objections than I ever possibly could. :wink:

Fine, but this still all boils down to 'you can use your Euclidean intuition except for all the ways SR is not Euclidean, and timelike motion is very special (in Newtownian physics, time is not included in the metric at all; when you bring it into the SR metric, you then say: use some Euclidean intuition except for all these gotchas). You could use each gotcha as above to teach a 'why', as suggested above. I prefer, instead, to make analogies to non-Euclidean geometry and highlight how it is risky to rely on Euclidean intuition.

Note, it is not so trivial to banish forward and back in time. If you are dealing with specelike paths, many non-inertial frames have paths of simultaneity that move forward and backward in time viewed in an inertial frame.

Anyway, I don't see that we disagree on an any facts or interpretations. We have a different judgment on the value of a heuristic that can be used with the appropriate rules.
 
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  • #93
DaleSpam said:
No, I agree with yuiop. What you are saying is true, but it is a tautology.

Here "path through the continuum" means "spacetime interval", and "ages less" means "experiences less proper time", and "proper time" is "timelike spacetime interval". So your earlier statement is:

"If 2 observers reside at both events, eg in the twins scenario, then the one who travels the shorter spacetime interval experiences less timelike spacetime interval over the interval, because he accrues less timelike spacetime interval".

Which is tautologically true. Similarly, this statement is tautological:

"Therefore, he who travels the longest spacetime interval must experience the most timelike spacetime interval, because he must accrue the most timelike spacetime interval over the interval"

I might say that that these statements are applications of definitions made to look tautological. I'm sure you agree that defintion of the invariants and their physical interpretation is perhaps the most essential part of SR.

Meanwhile, yuiop's proposed substitute Euclidean metric that can, with appropriate restrictions, allow one to read certain strictly qualitative results from a diagram, has no physical validity in the theory, and therefore can even less explain anything than a definition. You can't attach any meaning at all to the numeric value of interval based on dt^2 + dx^2. You can attach definite, invariant meaning to proper time.
 
  • #94
PAllen said:
I might say that that these statements are applications of definitions made to look tautological.
Do you know any other definitions for the terms I mentioned?
 
  • #95
I think I want to make more specific statement here, while still noting I don't think we disagree on anything except 'teaching approach'.

yuiop said:
I would like to take the qualifiers one at a time.
In an introduction to SR and spacetime diagrams, this is as good a time as any, to demonstrate that velocities of real particles or clocks that are greater than the speed of light is incompatible with SR and causes contradictions.
When you go beyond world lines to spacelike paths, then both the prior and succeeding restriction go away (due to relativity of simultaneity). Then you are confronted with saying the Euclidean analogy loses its meaning. My preference is just to get right to the issue of defining timelike invariant (physical time along a world line) and spacelike invariant (an invariant that has the character of length). Timelike geodesics (inertial paths) maximize proper time. Spacelike geodesics minimize distance in an inertial frame in which the endpoints are simultaneous.
yuiop said:
That you can only move forward in coordinate time is a very natural intuition for any lay person that has not not yet been introduced to relativity. If a tutor wrote this problem on the board: The students would immediately object to your traveling from the paper shop to your work in minus one hour. The concept that coordinate time only advances is entirely natural and we have never measured anything that contradicts this and the thermodynamic arrow of time generally supports this.
I am not quite sure what you mean by this last qualifier. If by "comparing paths between different points" you mean comparing elapsed proper times between clocks that are initially co-located and finally co-located, then this is as good as time as any to introduce the students to the concept that you can not compare elapsed proper times of spatially separated clocks in meaningful invariant way. If two clocks are spatially separated, then different observers will disagree on which clock is ticking slower. Until the clocks are re-co-located any comparison of elapsed proper times is just a matter of opinion and is observer dependent.
In Euclidean geometry, you can compare lengths of any curves on the plane. In SR you can compare invariant interval along any timelike or spacelike paths. In your 'heuristic Euclidean metric' any conclusion you draw for curves that don't begin and end at the same points are likely wrong. This is an opportunity for major confusion, despite the 'teaching opportunity you describe.
 
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  • #96
DaleSpam said:
Do you know any other definitions for the terms I mentioned?

I'm trying to say that defining timelike interval in a certain way (mathematically) coupled with the (physical) interpretation that it represents physical time along a world line is not tautological at all. It is a very strong prediction to be proven true or false. And that often there is little more you can say about 'why' you age differently on one path than another than the definition proper time.

I am often bothered by 'explanations' of things with limited validity. For example, in the twin paradox, that the 'missing aging' is associated with some particular part of the path. Any of these break down with a different variant, and all are based on simultaneity conventions which are purely conventions (as you have explained in many other posts). In this discussion, the meaningless explanation I see is 'longer Euclidean path is shorter proper time'. Except this doesn't explain anything and is generally false. While interval is a coordinate independent quantity of any path (except you might exclude mixed timelike and spacelike), that all agree on, the Euclidean analogy is only good (qualitatively, not quantitavely) for certain pairs of timelike paths - and even then it doesn't explain anything, and certainly doesn't 'get around' any dissatisfaction with statements like 'you aged less because you took a path with less time on it'. That is no different than accepting, in Euclidean geometry, that it takes more string along path A than path B because A is longer than B.
 
  • #97
DaleSpam & yuiop,

Thanx for your prior responses. I haven't had any problem (or issue) with spacetime interval formulae. The one thing I was unaware of, was that (ict)2+(vt)2 was an outdated former Minkowski metric. However, that doesn't effect any of the points I've been raising here.

Yuiop asked for opinions on the matter of defining a new spacetime interval length per the stationary POV, a euclidean 4d length ... (ct)2+(vt)2. The hope was that something new could be used in classroom. The desire was to expedite the determination as to who aged more or less over the defined interval, or make the learning of relativity theory easier via convenience.

It seems inappropriate IMO, that within the same theory we might consider axes as imaginary in some circumstances and real in others. The imaginary axes are required for transformation (ie rotation) between the 2 systems, given the 2 postulates true. However, let's assume that there exist instances whereby we desire calculations that require no transformations between the 2 systems ... eg the one yuiop desires. OK, so we ignore the fact that time axes are imaginary, and inquire as to the length of the spacetime interval, per the stationary POV. We then attain this metric ... (ct)2+(vt)2.

Now, we inquire as to the physical meaning of (ct)2+(vt)2. The soln would represent the distance traversed thru euclidean 4-space, per only the stationary POV.

Next we ask, of what benefit might this be? I can think of none, personally. Yuiop has pointed out that it may make the determination as to who aged the least (vs most) more convenient.

Are there any disadvantages ... The magnitude of this 4d distance vector would pertain only to the stationary POV, it cannot be measured, and can only be predicted. There would exist no way of confirming the prediction correct, nor would we ever expect it to. It surely does not represent clock readings of either system. We'd now have a new (extra) description of the spacetime interval, a frame dependent solution, which would differ from the related invariant soln of Minkowski. Lengths of worldlines would no longer (numerically) equal the proper time experienced in all cases, and the meaning of a worldline length would likely become confused.

That said, although I respect any goal to add convenience to education, I venture that goal would not be met in this case. I could always always be merely mistaken :)

GrayGhost
 
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  • #98
PAllen said:
I am often bothered by 'explanations' of things with limited validity. For example, in the twin paradox, that the 'missing aging' is associated with some particular part of the path.

PAllen,

I was unaware of a "missing aging" crisis. I'm just curious ... are you referring to 'ole instantaneous velocity changes per the non-inertial POV maybe?

GrayGhost
 
  • #99
GrayGhost said:
The one thing I was unaware of, was that (ict)2+(vt)2 was an outdated former Minkowski metric. However, that doesn't effect any of the points I've been raising here.
Correct, I was not intending it as a rebuttal of any of your points. I was simply mentioning that the convention is not commonly used any more. I don't know why it has fallen out of use, except that the others are more "GR-ish" (especially the last).
 
  • #100
GrayGhost said:
PAllen,

I was unaware of a "missing aging" crisis. I'm just curious ... are you referring to 'ole instantaneous velocity changes per the non-inertial POV maybe?

GrayGhost

This refers to many recent threads on the twin paradox. There is no crisis. Just that some people put forward arguments that the 'missing aging' of the twin who ages less 'should' be attributed to one part of the path or another. Dalespam and I have argued that these attempts are misguided because:

- for some variation on the twin scenario (changing timing, smoothness of acceleration, changing whether there is any coasting or not), you find they break down

- more fundamentally, they are really making a statement about distant simulataneity between the longer aging world line and the shorter aging world line, and any such choice of simultaneity convention has a substantially arbitrary character (within certain fundamental limits: you can't consider two causally connected events to be simultaneous).
 
  • #101
PAllen said:
In Euclidean geometry, you can compare lengths of any curves on the plane. In SR you can compare invariant interval along any timelike or spacelike paths. In your 'heuristic Euclidean metric' any conclusion you draw for curves that don't begin and end at the same points are likely wrong. This is an opportunity for major confusion, despite the 'teaching opportunity you describe.
I disagree that you can compare invariant intervals along any timelike paths. For example if we have one clock (A) that remains at rest in frame S and another clock (B) that moves at 0.8c relative to S, then according to an observer in S, less proper time has elapsed for clock B at any coordinate time t. Now if we switch to frame the rest frame of clock B, (S') then an observer at rest in frame S' will say less proper time has elapsed for clock A relative to clock B at any coordinate time t'. In other words asking "whose clock is really slower?" for two clocks that are not initially and finally co-located is meaningless even in the purely SR/Minkowski context. While B is still going away from A, which clock would end up with the least elapsed proper time when they come back together again, depends entirely upon which clock turns around and accelerates towards the other and without a crystal ball to predict the future, we do not know which clock that will be until they are actually alongside each other again. This is a very important point is the context of the main question originally posed in this thread.
 
  • #102
GrayGhost said:
However, let's assume that there exist instances whereby we desire calculations that require no transformations between the 2 systems ... eg the one yuiop desires. OK, so we ignore the fact that time axes are imaginary, and inquire as to the length of the spacetime interval, per the stationary POV. We then attain this metric ... (ct)2+(vt)2.
I am not sure why you are fixated on time axes being imaginary, when we can do the calculations for timelike paths without any imaginary or complex values. Sure, imaginary quantities can turn up when considering spacelike intervals, but if we restrict ourselves to the subject of this thread (clock rates) then this does not apply. I am also not sure why you think it is impossible to do transformations to different POVs. If we take two paths in a given reference frame where the path with the least proper time has the greatest Euclidean 4d length (ct)2+(vt)2 and use the regular Lorentz transformation to obtain the POV of an observer at rest in a different reference frame, then it is still true that the path with the least proper time has the greatest Euclidean 4d length.
GrayGhost said:
Now, we inquire as to the physical meaning of (ct)2+(vt)2. The soln would represent the distance traversed thru euclidean 4-space, per only the stationary POV. Next we ask, of what benefit might this be? I can think of none, personally. Yuiop has pointed out that it may make the determination as to who aged the least (vs most) more convenient.
It is the POV of a single inertial observer, but as mentioned above we can transform to the POV of any inertial observer and the inequality still holds. Let us say we have clocks 1 and 2 with paths (\Delta t1,\Delta x1) and (\Delta t2,\Delta x2) respectively. According to any inertial observer, if the inequality (\Delta t2)^2+(\Delta x2)^2 > (\Delta t1)^2+(\Delta x1)^2 then it always holds that the inequality \Delta \tau 2 > \Delta \tau 1 is also true (given the 3 conditionals* that I gave earlier). Although the Euclidean 4d calculation is qualitative rather than quantitative (as PAllen pointed out) it is instantly visually obvious which is the path with the least proper time because any student already knows that the combined lengths of any two sides of a triangle is greater than the length of the third side and that the shortest spatial distance between any two points is a straight line. Here they can use their Euclidean intuition and then apply the relativistic "twist".
GrayGhost said:
Are there any disadvantages ... The magnitude of this 4d distance vector would pertain only to the stationary POV, it cannot be measured, and can only be predicted. There would exist no way of confirming the prediction correct, nor would we ever expect it to. It surely does not represent clock readings of either system. We'd now have a new (extra) description of the spacetime interval, a frame dependent solution, which would differ from the related invariant soln of Minkowski. Lengths of worldlines would no longer (numerically) equal the proper time experienced in all cases, and the meaning of a worldline length would likely become confused.
Sure we would a different name for Euclidean 4d length other that worldline length or spacetime interval to avoid confusion. I disagree that it cannot be measured. Many so called measurements are not direct measurements but rather are calculations, e.g. velocity is not always a direct measurement but a calculation of distance versus time and kinetic energy etc. I agree that the Euclidean 4d distance is not frame invariant, but as an logical (true/false) inequality it is invariant.
GrayGhost said:
It seems inappropriate IMO, that within the same theory we might consider axes as imaginary in some circumstances and real in others. The imaginary axes are required for transformation (ie rotation) between the 2 systems, given the 2 postulates true.
Again, I think you need to elucidate on why you think time is imaginary and why imaginary axes are required for transformation.

*As for the 3 conditionals I gave earlier, these are not over and above the conditionals required by SR for real clocks. (By "real clocks" I mean clocks with non zero real rest mass rather than imaginary or complex rest mass) These conditionals are required by SR too.
 
  • #103
yuiop said:
I disagree that you can compare invariant intervals along any timelike paths. For example if we have one clock (A) that remains at rest in frame S and another clock (B) that moves at 0.8c relative to S, then according to an observer in S, less proper time has elapsed for clock B at any coordinate time t. Now if we switch to frame the rest frame of clock B, (S') then an observer at rest in frame S' will say less proper time has elapsed for clock A relative to clock B at any coordinate time t'. In other words asking "whose clock is really slower?" for two clocks that are not initially and finally co-located is meaningless even in the purely SR/Minkowski context. While B is still going away from A, which clock would end up with the least elapsed proper time when they come back together again, depends entirely upon which clock turns around and accelerates towards the other and without a crystal ball to predict the future, we do not know which clock that will be until they are actually alongside each other again. This is a very important point is the context of the main question originally posed in this thread.

Invariant means all observers agree on it, independent also of coordinate system. Otherwise it isn't invariant. All observer's agree on the interval along a world line: that a give particle decays or not, that a person dies of old age or not, what a clock reads along a world line. They may perceive that a clock on some world line goes a different rate than their own, they will radically disagree on which points of different world lines are 'simultaneous', but there is never any disagreement on what the clock on some world line does between two physical events. This is fundamental to both SR and GR.

Colocation is irrelevent. Suppose you are traveling at .99c from start s1 to s2. You send me a picture of yourself at s1, and send me another picture when you get to s2. However long it takes me to get these signals, I will agree on how much aging you will experience (as long as I know the distance from s1 to s1 as I would measure it, and your speed). You will experience the aging I compute. Further, if you know my start and end points as you would measure them, and my speed as you measure it, and compute the invariant interval along my path in these coordinates, you will get the same longer age that I experience. The explanation of why you agree on my invariant interval while still seeing my clock going slow is that you radically disagree on simultaneity. The event on my worldline I say is simultaneous to your passing s1 is not at all what you would say.

Let's make this last point more concrete. Let's say I blow up an H-bomb at t1 and t2 on earth. When I get your signals sent from s1 and s2, as I inerpret where s1 and s2 are, factoring in light delay, I find (miraculous coincidence) the you sent your singal from s1 at t1, and from s2 at t2. I compute both intervals and find you aged much less, consistent with the pictures you sent.

You do the same thing. Only you find that t1 and t2 are not remotely simultaneous with when you were at s1 and at s2. However, taking into account when they occurred as you see them, and where I was at t1 and t2, as you see it, would would compute the same age difference for me as I actually experienced.
 
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  • #104
yuiop said:
I am not sure why you are fixated on time axes being imaginary, when we can do the calculations for timelike paths without any imaginary or complex values. Sure, imaginary quantities can turn up when considering spacelike intervals, but if we restrict ourselves to the subject of this thread (clock rates) then this does not apply.

Hmmm. Well, we've been discussing the length of the spacetime interval as defined under the Minkowski model. OK then, are you suggesting here that imaginaries do not apply wrt clock rates?

Seems to me that you might not understand the meaning of complex systems. I do realize that Einstein did not use imaginaries in his OEMB. But Minkowski recognized that the Einstein model was equivalent to a relative rotation if the time axes were assumed orthogonal wrt 3-space. Remember, we begin with a spacetime illustration with imaginary time axes. Minkowski did not designate these as such for no good reason. They in fact were necessary, if Einstein's kinematic scenario is to be modeled consistent with his LT solns.

Where ict' = s, we start with this vector equation ...

(ict')2 = (ict)2+(vt)2

And we end up with this vector equation ...

(ct')2 = (ct)2-(vt)2

which reduces to ...

t' = t(1-v2/c2)1/2
If you think that the 2nd equation above exists regardless as to whether the i's exist in 1st eqn or not, you are mistaken. The 2nd eqn exists only after applying the Pathorean theorem, which itself requires the squaring of imaginary vectors (and where i2 = -1) ... physically, the ict-axis (or likewise the ict'-axis) is rotated 90 deg into a real 3-space plane. It is this rotation that allows the LTs to result in the precise way they did.

That said, it is impossible to obtain this ...

(ct')2 = (ct)2+(vt)2

if starting from this ...

(ict')2 = (ict)2+(vt)2

On the other hand, one can obtain this last metric if one ignores the fact that the ict time axis is imaginary (as you wish to), because then no rotations/transformations are done. That is, ict' would not then be indicative of either the moving (or even the stationary) frame's measure of space or time. The resultant value of ict' no longer represents the time of anything real, and would represent a distance thru spacetime that cannot be measured or verified by anyone. I realize what you are trying to do yuiop, however if done, I see more losses than gains, IMO.

GrayGhost
 
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  • #105
GrayGhost said:
Hmmm. OK then, so you claim here that imaginaries do not apply wrt clock rates.

Seems to me that you may not understand the meaning of complex systems. Remember, we begin with a spacetime illustration with imaginary time axes. Minkowski did not designate these as such for no good reason. They in fact were necessary, if Einstein's kinematic scenario is to be modeled consistent with his LT solns.

GrayGhost, I always am impressed with your posts and do not wish to argue against the very good presentation you've made on this. But here is the derivation I've done before (sorry I don't remember the link). This is just to show there is an alternative derivation that begins with a 4-dimensional spacetime--just to show it is possible to develop the Minkowski metric without resorting to an imaginary axis. You can always put one in, just because any parameter or variable shown as a negative squared quantity, i.e., -X^2, can be represented with an imaginary number arbitralily inserted, i.e., -X^2 = (iX)^2. After developing the metric as shown below, you can of course do this in order to have an imaginary axis.

I derived the metric, then substituted in the ct without ever resorting to the imaginary i to obtain the Lorentz transformation for the double-bar time.

In this derivation we just use spatial coordinates throughout--just the spatial length of legs and hypotenuse of a right triangle. You can take any right triangle in normal X-Y space and then use the Pythagorean theorem--then solve for the length of one leg-- followed by a substitution of the imaginary number i in the negative hypotenuse squared term.

Some people object to this derivation claiming that the original diagram is arbitrarily contrived. But this is not the case. It is required if the speed of light is to be the same for all observers. Furthermore it is very general, because for any two observers moving relative to each other, you can always find a rest system that has the two movers going in opposite directions at the same speed.

RedBlue_Pythag-1.jpg
 
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  • #106
Here's an idea: discuss these ideas with Stephen Hawking.
 
  • #107
GrayGhost said:
Hmmm. Well, we've been discussing the length of the spacetime interval as defined under the Minkowski model. OK then, are you suggesting here that imaginaries do not apply wrt clock rates?

Seems to me that you might not understand the meaning of complex systems. I do realize that Einstein did not use imaginaries in his OEMB.
Again, see my post 91. The use of ict is not necessary and is rarely used any more.
 
  • #108
PAllen said:
Colocation is irrelevent. Suppose you are traveling at .99c from start s1 to s2. You send me a picture of yourself at s1, and send me another picture when you get to s2. However long it takes me to get these signals, I will agree on how much aging you will experience (as long as I know the distance from s1 to s1 as I would measure it, and your speed). You will experience the aging I compute. Further, if you know my start and end points as you would measure them, and my speed as you measure it, and compute the invariant interval along my path in these coordinates, you will get the same longer age that I experience. The explanation of why you agree on my invariant interval while still seeing my clock going slow is that you radically disagree on simultaneity. The event on my worldline I say is simultaneous to your passing s1 is not at all what you would say.
This avoids the subject of the OP "which clock is really slower?". Until the clocks are co-located again, you can not in any meaningful (invariant) way say which clock is ticking slower. This is true, whether using Euclidean 4d or Minkowski 4d calculations.
 
  • #109
yuiop said:
This avoids the subject of the OP "which clock is really slower?". Until the clocks are co-located again, you can not in any meaningful (invariant) way say which clock is ticking slower. This is true, whether using Euclidean 4d or Minkowski 4d calculations.

But that wasn't the point of our discussion. Our discussion was around the limitations of trying to explain features of the Minkowski metric using a Euclidean metric. Using each metric where it really applies, you compute invariants that are coordinate independent (and observer independent, where applicable). Using the Euclidean metric in SR you have to be aware that nothing you compute with it is invariant, and you can't use it to compare anything across two arbitrary timelike, physically plausible paths. Meanwhile, the Minkowski metric can be used to compare intervals across arbitrary paths, just like the Euclidean could if it were really applicable.

My example is on point for this. I experience that the time between my bomb detonations is 10 years, and compute and observe that you only age 1 year traveling between s1 and s1 (which are say 8 light years apart, according to me). You experience 1 year going from s1 to s1, and compute that I age 10 years between between my H-bomb detonations. This is what one expect a metric to accomplish, and thus using the Euclidean metric in SR will lead to many confusions and false conclusions.
 
  • #111
Why does one's clock really have to be the one that is slower? Couldn't they both really be slower at the same time from the perspective of each observer?

Without a preferred frame of reference you would think it would force this situation for two observers that have always traveled at a constant speed relative to each other. You couldn't ever say this object is the one that has the true velocity so then how could you say that the others clock is the one that is really slower. Without an absolute frame of reference they both have to be slower at the same time...
 
  • #112
DaleSpam,

Wrt you prior post 91 ... I had assumed that the metric was the result "after having had multiplied by i". That's why I was unaware of any (++++) metric, given I understood it in that way. So when you said the 1st metric is no longer used, you mean that no axes are assumed imaginary in the very first place anymore (on a spacetime diagram), yes?

BobC2,

Indeed, spacetime diagrams show the relative spacetime orientations between observers moving relatively, regardless as to whether the i is used. Yours (of course) points that out nicely. Einstein used no imaginaries in OEMB, so their use by Minkowski was not necessary although mathematically appropriate.

yuiop,

Thanx for your patience here. While I was correct in that you cannot get from (ict)2+(vt)2 to (ct)2+(vt)2 (unless you discard the i's), you indeed CAN get to -(ct)2+(vt)2 or (ct)2-(vt)2 w/o invoking the use of imaginaries. Obviously, since OEMB used no imaginaries. So Minkowski's is nothing more than a different process to do the very same thing...

That said, no imaginaries need be used, as you said. I still contend that the length (ct)2+(vt)2 (per the stationary POV) may well hinder more than aid in expediting understanding of relative aging. Those related points I mentioned prior still stand, IMO. It'd be interesting to see how it turns out if used in classroom. I'm with PAllen on that point though ... it's probably better to adapt to Minkowski's metric than to add complexity using euclidean perspectives with stipulations. Yet at the same time, any inertial perspective in SR is euclidean, so.

GrayGhost
 
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  • #113
John232 said:
Why does one's clock really have to be the one that is slower? Couldn't they both really be slower at the same time from the perspective of each observer?

Without a preferred frame of reference you would think it would force this situation for two observers that have always traveled at a constant speed relative to each other. You couldn't ever say this object is the one that has the true velocity so then how could you say that the others clock is the one that is really slower. Without an absolute frame of reference they both have to be slower at the same time...

Correct. You cannot say which clock is slower, each observes the other clock is slower, and neither is more right than the other. However, each agrees on how much 'physical time' elapses between any two given physical events on any worldline (spacetime path of some observer). They differ on their explanations of this, the key difference being different perceptions of simultaneity.
 
  • #114
bobc2,

I'm curious, how would you apply your method of determining the spacetime interval under the situ per the attached figure, which is not a Loedel figure?

GrayGhost
 

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  • #115
PAllen said:
Correct. You cannot say which clock is slower, each observes the other clock is slower, and neither is more right than the other. However, each agrees on how much 'physical time' elapses between any two given physical events on any worldline (spacetime path of some observer). They differ on their explanations of this, the key difference being different perceptions of simultaneity.

While your response is well stated IMO, and cuts to the chase, I suppose there may be debate over whether moving clocks tick slower "per the inertial observer". I suppose it comes down to "slower wrt what".

GrayGhost
 
  • #116
PAllen said:
Note, it is not so trivial to banish forward and back in time.

I thought it might be interesting to demonstrate a problem that arises if we allow a physical object to travel back in time. Let us say we have two clocks at the origin of an inertial reference frame (S). One clock (A) travels directly to (x,t) coordinates (1,2) at half the speed of light. The other (B) remains at rest in S for 2.5 time units arriving at (0,2.5) and then travels back in time to meet clock A at coords (1,2). Now at coordinate time t=2.25 in S we can see there are two copies of clock B, one at coords (0,2.25) and the other at (0.5,2.25). The same clock exists in two places at the same time and there is possibly a violation of conservation of energy, because we have duplicated the clock. An additional complication is that it is possible to find an observer at rest wrt to a different frame (S') who does not ever see the second copy of clock B, so the cloned version of clock B does not have an observer independent existence.
 
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  • #117
yuiop said:
I thought it might be interesting to demonstrate a problem that arises if we allow a physical object to travel back in time. Let us say we have two clocks at the origin of an inertial reference frame (S). One clock (A) travels directly to (x,t) coordinates (1,2) at half the speed of light. The other (B) remains at rest in S for 3 time units arriving at (0,3) and then travels back in time to meet clock A at coords (1,2). Now at coordinate time t=2.5 in S we can see there are two copies of clock B, one at coords (0,2.5) and the other at (0.5,2.5). The same clock exists in two places at the same time and there is possibly a violation of conservation of energy, because we have duplicated the clock. An additional complication is that it is possible to find an observer at rest wrt to a different frame (S') who does not ever see the second copy of clock A, so the cloned version of clock A does not have an observer independent existence.

I believe this comment of mine was in relation to spacelike paths. And the original comment about timelike curves (that go forward and back in time) was to highlight the confusion that might be possible by thinking in Euclidean terms about spacetime - in Euclidean terms there is no special coordinate associated with a different signature sign, and coordinate paths can freely move back and forth with respect to any coordinate. Introducing a Euclidean metric encourages such confusion.

Of course, I assume you know that GR allows timelike curves that go forward and back in time, and that, so far, no one has clearly demonstrated they can only occur in 'impossible' situations. I have a strong bias against them, but until someone demonstrates a clear impossibility argument, I admit my view is a philosophic bias.
 
  • #118
PAllen said:
Of course, I assume you know that GR allows timelike curves that go forward and back in time, and that, so far, no one has clearly demonstrated they can only occur in 'impossible' situations. I have a strong bias against them, but until someone demonstrates a clear impossibility argument, I admit my view is a philosophic bias.
Me too ... :wink:
 
  • #119
yuiop said:
I thought it might be interesting to demonstrate a problem that arises if we allow a physical object to travel back in time. Let us say we have two clocks at the origin of an inertial reference frame (S). One clock (A) travels directly to (x,t) coordinates (1,2) at half the speed of light. The other (B) remains at rest in S for 3 time units arriving at (0,3) and then travels back in time to meet clock A at coords (1,2). Now at coordinate time t=2.5 in S we can see there are two copies of clock B, one at coords (0,2.5) and the other at (0.5,2.5). The same clock exists in two places at the same time and there is possibly a violation of conservation of energy, because we have duplicated the clock. An additional complication is that it is possible to find an observer at rest wrt to a different frame (S') who does not ever see the second copy of clock A, so the cloned version of clock A does not have an observer independent existence.

yuiop,

I'd throw a few comments your way, but I fear DaleSpam would cry metaphysical foul. I'll just sit back and process the exchange, which I find "interesting enough".

EDIT: Looks like PAllen's response beat mine. Indeed, no one can travel back in time (per himself) per the theory.

GrayGhost
 
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  • #120
PAllen said:
Of course, I assume you know that GR allows timelike curves that go forward and back in time, and that, so far, no one has clearly demonstrated they can only occur in 'impossible' situations. I have a strong bias against them, but until someone demonstrates a clear impossibility argument, I admit my view is a philosophic bias.

Outside of falling into a rotating black hole, how else could you travel thru time if c is a speed limit? If one falls into a black hole, isn't it true that one would never survive the gravitational gradient during the free fall? What situ in GR would allow for a successful "time travel" in theory?

GrayGhost
 

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