Converting a Linear Equation to Polar Form: Dealing with Constant Terms

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SUMMARY

The discussion focuses on converting the linear equation 2x + 3y = 4 into polar form. The correct transformation involves substituting x and y with their polar equivalents, resulting in the equation 2r cos(θ) + 3r sin(θ) = 4. This simplifies to r(2 cos(θ) + 3 sin(θ)) = 4, leading to the final polar form r = 4 / (2 cos(θ) + 3 sin(θ)). The confusion arose from handling the constant term, which is clarified through the proper application of polar coordinates.

PREREQUISITES
  • Understanding of polar coordinates and their relationship to Cartesian coordinates.
  • Familiarity with trigonometric functions, specifically sine and cosine.
  • Basic algebraic manipulation skills, particularly with equations.
  • Knowledge of linear equations and their graphical representations.
NEXT STEPS
  • Study the derivation of polar coordinates from Cartesian coordinates.
  • Learn about the applications of polar equations in graphing and analysis.
  • Explore trigonometric identities and their use in simplifying equations.
  • Investigate common pitfalls in converting between coordinate systems.
USEFUL FOR

Students in mathematics, educators teaching coordinate geometry, and anyone interested in understanding the conversion between Cartesian and polar forms of equations.

iggybaseball
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How would I change: 2x+3y=4
into polar form? I understand how to solve for polar form but the 4 without a variable is confusing me.
 
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2 r cos \theta + 3 r sin \theta = 4
r(2 cos \theta + 3 sin \theta) = 4
2 cos \theta + 3 sin \theta = 4/r
\frac{4}{2 cos \theta + 3 sin \theta} = r

whats wrong with that?
 
Thank you I feel ashamed that such a simple problem stumped me. I was thinking to hard lol. Thanks again
 

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