Can the Energy of a Photon be Expressed in h/s?

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SUMMARY

The discussion centers on the expression of photon energy in terms of Planck's constant (h) and its units. Participants clarify that while energy (E) is expressed in joules (J) or electronvolts (eV), Planck's constant (h) is a physical constant with units of J·s. The confusion arises from attempts to express energy in terms of h/s, which is deemed incorrect as it mixes a constant with a unit. The correct relationship is established as E = hf, where frequency (f) is in hertz (Hz), leading to energy being expressed in joules.

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  • Understanding of Planck's constant (h ≈ 6.626×10-34 J·s)
  • Knowledge of energy units (joules and electronvolts)
  • Familiarity with frequency and its unit (hertz)
  • Basic grasp of dimensional analysis in physics
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  • Study the relationship between energy and frequency using E = hf
  • Explore dimensional analysis in physics to avoid unit confusion
  • Learn about the significance of Planck's constant in quantum mechanics
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Students and professionals in physics, particularly those focusing on quantum mechanics, energy calculations, and dimensional analysis. This discussion is beneficial for anyone seeking clarity on the relationship between energy, frequency, and Planck's constant.

bobie
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Hi,

Energy is expressed in J or eV, but E= hf
As Planck constant h is J.s is it possible to express the energy of a photon in h/s? If not, why?
Can we say that the energy of a photon is 2.41 x 10^14 h/s?
 
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If h = Js, then J = h/s, and you can express E in joules, so it appears to me that you are already using h/s.
 
Naty1 said:
Your proposal is missing a unit of measure.

What unit is missing?
A photon with frequency 2.418 x 10^14 Hz has E = 1 eV, is that correct?
h = 4.135 x 10 ^-15 eV.s , h/s = 4,135 x 10^-15 eV (from your link)
( 2.318x 10^14 x) h/s = (2.428x10^14 x) 4.135 x 10^-15 eV
2.318x 10^14 x h/s = 1
A photon with frequency 2.418 x 10^14 Hz has E = 2.418 x 10^14 h/s

Where do I go wrong?
 
Can we say that the energy of a photon is 2.41 x 10^14 h/s?

'h' is a constant, right?

What does 's' mean in your equation?? Please explain.
 
bobie said:
Can we say that the energy of a photon is 2.41 x 10^14 h/s?

Be careful here, you are mixing a constant (h) and a unit (s) in the same unit expression, which is very unusual and should be avoided IMO.

You obviously mean

h: Planck's constant ≈ 6.626×10−34 J·s (joules times seconds)
s: seconds

but h as a unit usually mean hour. The usual unit - the SI unit - of energy is the joule (J), not any h/s. There are also some other units of energy like the electronvolt (eV).

Hmm... I'm wondering if someone will give me a prize for using the most wikipedia links in one and the same short post...?
 
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Thank you all,
If I got it right, h = J.s cannot be modified to h/s =J.
But I read that the Hz is equivalent to 1/s, then in the formula E= h.f => E = h. 1[]/s = aren't we mixing a constant with a unit?
 
For clarity's sake let's use brackets when we mean units, and remember to not mix the bracketed bits with unbracketed ones.

f=1/T not [1/s]
[1/s] is the unit of f

So, E=hf and the units are h=[J*s] and f=[Hz]=[1/s]

Then E=[J*s*Hz]=[J*s/s]=[J]
 
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Thanks, if h/s is forbidden, how can we express that the scalar of the frequency is always equal to the scalar of the energy of a photon?
 
  • #10
Not sure what you mean. Energy equals frequency of the wave times the Planck constant E=hf. These are all scalar quantities.
You can substitute 1/T for f if you like, to get E=h/T, where T is the period of the wave.
 
  • #11
Bandersnatch said:
You can substitute 1/T for f if you like, to get E=h/T, where T is the period of the wave.

So , what is the E of a photon with frequency 2.418x 10^14 wxpressed in h/T?
 
  • #12
It's the same as with the energy expressed as hf. The energy of the photon does not change just because you use some arithmetic to rearrange the equation. h/T is, after all, equal to hf in both value and units.

f=2.418*10^14 [Hz]

E=fh=2.418*10^14 [Hz]*6.626×10^-34 [J*s]=~16*10^-20 [J]

T=1/f
T=1/(2.418*10^14) [1/Hz]
T=~0.41*10^-14

E=h/T=6.626×10^-34 [J*s]/0.41*10-14 =~16*10^-20 [J]
 
  • #13
Just came back...
bobie,
my post #5 was an attempt to get you to see for yourself the difference between a measure, such as a frequency, f, and the unit utilized to express it, such a cycles per second.
I think that's what the prior posters are explaining,too.

If you write out the UNITS associated with any measure, any formula, you will see whether you have consistency:

for example distance equals velocity times time, right?? :
a distance = ft/sec x seconds = ft and that makes 'sense'...the seconds cancel...if you have instead a measure of speed such as [50] miles/hour x [25] seconds your units become mile-second/ hours...not a standard set of units...so much better to convert the right hand side to either hours, seconds, or whatever...


Note also the unit 'Hertz' [and seconds] has some confusion associated with it:

http://en.wikipedia.org/wiki/Cycle_per_second

[I wasn't even aware of this supposed confusion til I just checked. ]
 
  • #14
bobie said:
how can we express that the scalar of the frequency is always equal to the scalar of the energy of a photon?

We could define a new unit of energy: 1 bobie = 4.135 x 10-15 eV = 6.626 x 10-34 J. Give it the symbol 'B'. (Or is there another unit with that symbol? I forget...)

Then Planck's constant would be 1 B.s, and a photon with frequency 2.418 x 1014 Hz would have an energy of 2.418 x 1014 B.
 
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  • #15
jtbell said:
We could define a new unit of energy: 1 bobie = 4.135 x 10-15 eV = 6.626 x 10-34 J. Give it the symbol 'B'. (Or is there another unit with that symbol? I forget...)

Then Planck's constant would be 1 B.s, and a photon with frequency 2.418 x 1014 Hz would have an energy of 2.418 x 1014 B.
Congrats, jtbell, you hit the nail on the very head!, thanks.
That's exactly what I meant without aspiring to have a unit named after me.:redface:, that would make patent the relation of energy to a single oscillation (I posed a similar problem here :https://www.physicsforums.com/showthread.php?t=712514 , it seemed to me that dimensions prevent seeing the forest because of the trees. There I discovered geometrized units and that dimensions are not indispensable).
I have little (or no) experience and I still cannot see the subtle difference between 1B and 1 h/s.

Actually I cannot even grasp what a unit of energy can actually mean when multiplied by time.
I understand that power (J/s ) is energy absorbed every second but J.s would correspond to distance ( as compared to velocity, right)?
 
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  • #16
J.s is the unit for action (and also angular momentum).
 
  • #17
dauto said:
J.s is the unit for action (and also angular momentum).
Can 2 different entities have the same dimensions?, what has h in common with angular momentum?

...if h indeed is a unit then it can be mixed with other units and we can use h/s?
 
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  • #18
Stop it right now, mister! Stop saying that h is a unit, or I'm going to reach through the screen and give you a good spanking!
It is most emphatically not. Nobody has ever said that. It's a constant and it's units are J*s.

h/s is mixing constants with units.
Write J*s/s if you must, although it's obviously just J, if you want to write units. Or write h/T if you want equations. Don't write h/s. It's like writing a=V/s or F=kg*a.
 
  • #19
Bandersnatch said:
Stop saying that h is a unit, ...Nobody has ever said that
Why do you blame, me, bandersnatch,did you see that I was simply quoting Mr dauto:confused:, ?
how can I possibly know who is right or wrong?
 
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  • #20
Where, oh, where did he say h is a unit? All he said is that J*s is a unit.
 
  • #21
Bandersnatch said:
Where, oh, where did he say h is a unit? All he said is that J*s is a unit.
Sorry, if I misunderstood, but I thought that h=J.s? wiki:
h = 1.054571726(47)×10−34 J·s
. Can two different units have same dimensions?
 
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  • #22
bobie said:
Why do you blame, me, bandersnatch,did you see that I was simply quoting Mr dauto:confused:, ?
how can I possibly know who is right or wrong?

You were not quoting dauto. Dauto said:

dauto said:
J.s is the unit for action (and also angular momentum).

which only was about the unit [Js]. But you said:

bobie said:
...if h indeed is a unit then it can be mixed with other units and we can use h/s?

No, please read my post #6 again. Planck's constant (h) is not a unit, it is a physical constant (which is a physical quantity).

It seems to me that you don't understand the difference between a quantity and a unit. I think the posters in this thread have tried to explain this in various ways. But I will try to visualize it in this basic way:

Planck's constant is (full expression)

h ≈ 6.62606957 × 10−34 Js

h is a quantity (a constant)
6.62606957 × 10−34 is the value
Js is the unit (joules times seconds)

Is this clear? Do you understand that h is not a unit in itself, and therefore it should not be a part of a unit expression?
 
  • #23
DennisN said:
h is a quantity (a constant)
6.62606957 × 10−34 is the value
Js is the unit (joules times seconds)

Is this clear? Do you understand that h is not a unit in itself, and therefore it should not be a part of a unit expression?
Thanks for your patience, I'll try to make myself clear.
T time is not a unit, is a dimension , sec is its unit
Length is not a unit , cm is its unit...
is that right?
if h is only a constant, a quantity , a value, therefore a dimensioneless number, why is it always associated to units such as J.s, dimensions?
α is the fine structure constant and is just a quantity 0.007... but is never associated to units

That :confused: is what I do not understand, when I think of h I think of α, where do I go wrong?
 
  • #24
bobie said:
Thanks for your patience, I'll try to make myself clear.
Excellent, no problem! :smile: I think we are going somewhere now:

bobie said:
T time is not a unit, is a dimension , sec is its unit
Yes.

bobie said:
Length is not a unit , cm is its unit...
Yes (though normally the unit is m (meter)).

bobie said:
is that right?
Yes!

bobie said:
if h is only a constant, a quantity , a value, therefore a dimensioneless number, why is it always associated to units such as J.s, dimensions?

This is where you go wrong (my bolding in your quote). h is not dimensionless;

Planck's constant is (full expression) h ≈ 6.62606957 × 10−34 Js

h is a quantity (a constant)
6.62606957 × 10−34 is the value
Js is the unit (joules times seconds)

A dimensionless quantity is a quantity without a unit. But the unit of h is Js, so h is not dimensionless.
 
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  • #25
DennisN said:
h ≈ 6.62606957 × 10−34 Js
So, if I got it right some constants are dimensioneless and some have units. And we have to create a new unit B to express what I meant by h/s. What would then be the relation of h to B?

Moreover, you have used a new sign, and that makes more sense even if I do not know its properties: what fooled me is that wki has
h = ...J * s
and I am naive enough to think that you can always move around entities from left to right.
But the main problem remains that I have no clue what energy multiplied by time can represent.
 
  • #26
bobie, have a look at this book:
http://old.iupac.org/publications/books/gbook/green_book_2ed.pdf

It's very informative, and an easy read. Chapter 1 covers the basic definitions and ideas behind quantity calculus. There's also a lot of tables explaining various relationships, derivations and definitions. It has probably all you'll ever need to know about units.
 
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  • #27
Thanks, that is very helpful indeed
 
  • #28
bobie said:
So, if I got it right some constants are dimensioneless and some have units.
Correct! :smile:

bobie said:
Moreover, you have used a new sign, and that makes more sense even if I do not know its properties: [...]

Sorry if I confused you, I am accustomed to use ≈ (which means approximately equal to) to emphasize that the value is not exact. The value of Planck's constant (h) is not exactly known down to an arbitrary number of digits.

bobie said:
what fooled me is that wki has
h = ...J * s

Wiki says

h = 6.62606957(29)×10−34 Js

which also is ok since the two digits inside the parentheses denote the standard uncertainty in the last two digits of the value (link), which also indicates that the value is not exact.
 
  • #29
DennisN said:
So, if I got it right some constants are dimensioneless and some have units
.
Correct! :smile:
Could you give me some examples of constants with units so that I can get in the picture?
 
  • #30
bobie said:
Could you give me some examples of constants with units so that I can get in the picture?
In the book I linked you to, go to chapter five, or here, or http://www.ligo.caltech.edu/~vsanni/ph3/ToolsTables/NISTPhysicalConstants.pdf. You'll notice that nearly all of them have units.
 

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