Can anyone Explain why a glass tips over when pushed from the top?

AI Thread Summary
A glass with a height of 10 cm and a diameter of 2 cm weighs 300g and has a coefficient of friction of 0.30. The discussion centers on whether the glass will slip or tip when pushed from the top. It is noted that pushing higher on the glass increases the torque exerted, making it more likely to tip rather than slip. The tipping occurs when the torque from the applied force exceeds the torque due to gravity. Ultimately, the balance between the applied force and static friction determines the glass's behavior when pushed.
linuxux
Messages
133
Reaction score
0

Homework Statement



A glass has a height of 10 cm, and a diameter of 2 cm, it weight 300g and a coefficient of friction equal to .30 exists. Will it slip or tip?

Homework Equations



?

The Attempt at a Solution



Im almost certain there are no calculations informed since i have been hard pressed to find equations relating height and friction. But i did test this theory my self on a glass and it did tip. Is the reason it tips because the farther away you are from the base, the more perpendicular is the applied force in respect to the base, because is you push from the bottom of the glass all the force is against the friction. Is this right?
 
Physics news on Phys.org
linuxux said:
Is the reason it tips because the farther away you are from the base, the more perpendicular is the applied force in respect to the base, because is you push from the bottom of the glass all the force is against the friction. Is this right?
It's certainly true that the higher up the force is applied, the more torque it exerts. Whether it tips or not depends on whether the applied torque is greater than the torque due to gravity.

Assume for the moment that the glass doesn't slip. What applied force is required to overcome gravity? Would a force of that magnitude be enough to overcome static friction?
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Maximum height a waitress can push on a glass without it tipping
Replies
5
Views
5K
Maximizing Fridge Stability: Determining the Optimal Height for Pushing Force
Replies
3
Views
2K
Will the Lamp Slide or Tip When Pushed?
Replies
1
Views
7K
Frictional Torque of a Spinning Top
Replies
6
Views
3K
Can a 500g Glass of Water Tip or Slip?
Replies
2
Views
9K
Will the Block Tip Over or Slip on an Incline?
Replies
2
Views
3K
Statics Friction problem -- A 500lb box is being pushed up a ramp
Replies
2
Views
2K
Rectangular box tips over (or not)
Replies
1
Views
3K
Critical angle (torque) at which the block tips over
Replies
12
Views
6K
Calculating Torque for Tipping a Block: How Can I Determine the Required Force?
Replies
6
Views
15K

Hot Threads

Recent Insights

Back
Top