Can anyone Explain why a glass tips over when pushed from the top?

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A glass with a height of 10 cm and a diameter of 2 cm weighs 300g and has a coefficient of friction of 0.30. The discussion centers on whether the glass will slip or tip when pushed from the top. It is noted that pushing higher on the glass increases the torque exerted, making it more likely to tip rather than slip. The tipping occurs when the torque from the applied force exceeds the torque due to gravity. Ultimately, the balance between the applied force and static friction determines the glass's behavior when pushed.
linuxux
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Homework Statement



A glass has a height of 10 cm, and a diameter of 2 cm, it weight 300g and a coefficient of friction equal to .30 exists. Will it slip or tip?

Homework Equations



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The Attempt at a Solution



Im almost certain there are no calculations informed since i have been hard pressed to find equations relating height and friction. But i did test this theory my self on a glass and it did tip. Is the reason it tips because the farther away you are from the base, the more perpendicular is the applied force in respect to the base, because is you push from the bottom of the glass all the force is against the friction. Is this right?
 
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linuxux said:
Is the reason it tips because the farther away you are from the base, the more perpendicular is the applied force in respect to the base, because is you push from the bottom of the glass all the force is against the friction. Is this right?
It's certainly true that the higher up the force is applied, the more torque it exerts. Whether it tips or not depends on whether the applied torque is greater than the torque due to gravity.

Assume for the moment that the glass doesn't slip. What applied force is required to overcome gravity? Would a force of that magnitude be enough to overcome static friction?
 
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