Deriving Coulomb's Law with Virtual Photon Exchange Theory: Complete Explanation

[sharma_satdev]

How the virtual photon exchange theory be used to derive completely Coulombs Law related to electrostatic field? Complete derivation means derivation involving charges and distance

 

[torquil]

http://www.scribd.com/doc/70796478/97/The-Coulomb-Potential

 

[tom.stoer]

You don't need any virtual photons but you can derive Coulombs law w/o using perturbation theory. It's most transparent in
a) Coulomb gauge or in
b) A°=0 gauge plus fixing of the residual symmetry of time-independent transformations respecting A°=0.

In both cases it boils down to construct the inverse of the Laplacian 1/Δ; in Coulomb gauge this is due to the Poisson equation

\Delta A^0 = \rho

with

\Delta^{-1} \to k^{-2}

in k-space and

\Delta^{-1} \to |x|^{-1}

in x-space

This results in an interaction term

V \sim \int d^3x\,d^3y\,\frac{\rho(x)\,\rho(y)}{|x-y|}

Of course there are other interaction terms involving physical (transversal) photons as well.