Force from a Kinetic Energy Function

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SUMMARY

To derive force from a kinetic energy function, one must utilize the principles of conservation of energy and the work-energy relation. The force F(x) in a conservative field is defined as the negative gradient of the potential energy function U, rather than directly from kinetic energy. Additional information beyond kinetic energy and position is often required to fully determine the force acting on an object. This discussion emphasizes the importance of understanding the relationship between kinetic energy and potential energy in physics.

PREREQUISITES
  • Understanding of kinetic energy functions
  • Knowledge of potential energy and conservative forces
  • Familiarity with the work-energy theorem
  • Basic calculus for differentiation
NEXT STEPS
  • Study the relationship between kinetic energy and potential energy in conservative systems
  • Learn about the work-energy theorem in detail
  • Explore the concept of gradients in physics
  • Investigate examples of force derivation from energy functions
USEFUL FOR

Students of physics, educators teaching mechanics, and anyone interested in the mathematical relationships between energy and force in conservative fields.

Dustinc
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Say you're given a function that represents the kinetic energy of some object, what would you have to do to derive the force from that function? I know that for motion along a straight line a conservative force F(x) is the negative derivative of its associated potential energy function U, but what is there to do if the function is one of kinetic energy?
 
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Conservation of energy and the work-energy relation will be useful in such cases.
You usually will need more information than kinetic energy with position alone.
Do you have an example.

Note: For a conservative field, the force on an object at a position is the negative gradient of the potential energy function at that position. Motion does not have to be along a straight line.
 
You posted this same thing in the homework section. :confused:
I mean the OP, of course.
 
Ok, now we have an infinite loop. :smile:
I can go forever between the two threads, by using your links.
 

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