What is the metric (distance function) on the 1-sphere and 2-sphere?

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The distance function on the 1-sphere (S1) is defined using the round metric as g = dθ², where θ represents the angle in radians. For the 2-sphere (S2), the metric is given by g = sin²(θ)dφ² + dθ², incorporating spherical coordinates. The parametric equations for the 1-sphere are x = cos(θ) and y = sin(θ), leading to the calculation of the distance element ds² = dθ². For the 2-sphere, the coordinates are defined as x = cos(θ)sin(φ), y = sin(θ)sin(φ), and z = cos(φ), with the corresponding differential expressions for dx, dy, and dz. The discussion emphasizes the application of the Jacobian matrix for deriving the metric on these manifolds.
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Hi i only know the distance function in euclidean space as the standard definition involving the sqrt of the dot product of the vector connecting two points.

What is the metric (distance function) in S1 or S2 which is the 1 sphere and 2sphere respectively.
 
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The round metric for the unit 1-sphere is (using radians), \mathbf{g} = d\theta^2, and for the unit 2-sphere, \mathbf{g} = \sin^2\theta\,d\phi^2 + d\theta^2, I think, working off of memory. It should be simple to add in the r term for arbitrary euclidean 1 and 2-spheres

In general, if J is the jacobian matrix of the manifold:
\mathbf{g} = J^T J
 
That's right. The 1-sphere (unit circle for us pedestrians) has parametric equations x= cos(\theta), y= sin(\theta) so that dx= -sin(\theta)d\theta and dy= cos(\theta) so that ds^2= dx^2+ dy^2= (sin^2(\theta)+ cos^2(\theta))d\theta^2= d\theta^2.

For the 2-sphere (the surface of the unit sphere), we can take x= cos(\theta)sin(\phi), y= sin(\theta)sin(\phi), z= cos(\phi) (spherical coordinates with \rho= 1). Then dx= -sin(\theta)sin(\phi)+ cos(\theta)cos(\phi), dy= cos(\theta)sin(\phi)+ sin(\theta)cos(\phi), and dz= -sin(\phi)d\phi.

dx^2= sin^2(\theta)sin^2(\phi)d\theta^2- 2sin(\theta)cos(\theta)sin(\phi)cos(\phi)d\theta d\phi+ cos^2(\theta)cos^2(\phi)d\phi^2
 

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