Answer: Calculate the Value of sin inverse (2)

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Homework Help Overview

The problem involves finding the value of sin inverse (2), which raises questions about the validity of the input within the context of the arcsine function's domain.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss whether sin inverse (2) is a real value and question the domain of the arcsine function. Some explore the implications of assuming a solution exists, while others mention hyperbolic functions as a potential avenue for exploration.

Discussion Status

The discussion is ongoing, with participants sharing hints and insights related to complex numbers and hyperbolic functions. There is a recognition of differing levels of familiarity with the material, and some express frustration over the exam content not aligning with their coursework.

Contextual Notes

Participants note a lack of coverage of hyperbolic functions in their course materials, raising concerns about the fairness of the exam question. There is also mention of varying teaching standards across institutions within the same university.

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Homework Statement



Find the value of sin inverse (2 ) ?

Homework Equations





The Attempt at a Solution



This was a question in my final exam & i had no clue about it
 
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is it a real value? what is the domain of the ArcSin function?
 
No extra information was given
 
Suppose such a value, k, exists, so that [tex]\arcsin 2 = k[/tex]. Then taking sines of both sides, [tex]sin (k) = 2[/tex]. However, the sine function is bounded between -1 and 1 for all real numbers. Hence there is no real solution.
 
… hyperbolic sines … !

mkbh_10 said:
Find the value of sin inverse (2 ) ?

This was a question in my final exam & i had no clue about it

Hi mkbh_10! Hope you passed! :smile:

Hint: cosh ix = cosx, and sinh ix = isinx.

(that's why sinh is called the hyperbolic sin!)

So sin(x + iy) = sinx cos iy + cosx sin iy = sinx coshy - i cosx sinhy;

so you needed cosx = 0, and … ? :smile:
 
tiny-tim said:
Hi mkbh_10! Hope you passed! :smile:

Hint: cosh ix = cosx, and sinh ix = isinx.

(that's why sinh is called the hyperbolic sin!)

So sin(x + iy) = sinx cos iy + cosx sin iy = sinx coshy - i cosx sinhy;

so you needed cosx = 0, and … ? :smile:




But there is no hyperbolic sine function in the question ?

I am studying in DU (Delhi University ) so results will only be out in mid July . I will definitely pass but i want top marks which i will not be getting in this paper coz of my silly mistakes .
 
What course is this for? That's important. If you are studying complex numbers in the course, then there is a solution, if not, there is no solution.

And just because there is no "hyperbolic sine" in the problem doesn't mean you can't use one to solve it.
 
i have not found it anywhere in my course , that's why i am asking , i didn't study this type of question neither did our teacher taught nor does the book has this type of questions
 
i have studied complex numbers but i have no clue about it
 
  • #10
… really unfair … !

mkbh_10 said:
i have not found it anywhere in my course , that's why i am asking , i didn't study this type of question neither did our teacher taught nor does the book has this type of questions

That's really unfair! :mad:

(even if you've done things like log(-1) and log(i), sin(ix) isn't obvious, and should have been pointed out to you, IMO)

(Check the official syllabus, to see if it's on it … if it's not, complain about the exam … if it is, check with your fellow students, and make a joint request for credit for that question … will your student union help you with that?)

(btw, sin (π/2 - isinh^(-1)2) = 2)
 
  • #11
this is india, nothing happens at student level , & there are 30-40 clgs in DU that have this course & who knows what teacher teaches in a particular topic
 
  • #12
mkbh_10 said:
this is india, nothing happens at student level , & there are 30-40 clgs in DU that have this course & who knows what teacher teaches in a particular topic

share your pain bro.. share your pain.
 

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