Exact Value of Sin 65 Degrees: Trigonometry Identities for Finding the Solution

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Homework Help Overview

The discussion revolves around finding the exact value of sin 65 degrees, utilizing trigonometric identities and algebraic manipulation.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss using the identity sin(3x) = 3 sin(x) - 4 sin³(x) but encounter complex algebraic challenges. There is mention of exploring the value of sin(10 degrees) as a potential starting point.

Discussion Status

Some participants have suggested alternative approaches, including the possibility of using established formulas for analytic solutions. There is a reference to a resource that lists exact formulas for sine values of angles in 1-degree increments, indicating ongoing exploration of methods.

Contextual Notes

Participants express difficulty in solving the resulting equations and question the effectiveness of their chosen methods. There is no explicit consensus on a single approach or solution at this time.

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Homework Statement


Find the exact value of sin 65o

Homework Equations


Trigonometry Identities

The Attempt at a Solution


I tried using sin 3x = 3 sin x - 4 sin3x but ended with nasty algebra.

sin (3 . 65o) = 3 sin 65 - 4 sin3 65o
sin (195o) = 3 sin 65 - 4 sin3 65o
sin (180o+15o) = 3 sin 65 - 4 sin3 65o
- sin (15o) = 3 sin 65 - 4 sin3 65o ; let sin 65o = x
(√2 - √6) / 4 = 3x - 4x3

Can't solve for x

Thanks
 
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There is a formula for analytic solutions for the last equation. Using that is probably easier than finding different trigonometric identities.

You could try to establish a value for sin(10o) first I guess.
 
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songoku said:

Homework Statement


Find the exact value of sin 65o

Homework Equations


Trigonometry Identities

The Attempt at a Solution


I tried using sin 3x = 3 sin x - 4 sin3x but ended with nasty algebra.

sin (3 . 65o) = 3 sin 65 - 4 sin3 65o
sin (195o) = 3 sin 65 - 4 sin3 65o
sin (180o+15o) = 3 sin 65 - 4 sin3 65o
- sin (15o) = 3 sin 65 - 4 sin3 65o ; let sin 65o = x
(√2 - √6) / 4 = 3x - 4x3

Can't solve for x

Thanks

Somebody has published (on the internet) a list of exact formulas involving roots and the like, for the sine function for all angles in 1 degree increments from 1 degree to 90 degrees. The work includes proofs of all the results. (It was done as a retirement project by an ex-professor of mathematics.) For more details, see

http://www.intmath.com/blog/mathematics/how-do-you-find-exact-values-for-the-sine-of-all-angles-6212
 
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Thanks for all the help
 

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