Frequency shift of light between observers in Schwarzschild space-time

Click For Summary
SUMMARY

The discussion focuses on the frequency shift of light between two observers, O1 and O2, in Schwarzschild space-time, specifically at positions r=r1 and r=r2. The ratio of frequencies is derived using the equation \(\frac{\nu_1}{\nu_2} = \frac{(g_{mn}u^m k^n)_1}{(g_{mn}u^m k^n)_2}\), where \(u^m\) represents the 4-velocities of the observers and \(k^n\) is a null vector along the photon trajectory. The components of the null vector are determined, leading to a generalization of the gravitational frequency shift formula, which aligns with special relativity when the mass \(M\) approaches zero. The findings reference Stephani's 'General Relativity' (1993) for foundational concepts.

PREREQUISITES
  • Understanding of Schwarzschild space-time
  • Familiarity with 4-vectors and geodesic conditions
  • Knowledge of gravitational frequency shift concepts
  • Basic principles of general relativity as outlined in Stephani's 'General Relativity'
NEXT STEPS
  • Explore the implications of gravitational frequency shift in astrophysical contexts
  • Study the derivation of null vectors in curved space-time
  • Investigate the relationship between general relativity and special relativity
  • Review advanced topics in geometric optics related to general relativity
USEFUL FOR

Physicists, astrophysicists, and students of general relativity seeking to deepen their understanding of light behavior in gravitational fields and the mathematical frameworks that describe these phenomena.

Mentz114
Messages
5,429
Reaction score
292
Considering the simple case of two observers O1 and O2 lying on the same radius at positions r=r1 and r=r2 respectively.

Using a result from Stephani(1) I work out that the ratio of frequencies of light sent radially between these observers is given by this ratio, numerator and denominator evaluated at the points r=r1 and r=r2 respectively,

\frac{\nu_1}{\nu_2} = \frac{(g_{mn}u^m k^n)_1}{(g_{mn}u^m k^n)_2} -------- (1)

where u(i)n is the 4-velocity of O1 and O2 and kn is a null vector defined by the photon trajectory ( up to a constant which will cancel out) so that

k_{m;n}k^n = 0 --------- (2)

which is the geodesic condition for a (transverse ?) plane wave.

We need to find the null vector kn. Because only k0 and k1 are non-zero for a radial photon it is not difficult to solve for k from equation (2), up to a factor, which is all we need. I got the components of kn,

\left(1 - \frac{2M}{r}\right)^{-\frac{1}{2}}, \left(1 - \frac{2M}{r}\right)^{\frac{1}{2}}, 0, 0

which satisfy equ (1) and also gmnkmkn = 0.

Now we can calculate (g_{mn}u^m k^n)_i which gives,

(g_{mn}u^m k^n)_i = u_i^1\left(1-\frac{2M}{r_i}\right)^{-\frac{1}{2}} - u_i^0\left(1-\frac{2M}{r_i}\right)^{\frac{1}{2}}.

Which looks as if it could be right. If the observers are at rest wrt to each other, then we can write ui0 = 1 and ui1 = 0, which reduces equation (1) to the usual gravitational frequency shift.

For u to be a proper 4-vector gmnumun = 1 ( speed of light), so it should be possible to generalise this result a bit more.

If it's correct. This must have been worked out somewhere.



(1) 'General Relativity', Stephani, (Cambridge, 1993).
 
Physics news on Phys.org
I haven't had much time for this and resources on the web for geometric optics seem limited. I did notice that my formula derived above,

(g_{mn}u^m k^n)_i = u_i^1\left(1-\frac{2M}{r_i}\right)^{-\frac{1}{2}} - u_i^0\left(1-\frac{2M}{r_i}\right)^{\frac{1}{2}}

gives the correct SR result for M=0, namely

g_{mn}u^m k^n = u^1 - u^0 = \gamma\beta - \gamma = \gamma(\beta - 1).

The sign is different, but that disappears when we take the ratio.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 26 ·
Replies
26
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 1 ·
Replies
1
Views
949
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 30 ·
2
Replies
30
Views
5K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K