Understanding the Orbit of Kapler's Law and its Relation to Potential Energy

  • Thread starter Thread starter Cosmossos
  • Start date Start date
  • Tags Tags
    Orbits
Cosmossos
Messages
100
Reaction score
0
Hello,
In question 3(b) in the following file
http://phstudy.technion.ac.il/~wn114101/hw/wn2010_hw09.pdf

Why the orbit will be a straight line?
I think that when the particles are coming to r=0 the potential will be infinity, isn't that so?
So the energy will be infinity and e will be infinity... please help me...
thank you

AND ONE MORE THING: if the potential is a/r^2 (>0) then then the two objects will attract each other, right? But in the Gravitational law (-Gm1m2/r^2) the potential is <0 and the objects will attract to each other
 
Last edited by a moderator:
Physics news on Phys.org
Cosmossos said:
Hello,
In question 3(b) in the following file
http://phstudy.technion.ac.il/~wn114101/hw/wn2010_hw09.pdf

Why the orbit will be a straight line?
The problem statement explicitly states the particles move "on the x direction" and "on the y direction". Presumably they mean on the x and y axes; it is not worded quite properly but I can't imagine it meaning anything else.

So, each particle moves in straight line simply because the problem statement says that they do. What would actually cause this to happen is not important.

I think that when the particles are coming to r=0 the potential will be infinity, isn't that so?
No, it would be negative infinity in this example.
 
Last edited by a moderator:
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
Back
Top