Why Is the Inverse Function Theorem by Spivak Difficult to Follow?

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SUMMARY

The discussion centers on the challenges faced in understanding the proof of the Inverse Function Theorem (IFT) as presented by Michael Spivak. The theorem's statement indicates that if the theorem holds for the composition of the inverse function and another function, it also holds for the original function, allowing the assumption that the inverse function is the identity. The proof involves applying the chain rule to the derivative of the composition of functions, leading to the conclusion that the derivative of the inverse function can be expressed as the inverse of the derivative of the original function. This approach is applicable to both single-valued and multivariable functions.

PREREQUISITES
  • Understanding of the Inverse Function Theorem
  • Familiarity with derivatives and the chain rule
  • Knowledge of vector-valued functions
  • Basic concepts of multivariable calculus
NEXT STEPS
  • Study the proof of the Inverse Function Theorem in Spivak's "Calculus on Manifolds"
  • Learn about the application of the chain rule in multivariable calculus
  • Explore the properties of single-valued and multivariable functions
  • Investigate examples of the Inverse Function Theorem in practical scenarios
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Mathematics students, educators, and anyone studying advanced calculus or differential geometry who seeks to deepen their understanding of the Inverse Function Theorem and its applications.

tjkubo
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I'm having trouble following the proof of the IFT by Spivak. The statement of the theorem was posted in a similar thread:
https://www.physicsforums.com/showthread.php?t=319924

He says, "If the theorem is true for \lambda^{-1} \circ f, it is clearly true for f. Therefore we may assume at the outset that \lambda is the identity."

These statements are not clear to me, so if anyone can provide a little more explanation, that would be helpful.
 
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I'm not sure I follow the chain of reasoning from the thread. But the basic proof is straightforward.

Apply the chain rule to the derivative (w.r.t. y) of [f\circ f^{-1}](\mathbf{y})=\mathbf{y}
you get:
[Df]\circ f(\mathbf{y})\cdot Df^{-1}(\mathbf{y}) = \mathbf{1}
thence
Df^{-1}(\mathbf{y}) = [Df(f^{-1}(\mathbf{y}))]^{-1}

This works for single valued functions and for functions of many variables (treated as a vector valued function of a vector.)
 

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