Diffraction grating angular separation

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SUMMARY

The discussion focuses on deriving the angular separation of two wavelengths, L and L+dL, incident on a diffraction grating with slit separation D. The correct formula for angular separation in the m'th order is established as dTheta = dL / sqrt((D/m)² + L²). The initial attempt at the solution incorrectly simplified the sine function, leading to an erroneous expression for dTheta. The clarification emphasizes that for small angles, sin(Theta) approximates Theta in radians, which is crucial for accurate calculations.

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  • Understanding of diffraction grating principles
  • Familiarity with the sine function and small angle approximations
  • Knowledge of angular measurements in radians
  • Basic algebra for manipulating equations
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  • Study the derivation of the diffraction grating equation D sin(Theta) = mL
  • Learn about small angle approximations in trigonometry
  • Explore the implications of wavelength separation in optical systems
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charlesh
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Homework Statement


Light consisting of two nearly equal wavelengths L and L+dL, where dL << L, is incident on a diffraction grating. The slit separation of the grating is D. Show that the angular separation of these two wavelengths in the m'th order is dTheta = dL / ((D/m)2+L2)0.5


Homework Equations



D sin(Theta) = mL (m=0,+-1, +-2,...)

The Attempt at a Solution



D sin(Theta1)=m(L+dL)
D sin(Theta2)=m(L)
dTheta = sin(Theta1)-sin(Theta2) = (m/D)(L+dL-L) = (m/D)dL= dL/(D/m)
This answer doesn't match the formula I need to proof: dTheta = dL / ((D/m)2+L2)0.5
 
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charlesh said:

Homework Statement


Light consisting of two nearly equal wavelengths L and L+dL, where dL << L, is incident on a diffraction grating. The slit separation of the grating is D. Show that the angular separation of these two wavelengths in the m'th order is dTheta = dL / ((D/m)2+L2)0.5


Homework Equations



D sin(Theta) = mL (m=0,+-1, +-2,...)

The Attempt at a Solution



D sin(Theta1)=m(L+dL)
D sin(Theta2)=m(L)
dTheta = sin(Theta1)-sin(Theta2) = (m/D)(L+dL-L) = (m/D)dL= dL/(D/m)
This answer doesn't match the formula I need to proof: dTheta = dL / ((D/m)2+L2)0.5

highlighted part is incorrect
 
Thanks for the response.
For small angle, sin(Theta) is very close to Theta (in radian).
 

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