On the edge of completing this proof about the order of an element

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SUMMARY

The discussion centers on proving the order of an element in group theory, specifically addressing the relationship between the element's order and the integer n. The user has established that the order is less than or equal to n and seeks guidance on which theorem to apply to confirm that the order is indeed n. The expression (bab^(-1))^m = b*a^m*b^(-1) is highlighted as a key component in the proof, indicating that if this equals the identity element e for m PREREQUISITES

  • Understanding of group theory concepts, particularly element order
  • Familiarity with the properties of group homomorphisms
  • Knowledge of the identity element in groups
  • Experience with mathematical proofs and theorems in abstract algebra
NEXT STEPS
  • Study Lagrange's Theorem in group theory
  • Learn about the structure of cyclic groups and their properties
  • Research the concept of conjugacy in groups
  • Explore the implications of the identity element in group operations
USEFUL FOR

Mathematics students, particularly those studying abstract algebra, and educators looking to deepen their understanding of group theory and element orders.

jdinatale
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Homework Statement


finish.jpg



The Attempt at a Solution



Based on my attempt above, I have demonstrated that the order is less than or equal to n. I am certain that it is actually n, but I'm not sure which theorem I can grab finish this thing off. Any tips for pointing me in the right direction?
 
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(bab^(-1))^m is equal to b*a^m*b^(-1) for any m. You've shown that. If that's equal to e for m<n, then was the order of a really n?
 

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