Calculate tension in a rope (pulley-rope-mass system)

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SUMMARY

The discussion focuses on calculating the tension in a pulley-rope-mass system involving a 2.00-kg textbook on a frictionless surface and a 3.00-kg hanging mass. Initially, the tension is calculated as 29.4 N when the system is at rest, based on the equilibrium condition. However, once the system is released, the tension changes due to acceleration, resulting in different tensions of 7.5 N and 18.2 N in the two sections of the rope. The presence of the pulley introduces varying tensions, necessitating a force diagram for accurate calculations.

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MarliesM
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Mhmm okay thanks, so if the rope had a mass, the two people would exert a force to make sure the rope didn't fall..

But now what about this (still can't solve a tension problem); a 2.00-kg textbook rests on a frictionless, horizontal surface. A cord attached to the book passes over a pulley whose diameter is 0.150m to a hanging book with mass 3.00 kg. The system is released from rest, and the books are observed to move 1.20m in 0.800s. (a) What is the tension in each part of the cord?

My attempt; before the system is released from rest, the tension equals 3.00 x 9.81 = 29.4 N. This is because the rope is in equilibrium and no forces act except at its ends, so the tension is the same at both ends and throughout the rope. (Right?)

But I don't understand what to do after the system starts moving. There is only one force acting, so the tension should be 3.00 x 2.00 x 9.81 = 58.9 N, but the answer is 7.5 N, 18.2 N.
 
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Hi,

Since this is a specific physics problem, I have moved your post to the Homework & Coursework Questions area from the other thread where we were discussing rope tension.

... a 2.00-kg textbook rests on a frictionless, horizontal surface. A cord attached to the book passes over a pulley whose diameter is 0.150m to a hanging book with mass 3.00 kg. The system is released from rest, and the books are observed to move 1.20m in 0.800s. (a) What is the tension in each part of the cord?

My attempt; before the system is released from rest, the tension equals 3.00 x 9.81 = 29.4 N. This is because the rope is in equilibrium and no forces act except at its ends, so the tension is the same at both ends and throughout the rope. (Right?)
Well, the pulley could cause the two sections of rope to have different tensions.
But I don't understand what to do after the system starts moving. There is only one force acting, so the tension should be 3.00 x 2.00 x 9.81 = 58.9 N, but the answer is 7.5 N, 18.2 N.
A pulley can cause the two sections of rope to have different tensions, and that appears to be the case here. The same-tension-through-the-rope rule only applies to a section of rope that connects objects at each end; i.e. the 2.0kg-to-pulley section, and separately to the pulley-to-3.0kg section of rope.

To solve the problem, draw a force diagram for each mass, then relate the net force to the acceleration of that mass.
 

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