What is the role of fields in Quantum Field Theory (QFT)?

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Quantum Field Theory (QFT) merges quantum mechanics and special relativity, with roots in Dirac's equation and developments in QED, QCD, and EWT, forming the basis of the standard model of particle physics. The discussion highlights confusion regarding the nature of quantum fields, questioning whether different particles correspond to distinct fields and how these fields relate to observable phenomena. It is clarified that QFT does not describe bound states, such as those in a hydrogen atom, but rather focuses on free states and scattering processes. The concept of particles in QFT is emphasized as experimental detections rather than tangible entities, while the fields themselves are considered unobservable. Overall, the conversation seeks to clarify the fundamental characteristics and implications of fields within QFT, recognizing the complexities involved in understanding these concepts.
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Hi,
I have just started to try to understand some ‘basic’ quantum field theory (QFT), if this is even possible, but not sure that I have any real understanding of the scope of the fields implied within the QFT model. As such, the following description may be completely wrong, but may serve as a description of my confusion.

As I understand it, QFT is the combination of quantum mechanics and special relativity, which has its roots in Dirac’s equation, but which later developed in terms of Quantum Electro-Dynamics (QED), Quantum Chromo-Dynamics (QCD) and the Electro-Weak Theory (EWT). In combination these theories seem to underpin the standard model of particle physics, although the semantics of the word ‘particle’ should not necessarily be taken literally as the terms may be more reflective of an underlying field theory.

However, I am struggling to understand whether the ‘field’ in question has any fundamental characteristics. For example is the quantum field of an electron different to the quantum field of a proton or photon? Is the idea of a quantum wave just an undulation of the quantum field?

By way of example, how might QFT describe a hydrogen atom, consisting of a proton and electron is floating in space, free of any obvious ‘classical’ fields. Under the particle model, the proton is a baryon made of quarks bound by a strong force described in terms of boson gluons. In contrast, electron is a lepton that presumably sits in a ground state orbital, but I am not sure how the stability of this orbital is described in QFT, e.g. is the electromagnetic ‘force’ linked to photons as a force carrier within the atomic structure?

Classically, a stable atom is said not to radiate EM, even though it appears to contain an accelerating charge, e.g. electron. In QFT, does the photon force carrier exist as quantized EM energy within the atom?

Equally, how does QFT describe a ‘free’ photon traveling through space. Is it a quantization of the EM field or is there a more fundamental description in terms of some quantum field description. In contrast, I have seen the suggestion that boson force carriers are described as scalar fields. Are there both quantum scalar fields and quantum vector fields? As such, I have become confused as to the scope and meaning of the fields in QFT and would very much appreciate any general insights before getting too lost, again, in the all the associated maths. Thanks
 
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mysearch said:
Hi,
I have just started to try to understand some ‘basic’ quantum field theory (QFT), if this is even possible, but not sure that I have any real understanding of the scope of the fields implied within the QFT model. As such, the following description may be completely wrong, but may serve as a description of my confusion.

As I understand it, QFT is the combination of quantum mechanics and special relativity, which has its roots in Dirac’s equation, but which later developed in terms of Quantum Electro-Dynamics (QED), Quantum Chromo-Dynamics (QCD) and the Electro-Weak Theory (EWT). In combination these theories seem to underpin the standard model of particle physics, although the semantics of the word ‘particle’ should not necessarily be taken literally as the terms may be more reflective of an underlying field theory.

However, I am struggling to understand whether the ‘field’ in question has any fundamental characteristics. For example is the quantum field of an electron different to the quantum field of a proton or photon? Is the idea of a quantum wave just an undulation of the quantum field?

By way of example, how might QFT describe a hydrogen atom, consisting of a proton and electron is floating in space, free of any obvious ‘classical’ fields. Under the particle model, the proton is a baryon made of quarks bound by a strong force described in terms of boson gluons. In contrast, electron is a lepton that presumably sits in a ground state orbital, but I am not sure how the stability of this orbital is described in QFT, e.g. is the electromagnetic ‘force’ linked to photons as a force carrier within the atomic structure?

Classically, a stable atom is said not to radiate EM, even though it appears to contain an accelerating charge, e.g. electron. In QFT, does the photon force carrier exist as quantized EM energy within the atom?

Equally, how does QFT describe a ‘free’ photon traveling through space. Is it a quantization of the EM field or is there a more fundamental description in terms of some quantum field description. In contrast, I have seen the suggestion that boson force carriers are described as scalar fields. Are there both quantum scalar fields and quantum vector fields? As such, I have become confused as to the scope and meaning of the fields in QFT and would very much appreciate any general insights before getting too lost, again, in the all the associated maths. Thanks
QFT is different from quantum mechanics (Mandl and Shaw QFT textbook).

The term particle is correct, because what one detects in experiments are particles (Weinberg QFT textbook). Fields are unobservable, by definition.

Yes, the quantum field of an electron is different to the quantum field of a photon.

There are not quantum waves in QFT.

QFT cannot completely describe a hydrogen atom, because QFT does not deal with bound states, but with free states and with scattering of free states.

In QFT position is not observable; therefore, QFT cannot physically describe a "photon traveling through space".
 
QFT cannot completely describe a hydrogen atom, because QFT does not deal with bound states,
You need to read about the Lamb shift.
 
juanrga said:
QFT cannot completely describe a hydrogen atom, because QFT does not deal with bound states, but with free states and with scattering of free states.
It can!

Nobody would use QED to describe the hydrogen atom "from scratch", but one used QED corrections to calculate the lamb shift.
In QCD one describes bound states (hadrons) using the lattice gauge formalism and one can derive mass spectrum, magnetic moment etc.

The fact that in many QFT textbooks one does not find descriptions of bound states is a problem of these books, not a problem of QFT
 
Hi,
Appreciate the comments and will read up on the issue of Lamb shift and bound states starting with the initial links, as cross reference. However, I would like to follow up on Juanrga's comments because they seem to address some of the fundamental issues I am interested in:
juanrga said:
QFT is different from quantum mechanics (Mandl and Shaw QFT textbook).
I have been trying to follow the historical developments leading to QFT. As I have understood things, Schrodinger’s wave equation did not account for special relativity (SR) and was limited to modelling just a few ‘particles’ at most. The Klein_Gordon equation was the first attempt to include SR, but did not account for spin. For this reason, Dirac’s equation seems to be the accepted starting point of QFT as a merger of quantum mechanics (QM) and SR. However, post-war development of QFT seems to have split into various branches, e.g. QED, QCD & EWT as mentioned in post #1. What I am not too sure about is whether QFT research continues as a subject in its own right?
juanrga said:
The term particle is correct, because what one detects in experiments are particles (Weinberg QFT textbook). Fields are unobservable, by definition.
While I agree that the term ‘particle’ is commonly used and certainly the focus of the particle model, I am not sure that the semantics of its use in QFT can be equated to any classical concept of a particle having tangible substance within the context of a field theory? In the spirit of the title of this thread, ‘What are the Fields in QFT?’, I would also like to try to clarify the comment about fields being unobservable. I am not questioning the comment, but the implication of what level of physical existence is attached to these fields. Do they have ‘any’ physical existence outside their mathematical description. From my initial review of the Euler-Lagrange equation for fields, it would seem that an aspect of the fields can be assigned both energy and momentum density. If so, are quantum fields described in terms of both scalar or vector fields? What physical concepts, if any, underpins these fields? See further comment below.
juanrga said:
Yes, the quantum field of an electron is different to the quantum field of a photon.
Is there any fundamental description of the nature of quantum fields, i.e. can I assume these fields are some sort of quantized energy field? Is a photon a quanta of EM energy that conforms to the general description of an EM field? So how is the make-up of the quantum field of an electron different? Is this field fundamentally different again when describing the quantum field of a proton?
juanrga said:
There are not quantum waves in QFT.
If energy is a scalar quantity, how does energy get transported between two points in spacetime without any concept of a basic wave mechanism?
juanrga said:
QFT cannot completely describe a hydrogen atom, because QFT does not deal with bound states, but with free states and with scattering of free states.
While I am not sure that I necessarily understand the detailed implications of the points raised by Bill_K and Tom.Stoer, I thought one of the reasons for developing QFT was due to the limitation of QM, i.e. Schrodinger’s equation, to describe ‘N’ particle systems. As far as I am aware, I thought QED was limited to electron-photon interactions, while QCD was more focused on quark interactions in the nucleus. Therefore, I thought the example of a hydrogen atom, given in post #1, would be relatively simple as a model to describe the various quantum fields at work. What is the state of play in quantum theory in the sense of providing a physical description versus just a probability outcome?
juanrga said:
In QFT position is not observable; therefore, QFT cannot physically describe a "photon traveling through space".
By that argument, can it describe an electron traveling through space? I realize that the idea of a photon can be problematic, but regarding the comment ‘there are not quantum waves in QFT’ – how does the energy of the photon move through spacetime according to QFT?

As always, would appreciate any help on offer. Thanks
 
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Whilst you're trying to grasp the physical nature of quantum fields, it's important not to forget that they need to be considered in conjunction with states in order to describe a system. This thread contains some useful insights. It's a long thread and there are a few disagreements, but there is some good stuff there !

For a not-too obscure discussion of what it all really means, Paul Teller's book is quite useful.
 
sheaf said:
Whilst you're trying to grasp the physical nature of quantum fields, it's important not to forget that they need to be considered in conjunction with states in order to describe a system. This thread contains some useful insights. It's a long thread and there are a few disagreements, but there is some good stuff there ! For a not-too obscure discussion of what it all really means, Paul Teller's book is quite useful.

Appreciate both references. However, there seems to be some mixed reviews on the Teller book.

Therefore, started to review the thread suggested, but finding most posts apparently focused on escalating a purely mathematically description of evermore abstracted concepts hard going. Couldn’t help thinking that Einstein’s quote “if you can't explain it simply, you don't understand it well enough” might have some relevance here. While I realize that QFT requires a given level of maths to understand the details in depth, I was hoping to get a few basic concepts sorted out before going straight to the 10 metre board to use a diving analogy.

I think you are being quite diplomatic, when you say that there are a ‘few disagreements’, e.g. Post #37 makes a possibly insightful general comment, which is then immediately refuted in post #38. I don’t think there is a single page in which one post doesn’t appear to be completely contradicted by another.

Having spent some time reviewing QM, I was left with doubts as to whether a quantum wave could be anchored to any sort of physical description due to the implications of wave dispersion required by a deBroglie wave packet. Therefore, posts #1 and #5 were simply trying to ascertain whether there was any consensus of the physical nature of quantum fields. Thanks
 
Bill_K said:
You need to read about the Lamb shift.

You would pay attention to the word "completely"
 
tom.stoer said:
It can!

Nobody would use QED to describe the hydrogen atom "from scratch", but one used QED corrections to calculate the lamb shift.
In QCD one describes bound states (hadrons) using the lattice gauge formalism and one can derive mass spectrum, magnetic moment etc.

The fact that in many QFT textbooks one does not find descriptions of bound states is a problem of these books, not a problem of QFT

First I said "completely" a word that another poster also missed.

Second, even if we restrict ourselves to working in an approximation where QED or QCD; i.e. where QFT is valid, there is not consistent and complete description of bound states.

I haven't seen a single rigorous treatment of such an issue in
quantum field theory.

Weinberg states in his QFT book (Vol. I) repeatedly that bound state
problems (and this includes the Lamb shift) are still very poorly
understood (though the Lamb shift is one of the most accurately
predicted physical quantity)...

http://arnold-neumaier.at/physfaq/topics/bound

And Arnold has only covered the surface of this topic.
 
  • #10
mysearch, are you familiar with operators in QM by now? In QFT, the most important dynamical equations like the Dirac equation are statements about operators, not about wavefunctions. So I think it is absolutely necessarry to learn how operators are used in simple QM and why they are needed, in order to understand how QFT works.

Note that there is a wavefunction interpretation of the Dirac equation for a single particle. This is sometimes called Realtivistic Quantum Mechanics. It's important to distinguish this from QFT. QFT is absolutely needed, if particle creation and annihilation is possible, that is in every collider experiment for example.
 
  • #11
juanrga said:
First I said "completely" a word that another poster also missed.
The problem is not the word "completely" but the statement "because QFT does not deal with bound states, but with free states and with scattering of free states."

I agree that may problems are not yet solved rigorously, but if you look a t lattice QCD you will find bound states of quarks (hadrons) in some approximation (e.g. quenched QCD) with e.g. 5% accuracy of mass spectra. So I would say that QFT is not able to fully describe all aspects of bound states rigorsously, but the statement that it "does not deal with bound states" is not correct; there are other QFT models of bound states, e.g. effective field theories, which are not so bad.

juanrga said:
even if we restrict ourselves to working in an approximation where ... QCD
What do you mean by that? In order to apply QCD you don't need any approximation in principle; the only thing you need is an appropriate method or maybe approximation depending on the regime you may want to study.

juanrga said:
i.e. where QFT is valid
What is the regime where QCD is not valid but where you have bound states?
 
  • #12
Regarding your link:

Bound states are supposed to be poles of the S-matrix ... for the bound state dynamics can be obtained approximately from resumming infinite families of Feynman diagrams

The second assumption is wrong b/c it is by no means clear that 'first expand then resume' is mathematically well defined. So yes, bound states would show up in the S-matrix, but a) it is not clear if this is the best way to calculate them and b) things get worse by a perturbative treatment of the S-matrix.

Bound states don't exist perturbatively
Exactly.

These problems are those inbolving bound states [...] such problems necessarily involve a breakdown of ordinary perturbation theory
Exactly.

Does that mean that QFT is incomplete? No, not necessarily. It simply means that a perturbative treatment of QFT is limited to scattering states and that bound states have to be treated differently (and there are other problems which you don't see in any perturbation expansion: color confinement, chiral symmetry breaking, instantons, ...)

When all you own is a hammer, every problem starts looking like a nail.
 
  • #13
mysearch said:
Hi,
Appreciate the comments and will read up on the issue of Lamb shift and bound states starting with the initial links, as cross reference.

If you are going to read those, you would at least read the next as well

http://arnold-neumaier.at/physfaq/topics/bound

There is not rigorous and complete treatment of bound states in QFT. In rigor, QFT only deals with free states although, using some tricks, QFT can deal with some energetic aspects of bound states as Lamb shift.

mysearch said:
I have been trying to follow the historical developments leading to QFT. As I have understood things, Schrodinger’s wave equation did not account for special relativity (SR) and was limited to modelling just a few ‘particles’ at most. The Klein_Gordon equation was the first attempt to include SR, but did not account for spin. For this reason, Dirac’s equation seems to be the accepted starting point of QFT as a merger of quantum mechanics (QM) and SR. However, post-war development of QFT seems to have split into various branches, e.g. QED, QCD & EWT as mentioned in post #1. What I am not too sure about is whether QFT research continues as a subject in its own right?

The Schrodinger equation is valid for systems of N particles, where N can be relatively large.

There are particle without spin. The problem of the Klein & Gordon equation is that is inconsistent. Dirac equation was an attempt to add spin but this equation is also inconsistent.

Both equations are the basis of RQM (relativistic quantum mechanics) but are completely inconsistent and were abandoned.

Then QFT born, rejecting RQM, and developing an different theory. For instance Dirac wavefunction equation of RQM is replaced by an identity for an operator named dirac operator, which is quantized and which describes a field: fermion field.

QED and QCD are subfields of QFT. QED is the quantum field theory of electromagnetic and fermion fields.

mysearch said:
While I agree that the term ‘particle’ is commonly used and certainly the focus of the particle model, I am not sure that the semantics of its use in QFT can be equated to any classical concept of a particle having tangible substance within the context of a field theory? In the spirit of the title of this thread, ‘What are the Fields in QFT?’, I would also like to try to clarify the comment about fields being unobservable. I am not questioning the comment, but the implication of what level of physical existence is attached to these fields. Do they have ‘any’ physical existence outside their mathematical description. From my initial review of the Euler-Lagrange equation for fields, it would seem that an aspect of the fields can be assigned both energy and momentum density. If so, are quantum fields described in terms of both scalar or vector fields? What physical concepts, if any, underpins these fields? See further comment below.

The concept of particle used in quantum theory is not a classical concept. E.g. the electron in the Schrödinger equation of QM is not the electron in Lorentz equation of the classical theory.

A field is unobservable, therefore in rigour (scientific method) you cannot attach "physical existence outside their mathematical description", although some physicists do (but well, you can find physicists believing in aliens and in parallel universes also).

Effectively fields have associated such concepts as energy and momentum density, and you cannot measure globally energy and momentum densities but only locally where there are particles. As Weinberg emphasizes in CERN experiments we detect particles, not fields. The field is a mathematical abstraction.

There are scalar, vector, and tensor quantum fields.

mysearch said:
Is there any fundamental description of the nature of quantum fields, i.e. can I assume these fields are some sort of quantized energy field? Is a photon a quanta of EM energy that conforms to the general description of an EM field? So how is the make-up of the quantum field of an electron different? Is this field fundamentally different again when describing the quantum field of a proton?

You are asking in essence, can I assume these fields are some sort of field?

Quantum fields have energy and momentum, but are not "energy fields", but fermion fields, boson fields...

The photon is the quanta of the EM quantum field.

Each field and its quanta has different properties as charge, spin, mass...

mysearch said:
If energy is a scalar quantity, how does energy get transported between two points in spacetime without any concept of a basic wave mechanism?

An electron with energy E traveling is transporting energy. A photon transports energy as well, but a photon is a quantum particle. The macroscopic wave phenomena is the result of a large collection of photons. Wave optics follow from QED as an approximation.

mysearch said:
While I am not sure that I necessarily understand the detailed implications of the points raised by Bill_K and Tom.Stoer, I thought one of the reasons for developing QFT was due to the limitation of QM, i.e. Schrodinger’s equation, to describe ‘N’ particle systems. As far as I am aware, I thought QED was limited to electron-photon interactions, while QCD was more focused on quark interactions in the nucleus. Therefore, I thought the example of a hydrogen atom, given in post #1, would be relatively simple as a model to describe the various quantum fields at work. What is the state of play in quantum theory in the sense of providing a physical description versus just a probability outcome?

QED also deals with interactions electron-electron, electron-positron, positron-photon...

Even limiting ourselves to study an hydrogen atom within the framework of QFT, you cannot describe it completely using only QED and QCD.

I do not know why you think that "physical description" and "probability outcome" are antonyms.

mysearch said:
By that argument, can it describe an electron traveling through space? I realize that the idea of a photon can be problematic, but regarding the comment ‘there are not quantum waves in QFT’ – how does the energy of the photon move through spacetime according to QFT?

As always, would appreciate any help on offer. Thanks

QFT cannot describe arbitrary motion. It only can describe simple cases as scattering, where spacetime coordinates are not measured. In QED the velocity of an electron is not even defined, the different components of the velocity do not commute and you cannot build a vector velocity
 
  • #14
I think you still don't get the difference between QFT and perturbative QFT.
 
  • #15
tom.stoer said:
The problem is not the word "completely" but the statement "because QFT does not deal with bound states, but with free states and with scattering of free states."

I agree that may problems are not yet solved rigorously, but if you look a t lattice QCD you will find bound states of quarks (hadrons) in some approximation (e.g. quenched QCD) with e.g. 5% accuracy of mass spectra. So I would say that QFT is not able to fully describe all aspects of bound states rigorsously, but the statement that it "does not deal with bound states" is not correct; there are other QFT models of bound states, e.g. effective field theories, which are not so bad.

The meaning of the word "completely" in my original posts must be understood as close to your "I would say that QFT is not able to fully describe all aspects of bound states rigorously".

tom.stoer said:
What do you mean by that? In order to apply QCD you don't need any approximation in principle; the only thing you need is an appropriate method or maybe approximation depending on the regime you may want to study.

What is the regime where QCD is not valid but where you have bound states?

QFT is not the final theory of the universe, but based in many approximations.
 
  • #16
tom.stoer said:
Regarding your link:

The second assumption is wrong b/c it is by no means clear that 'first expand then resume' is mathematically well defined.

The link starts by merely reporting what is "supposed" in the literature. In fact the author think something different:

I haven't seen a single rigorous treatment of such an issue in
quantum field theory.

As said before Arnold has only considered the surface of this topic.

Effectively, QFT is incomplete and cannot deal completely with bound states.

The impossibility to describe all the aspects of a bound state has nothing to see with perturbative vs non-perturbative QFT, although for some strange reason you believe the contrary.
 
  • #17
juanrga said:
QFT is not the final theory of the universe, but based in many approximations.
Tell me one single approximation that applies to QFT in general.

juanrga said:
Effectively, QFT is incomplete and cannot deal completely with bound states.
You can repeat it many times - w/o any profound reason it's implausible.

juanrga said:
The impossibility to describe all the aspects of a bound state has nothing to see with perturbative vs non-perturbative QFT
What are the aspects of bound states you miss in QFT? which bound states? and in which formalism?
 
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  • #18
kith said:
In QFT, the most important dynamical equations like the Dirac equation are statements about operators, not about wavefunctions. So I think it is absolutely necessary to learn how operators are used in simple QM and why they are needed, in order to understand how QFT works. Note that there is a wavefunction interpretation of the Dirac equation for a single particle. This is sometimes called Realtivistic Quantum Mechanics. It's important to distinguish this from QFT. QFT is absolutely needed, if particle creation and annihilation is possible, that is in every collider experiment for example.

Kith, thanks for the pointers and clarification regarding RQM versus QFT. I have only just started to work my way into post-war developments, which seem to underpin the standard particle model, i.e. QFT, QED, QCD, EWT. However, I am still only at the stage of working through the update of the Euler-Lagrange equation for fields, which then raised a number of questions in my mind regarding the nature of quantum fields, hence this thread.

As regard to operators, while I think I understand the basic concept I am not sure I fully appreciate the full scope within QFT. I am posting the following summary of my understanding so that somebody might be able correct any misconceptions on my part.
Thanks

My Understanding
Historically, the Klein-Gordon equation was interpreted in terms of particles. Subsequently it was re-interpreted in terms of a field [Φ], which was considered as an operator that could describe the creation and annihilation of particles. Again, in term of historical developments, QM was initial based on what is called the ‘first quantization’ that was re-interpreted in terms of fields via a ‘second quantization’. Originally, the first quantization defined position and momentum as operators, but in QFT the fields are quantized and become operators, while position, momentum and time are all now treated as parameters. However, the scope of the field operators is to act on the ‘state’ of the field. I think ‘Sheaf’ was trying to point me in this direction in post #6, although the idea of the field as an operator and the state of the field are still somewhat abstract concepts in my mind at this stage -see reply to Juanrga for examples:confused:. This said, the field operators are assumed to act on the field state to create or destroy particles, which is a key idea in QFT such that the number of particles is not fixed.

However, I will be honest and say that I not sure whether this approach is simply the preference of the mathematicians, which might still be described in some other way so that the physics of these interactions seem more tangible. :wink:
 
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  • #19
Juanrga, thanks for taking the trouble to respond to my questions in post #5. The following reply is intended primarily as comments rather than further questions.
juanrga said:
If you are going to read those, you would at least read the next as well http://arnold-neumaier.at/physfaq/topics/bound
Thanks for the reference.
juanrga said:
The Schrodinger equation is valid for systems of N particles, where N can be relatively large. There are particle without spin. The problem of the Klein & Gordon equation is that is inconsistent. Dirac equation was an attempt to add spin but this equation is also inconsistent. Both equations are the basis of RQM (relativistic quantum mechanics) but are completely inconsistent and were abandoned. Then QFT born, rejecting RQM, and developing an different theory. For instance Dirac wavefunction equation of RQM is replaced by an identity for an operator named dirac operator, which is quantized and which describes a field: fermion field. QED and QCD are subfields of QFT. QED is the quantum field theory of electromagnetic and fermion fields. The concept of particle used in quantum theory is not a classical concept. E.g. the electron in the Schrödinger equation of QM is not the electron in Lorentz equation of the classical theory.
Thanks, understanding the chronology is useful.
juanrga said:
A field is unobservable, therefore in rigour (scientific method) you cannot attach "physical existence outside their mathematical description", although some physicists do (but well, you can find physicists believing in aliens and in parallel universes also). Effectively fields have associated such concepts as energy and momentum density, and you cannot measure globally energy and momentum densities but only locally where there are particles. As Weinberg emphasizes in CERN experiments we detect particles, not fields. The field is a mathematical abstraction. There are scalar, vector, and tensor quantum fields.
I am not a physicist and do not necessary rule out the possibility of aliens or parallel universes, at least, at this stage. Therefore, it may come as no surprise that I struggle with physics that seems to be predicated on only mathematical concepts. It’s a limitation I know:rolleyes:
juanrga said:
You are asking in essence, can I assume these fields are some sort of field? Quantum fields have energy and momentum, but are not "energy fields", but fermion fields, boson fields... The photon is the quanta of the EM quantum field. Each field and its quanta has different properties as charge, spin, mass... An electron with energy E traveling is transporting energy. A photon transports energy as well, but a photon is a quantum particle. The macroscopic wave phenomena is the result of a large collection of photons. Wave optics follow from QED as an approximation. QED also deals with interactions electron-electron, electron-positron, positron-photon... Even limiting ourselves to study an hydrogen atom within the framework of QFT, you cannot describe it completely using only QED and QCD.
I know I am going to run into trouble with the following comments, but based on a ‘need’ to try to describe these concepts in some form of lowest common denominator, I think in terms of energy, fields and waves. The idea of a ‘particle’ which has no definable ‘substance’ seems to have no meaning other than in terms of a descriptive convenience at larger scales. In this context, a field seems to align to the idea of potential energy, where waves or perturbations in the field would appear analogous to kinetic energy of motion. Please understand I am not promoting this idea, especially in this forum, simply trying to explain my current difficulties in understanding QFT.:redface:
juanrga said:
I do not know why you think that "physical description" and "probability outcome" are antonyms.
Fair comment and a good word. In part, I have explained some of 'my' issues above, where basically I can’t reconcile the ability to predict the probability of a certain outcome or state with an actual physical description of why that outcome occurred. I accept that many will see this a complete failure to understand the probabilistic nature of quantum physics. However, I am still prepared to work on these issues:-p
 
  • #20
mysearch said:
I am not a physicist and do not necessary rule out the possibility of aliens or parallel universes, at least, at this stage. Therefore, it may come as no surprise that I struggle with physics that seems to be predicated on only mathematical concepts. It’s a limitation I know:rolleyes:

Some precision is needed here I am not objecting to people believing in many-worlds or aliens, but to people who pretends that such issues have the same scientific status that the law of gravity of the laws of thermodynamics.

mysearch said:
I know I am going to run into trouble with the following comments, but based on a ‘need’ to try to describe these concepts in some form of lowest common denominator, I think in terms of energy, fields and waves. The idea of a ‘particle’ which has no definable ‘substance’ seems to have no meaning other than in terms of a descriptive convenience at larger scales. In this context, a field seems to align to the idea of potential energy, where waves or perturbations in the field would appear analogous to kinetic energy of motion. Please understand I am not promoting this idea, especially in this forum, simply trying to explain my current difficulties in understanding QFT.:redface:

I do not know what you mean by «substance» (it seems some kind of metaphysical idea), but the concept of elementary particles as building blocks of nature seems particularly elegant and powerful for me.

Regarding fields they are modeled as a collection of harmonic oscillators. And if you ask what is oscillating? Then either you avoid to answer or you return to a particle concept. Moreover, the concept of field is only approximate. It is now generally accepted that QFT is only an effective theory that breaks down to higher energies. Field theory also breaks in other situations, and alternatives are under active research.
 
  • #21
Everybody says that in QFT there is no position operator, time and postion are considered as labels, but...
what is phi(x)?
what represents the state phi(x)|0>? (I thought that it represented the state in which there is 1 particle in position "x")
what represents the state phi(x)|phi(y)|0>? (I thought that it represented the state in which there is 1 particle in position "x" and another in position "y")
Thanks for everything you can do!
 
  • #22
mysearch said:
I know I am going to run into trouble with the following comments, but based on a ‘need’ to try to describe these concepts in some form of lowest common denominator, I think in terms of energy, fields and waves. The idea of a ‘particle’ which has no definable ‘substance’ seems to have no meaning other than in terms of a descriptive convenience at larger scales.

Here's a fun little calculation to try that demonstrates (to me at least) just how little "substance" there is in elementary particles. If you divide the radius of the Earth by the classical radius of an electron, then multiply that by the mass of an electron you will have effectively grown the mass of the electron to what it would be if you grew the size of the electron to be the size of the Earth.

The surprise is that the electron would weigh about 1/10 of an ounce (if memory serves correctly)
 
  • #23
juanrga said:
Some precision is needed here I am not objecting to people believing in many-worlds or aliens, but to people who pretends that such issues have the same scientific status that the law of gravity of the laws of thermodynamics.
My apologises, I knew what you meant, my comment was somewhat tongue-in-cheek.:-p
juanrga said:
I do not know what you mean by «substance» (it seems some kind of metaphysical idea), but the concept of elementary particles as building blocks of nature seems particularly elegant and powerful for me.
While I don’t want to waste your time on semantics, I meant the statement about ‘substance’ quite literally, not metaphysical. While, I agree with your comment in post #13 that “the concept of particle used in quantum theory is not a classical concept” it is not always clear just how people are defining a particle in QM versus QFT. Therefore, all I was implying is that an electron has no substance by virtue of there being no definition of material substance at this level other than in terms of E=mc^2. If so, is a particle just a concentration of energy in a small volume of space, ignoring spin and charge for now? Equally, I am not sure if the QM time evolution of a matter wave, i.e. dispersion, prior to the wave function collapse still fits into the QFT description. Sorry to belabour the point.
juanrga said:
Regarding fields they are modeled as a collection of harmonic oscillators. And if you ask what is oscillating? Then either you avoid to answer or you return to a particle concept. Moreover, the concept of field is only approximate. It is now generally accepted that QFT is only an effective theory that breaks down to higher energies. Field theory also breaks in other situations, and alternatives are under active research.
I have just found what appears to be a useful site, especially Chapter-1. Any thoughts: http://www.quantumfieldtheory.info/
 
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  • #24
PhilDSP said:
Here's a fun little calculation to try that demonstrates (to me at least) just how little "substance" there is in elementary particles. If you divide the radius of the Earth by the classical radius of an electron, then multiply that by the mass of an electron you will have effectively grown the mass of the electron to what it would be if you grew the size of the electron to be the size of the Earth. The surprise is that the electron would weigh about 1/10 of an ounce (if memory serves correctly)

Hi,
Here is the calculation as I have understood it, but I not sure whether this is what you meant.
Earth Radius/Electron Radius * Electron Mass
= (6378.1*10^3)/(2.817*10^-15)*(9.1*10^-31) = 2.01*10^-9 kg
This seems a lot less than 1/10 of an ounce, if the figures are correct.
The calculations were also a bit rushed as it is now getting late in my time zone.

However, wouldn’t the density of the electron be more relevant here?
Electron Density=Electron Mass/Electron Volume
=(9.1*10^-31)/(9.36*10^-44)=9.72*10^12

Earth Density=Earth Mass/Earth Volume
=(5.97*10^24)/(1.09*10^21)=5.52*10^3

On this basis it is the Earth that has no substance, while an electron would appear to be full of it. However, the question of ‘substance’ was more to do with what we think the (classical) Earth is made of versus what we think a (quantum) electron is made of. See issue raised by Juanrga in previous post.
 
  • #25
A field in QFT has just as much substance as a field in classical physics.

Take the electromagnetic field. If you think it has substance or no substance in classical physics, then it is the same in QFT. The only difference in "substance" between classical and quantized EM fields is that classically we may work with the electromagnetic fields, whereas quantum mechanically we have to work with the electromagnetic potentials (which we also call the electromagnetic field).

A photon is a quantized excitation of the electromagnetic field.
 
  • #26
the_pulp said:
Everybody says that in QFT there is no position operator, time and postion are considered as labels, but...
what is phi(x)?
what represents the state phi(x)|0>? (I thought that it represented the state in which there is 1 particle in position "x")
what represents the state phi(x)|phi(y)|0>? (I thought that it represented the state in which there is 1 particle in position "x" and another in position "y")
Thanks for everything you can do!
In QFT, \phi(x) is the field operator, and both {\bf x} and t are simply labels. Just because position is demoted from being an operator in QFT does not mean it loses its meaning. It is still possible to create particles at, say {\bf x}_1, by acting on the vacuum with the creation operator for that particle at that location: a^\dagger({\bf x}_1)|0\rangle.
 
  • #27
Let's see, I think the situation is:

There is an operator which creates a particle at a certain position. This creation operator is not Hermitian, so it doesn't correspond to an observable.

There is another operator called the Newton-Wigner operator, which seems to correspond to an observable. However, it is not relativistically invariant, so if in one inertial frame the particle is localized, in another it is spread out.

So what is meant by there is no position operator is that there is no relativistically invariant position operator.

The amount of frame-dependent non-localization due to the Newton-Wigner operator is probably too small to have practical consequences. However, I'm not sure that the Newton-Wigner operator corresponds to the very inaccurate "position" measured in particle physics experiments. Although the position measurement seems accurate to us, those measurements are inaccurate compared to the particle's de Broglie wavelength, as is required for the momentum to measured very accurately.
 
  • #28
the_pulp said:
Everybody says that in QFT there is no position operator, time and postion are considered as labels, but...
what is phi(x)?
what represents the state phi(x)|0>? (I thought that it represented the state in which there is 1 particle in position "x")
what represents the state phi(x)|phi(y)|0>? (I thought that it represented the state in which there is 1 particle in position "x" and another in position "y")
Thanks for everything you can do!

The main question here is that x and t are non-observable parameters (unphysical labels or dummy parameters if you prefer).

As stated in many textbooks x and t in QFT are not related to physical measurement of position and time.

That is the reason which you need to integrate out x and t from QFT formulae before comparing with experiments. E.g. the S-matrix cannot depend on labels x,t that cannot be measured, evidently.
 
  • #29
mysearch said:
While I don’t want to waste your time on semantics, I meant the statement about ‘substance’ quite literally, not metaphysical. While, I agree with your comment in post #13 that “the concept of particle used in quantum theory is not a classical concept” it is not always clear just how people are defining a particle in QM versus QFT. Therefore, all I was implying is that an electron has no substance by virtue of there being no definition of material substance at this level other than in terms of E=mc^2. If so, is a particle just a concentration of energy in a small volume of space, ignoring spin and charge for now? Equally, I am not sure if the QM time evolution of a matter wave, i.e. dispersion, prior to the wave function collapse still fits into the QFT description. Sorry to belabour the point.

I continue without understand what you mean by «substance». This is not a scientific term neither in QM nor QFT (the term substance is defined in chemistry).

E=mc2 is not valid in the general case.

A particle is an object with determined properties assigned to it. An elementary particle is a microscopic non-composite object characterized by mass, spin, charge...

Energy and position are not properties that define what a particle is. Moreover a particle does not need to be confined in a small volume of space.

The term «matter wave» is a misnomer for me.
 
  • #30
PhilDSP said:
The surprise is that the electron would weigh about 1/10 of an ounce (if memory serves correctly)
I'm surprised no one took you up on this interesting calculation, but your conclusion must be very wrong. We know that electrons represent roughly 1/1800 of the mass of the Sun, by its mass ratio to protons. Thus if electrons occupied 1/1800 of the volume of the Sun (using their classical radius to talk about the volume they "occupy", for no particular reason), then electrons would have the same average density as the Sun (not much less). However, electrons occupy much much less than 1/1800 of the volume (using their classical radius), so the average density of an electron (in this arbtirary measure) must be way way more than the average density of the Sun. Since the classical radius is about 2 times 10^(-15) m, its ratio to the solar radius is about 3 times 10^(-24), and there are about 10^57 electrons in the Sun. Hence their volume fraction is about 10^(-13), in this arbitrary volume measurement. That puts their "average density" at about 10^10 times larger than the Sun, and if you grew one to the size of the Sun, it would have 10^10 Suns of mass.
 

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