Finding Time t for Instantaneous & Average Velocity: Particle Motion

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The position of a particle moving in a straight line during a 10–second trip is s(t) = 3t2 − 3t + 5 cm.Find a time t at which the instantaneous velocity is equal to the average velocity for the entire trip.
 
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Average velocity = (x2 - x1)/Δt

How do you find instantaneous velocity?
 
the derivative
 
what does x represent?
 
The position. x2 - x1 is the change in position. Your object starts at one point, and ten seconds later, it's somewhere else. That somewhere else is x2.
 
sammiyahc0 said:
what does x represent?
Your "s". The average speed, between t= 0 and t=10, is (s(10)- s(0))/(10 - 0). Calculate that, set it equal to s'(t) and solve for t.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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