Test Question (Potential Energy): Need help finding answer

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Homework Help Overview

The problem involves a 4kg block dropped from a height of 0.8m onto a spring with a spring constant of 120N/m. Participants are discussing the relationship between potential energy and kinetic energy to determine the maximum compression of the spring.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to equate the potential energy at the top with the kinetic energy at the bottom and subsequently with the potential energy stored in the spring. Some participants question the assumptions made regarding the gravitational potential energy and its effect on the spring compression.

Discussion Status

Participants are actively engaging with the problem, with some suggesting that the gravitational potential energy needs to be reconsidered in the context of the spring's compression. There is an ongoing dialogue about the equations used and their implications, but no consensus has been reached.

Contextual Notes

There appears to be confusion regarding the treatment of gravitational potential energy in relation to the spring's compression, with differing interpretations of the variables involved in the equations.

gokugreene
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I can't figure out what I did wrong on this test question.

A 4kg block is dropped from a height of 0.8m above a spring, k=120N/m. Find the maximum compression of the spring.

I have the PE at the top is equal to KE at the bottom.
PEtop=31.4J
KEbottom=31.4J

The potential energy in the spring when compressed should equal the KE at the bottom. Based upon that I should be able to find the maximum distance the spring will compress.

KEbottom=Wspring
31.4J=.5*120*x^2
Rearranging x=sqrt(2*31.4/120) and I get x=-0.723m

What am I doing wrong here? Can someone point it out.

Thanks, peace
 
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Remember that the spring is compressing in the vertical direction, so there is more gravitational potential energy to take into account:

Initial gravitational potential energy = Final spring potential energy

mg(x_0+x_{spring})=\frac{1}{2}kx_{spring}^2
 
Last edited:
Your equation will give me the exact same answer I got.
mg(0.8 + 0) =.5kx^2
 
gokugreene said:
Your equation will give me the exact same answer I got.
mg(0.8 + 0) =.5kx^2

No, in my response, x_spring is the same as x in your response. On the left side, you set the second term to 0, when it should be mgx. It's a quadratic equation.
 

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