Calculating Cliff Height Using Acceleration Due to Gravity

  • Thread starter thschica
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In summary, the problem involves a stone being dropped from the top of a cliff and hitting the ground after 3.30 seconds. Using the kinematics equation, s = ut + 1/2at^2, where s is the height, u is the initial velocity, t is time, and a is acceleration, we can solve for the height of the cliff. With a known initial velocity of 0 and time of 3.30 seconds, we can use the acceleration due to gravity, which is approximately 10 m/s^2, to calculate the height of the cliff. The result is 54.5 meters.
  • #1
thschica
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A stone is dropped from the top of a cliff. It is seen to hit the ground below after 3.30 s. How high is the cliff?
 
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  • #2
Please note that we DO have a Homework section, and that to get "Help!", you need to show what you have done and where exactly are you stuck. No one here will do the problem for you.

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  • #3
This is a basic kinematics problem so it works the same mathematically as say the "car problem".

In the car problem, you can figure out the horizontal distance something travels using time by the relationship:

X = Vi(t) + 1/2(A)t^2

There are 4 variables in this equation: distance, velocity, time, and acceleration. If you know three of them, you can solve for the missing one. So let's say the car was initially at rest. Your initial velocity would be Vi = 0. Let's say the car accelerates at a constant rate of 4 m/s. Then A=4 m/s. And let's say that you want to know how far the car traveled in say 20 seconds. Now you know T. Once you know three of the 4, you can plug these in and use Algebra to solve for the missing distance traveled, X.

Your problem is very similar to the car problem except instead of a car traveling horizontally you have a ball traveling in a straight line vertically. Without spoiling anything you are given the time, the initial velocity, and the acceleration in your problem as well. Think about it a bit and you should be able to figure out what these three values are. From there, you can use the equation and solve.
 
  • #4
u = 0 -as it is dropped.
t = 3.3 secs.
height = s
a = acceleration due to gravity = 10 approx.
s = ut +1/2at^2 ( t^2 is t square i.e t to the power of 2)
s = 0 + 1/2 * 10 * 3.3*3.3
s = 5 * 10.9
s =54.5
Therefore the height of the cliff is 54.5 m.
 
  • #5
I am still confused as to what exactly is the acceleration.I know the initial velocity is 0 and the time is 3.30 sec.But i don't know what the acceleration is!
 
  • #6
Nevermind The acceleration is 9.80 thanks everyone for the help!
 
  • #7
Well I hope you know what acceleration means. In this problem it equals to 9.81 m/s^2 (gravitation constant), and it is acceleration caused by gravity, because you are dropping the stone verticaly.
 

1. How is the height of a cliff measured?

The height of a cliff is typically measured from the base of the cliff to the highest point on the cliff's edge.

2. What is the average height of a cliff?

The average height of a cliff can vary greatly, but it is generally considered to be around 50-100 feet.

3. How can you estimate the height of a cliff without using any tools?

One way to estimate the height of a cliff without using tools is by using the "handrail" method. This involves holding out your arm at full length and using your hand as a reference point to estimate the height of the cliff.

4. Is there a standard unit for measuring the height of a cliff?

The most common unit for measuring the height of a cliff is feet. However, some countries may use meters as the standard unit of measurement.

5. Can the height of a cliff change over time?

Yes, the height of a cliff can change over time due to natural erosion or man-made alterations to the landscape.

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