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A stone is dropped from the top of a cliff. It is seen to hit the ground below after 3.30 s. How high is the cliff?
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The height of the cliff is calculated to be 54.5 meters using the kinematic equation s = ut + 1/2at², where the initial velocity (u) is 0 m/s, time (t) is 3.30 seconds, and acceleration (a) is 9.81 m/s², the acceleration due to gravity. The calculation involves substituting these values into the equation, resulting in s = 0 + 1/2 * 9.81 * (3.30)². This discussion emphasizes the importance of understanding the relationship between distance, velocity, time, and acceleration in solving basic kinematics problems.
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