Find final velocity in a horizontal projectile motion

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SUMMARY

The discussion focuses on calculating the final velocity of a ball thrown horizontally from a cliff, with a fall time of 2.5 seconds. The height of the cliff is determined to be 30.6 meters, and the vertical final velocity (Vfy) is calculated as 24.5 m/s using the equation Vfy = g⋅t, where g is the acceleration due to gravity. However, the horizontal distance (Δx) cannot be calculated without knowing the initial horizontal velocity (Vx), which is not provided in the problem statement. The assumption of negligible air resistance allows for the final horizontal velocity (Vfx) to be approximated as equal to the initial horizontal velocity.

PREREQUISITES
  • Understanding of projectile motion principles
  • Familiarity with kinematic equations, specifically Δy = 2⋅g⋅t^2 and Vfy = g⋅t
  • Knowledge of horizontal motion and its independence from vertical motion
  • Basic grasp of gravity's effect on falling objects
NEXT STEPS
  • Research how to calculate horizontal projectile motion with known initial velocities
  • Learn about the effects of air resistance on projectile motion
  • Study the concept of initial velocity in projectile motion scenarios
  • Explore real-world applications of projectile motion in sports, such as baseball pitching
USEFUL FOR

Students studying physics, educators teaching projectile motion concepts, and anyone interested in understanding the dynamics of objects in motion under gravity.

vAhmed
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Homework Statement


A ball was thrown from a cliff, it reached to the ground after 2.5 seconds.
a) Find the height of the cliff.
b) Find the horizontal distance the ball reached.

Homework Equations


Δy = 2⋅g⋅t^2
Vfy = g⋅t
√(Vfy)^2+(Vfx)^2
Δx= Vx⋅t

The Attempt at a Solution


I've found Δy=30.6m and Vfy=24.5m/s but I couldn't find Vfx without Δx using the equation Δx=Vx⋅t
How can I find Vfx in order to calculate Vf
 
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You need to know the initial velocity and the angle which thrown. If it was thrown at a 0° angle to the horizontal, then the initial velocity will not contribute to how long it takes to hit the ground.

If you are assuming negligible air resistance, then you can assume the final horizontal velocity will be approximately equal to the initial horizontal velocity.

If the problem doesn't give an initial velocity, You could take something known like the fastest baseball thrown, and use that to find an upper bound.o0)
 
+1

vAhmed said:
I've found Δy=30.6m and Vfy=24.5m/s

Those answers look ok but as Scott said you don't have enough info in the problem statement to answer b). Did you miss out something?
 

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