Equation to find density of metal

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Homework Help Overview

The discussion revolves around calculating the density of a metal, as well as related concepts such as mass, weight, and energy in the context of physics problems. Participants explore the definitions and units associated with these concepts.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss the appropriate SI units for measuring mass and weight, questioning the definitions of density and the relationship between potential and kinetic energy. There are attempts to clarify the calculations needed for specific problems, including the weight of a lump of metal and the kinetic energy of a falling mass.

Discussion Status

The discussion is active, with participants providing guidance on the relationships between mass, weight, and energy. Some participants are exploring different interpretations of the problems, while others are questioning their own assumptions and calculations. There is no explicit consensus, but several productive directions have been suggested.

Contextual Notes

Some participants express uncertainty about the equations and units involved, particularly in the context of homework constraints. There are mentions of specific values and calculations that may not align with standard practices, indicating a need for clarification on the correct approach.

RMHAZARD
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i need help please what si unit do i use to messure the mass of a coin i believe that you would have to use grams but i believe i could be mistaken
Thanks
also how woul i calculate the weight of a lump of metal of mass 3.4 x 10 to the power of -six
I forgot what is the equation to find density of metal and weight of metal under water
i do not want the answer just a step in the right direction
 
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The SI unit for mass is the Kilogram, so using grams is ok.

Weigh is a force, Newtons 2nd law states; Force = Mass x Acceleration.

The mass of the object will not change if placed in water. Similarly the acceleration due to gravity does not change in water, therefore it`s wieght is unchanged if on land or in water.

Q. What is the definition for density?
 
The SI unit for mass is kg.
also how woul i calculate the weight of a lump of metal of mass 3.4 x 10 to the power of -six
The weight of and object is proportional to the mass and the acceleration of gravity.

EDIT: Just saw zanazzi78's reply.
 
10 to the power -6 would be what in normal digits
 
RMHAZARD said:
10 to the power -6 would be what in normal digits

not sure what you mean but ...

1 x 10 ^ -6 = 0.000001
 
kk thanks i have got a test and are finding out how to do these types of question how would i do this one pleae

A 2g mass falls 10m. Calculate the kinetic energy of the mass after falling this distance. Gravitational acceleration = 10 m/s ^ 2
 
RMHAZARD said:
kk thanks i have got a test and are finding out how to do these types of question how would i do this one pleae
A 2g mass falls 10m. Calculate the kinetic energy of the mass after falling this distance. Gravitational acceleration = 10 m/s ^ 2

Do you know the equation for Kinetic energy?
Do you know the relationship between Potential energy and kinetic energy?
 
The equation for Kinetic energy is

K.E = 1/2 Mv ^ Kinetic energy +1/2 Mass x Velocity

Potenial energy and kinetic energy forgot what they had in common
 
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RMHAZARD said:
The equation for Kinetic energy is
K.E = 1/2 MU ^
And i forgot the potenial energy
[tex]K.E. = \frac{mv^2}{2}[/tex]
P.E. = mass x gravity x height
Q. How are P.E. and K.E. related?
this will help you work out the K.E. of the system!
 
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  • #10
i think i have got the answer is it 5.67893 ami right if i am wrong can you show the steps u did to do it
 
  • #11
How did you get that value?

if you tell my what you did, i`ll show you where you went wrong.

What are the units for Kinetic Energy?
 
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  • #12
the units for kinetic energy are K.E?

how u find velocity i think i know what to do now thanks
 
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  • #13
RMHAZARD said:
the units for kinetic energy are K.E?

Mass is mesured in Kg
Time in seconds,
Energy in ...

Your answer is wrong. PF forbids people from giving answers. If you show your workings i can help you.
 
  • #14
i done it twice i don't know if either one is correct

First attempt


K.E = ? Mass = 2

Gravitational acceleration = 10

so i worked out i need to find velocity so the formula for velocity is V = M x A
V = 2 x 10 = 20 so velocity is 20 now i have done that i need to do
K.E = MV ^2 all divided by 2 so that's 40 divide by 2 equal 20 is this right?


Second atempt

I think Kinetic Energy = 1/2 Mass x Velocity squared.

Therefore: 1/2 x 0.002 x Velocity squared.

We need to work out velocity.

V = U squared + 2 accel x distance
V= 0 + 2 x 10 x 10
V = 200 but that doesn't at all sound right.

Therfore = 1/2 0.002 x 200 squared
= 40
 
  • #15
When you read a question think "What information do i have? how can i use this info?" If a question gives you a height then you need to use it some where, teachers don`t give you info in a question to confuse you!

Fact; "The lost in potential energy is equal to the gain in Kinetic energy"

The question gives you the height of the falling object! - 10m

It gives you mass 2g or 0.002kg

It gives you acceleration due to gravity - 10m/s^2

PE= m.g.h

Therefore you know all the values on the right hand side!:rolleyes:

But for the K.E expression you only know the mass :confused:

The question is designed to test your knowlede of the relationship between K.E. and P.E.

so you work out the P.E. of the object when it is 10m above the ground and then state that once it has fallen 10m, then the very same, amount of energy it "transfered" into Kinetic energy.

so we now have ...

P.E. = 0.002 kg x 10 m x 10m/s^2
= 0.2 ?, you never answered my question "what is energy measured in?"
so i`ll ask it again, what are the units here? You will loose marks if you don`t get the units right!
 
  • #16
Energy is messured in joules
 
  • #17
so what did i get wrong?
 
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  • #18
RMHAZARD said:
so what did i get wrong?

only your approach to the question:biggrin:

You made the assumption that since the question was asking about Kinetic energy you needed to use [tex]\frac{mv^2}{2}[/tex] you don`t. The question gave you all the info you needed to work out the potential energy.

you first attemp was allmost right you need to use si units i.e. kg inorded to get the correct value of joules, there is a big dirffrence between 20 and 0.2!

hope this helped.
 
  • #19
yes thank you for all your help you really helped me thanks
 

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