Calorimetry Lab Analysis (predict specific heat of unknown metal)

[ZapperZ]

do you think i need ideal gas law?

I have no idea, because I don't know what you are doing. Besides, this is not relevant to your question in this thread.

and do you think you can help me with the thing on google sheets?

A what?

Zz.

 

[Chestermiller]

$$C_{cube}=\frac{(30)(4.184)(26-20)}{(121.5)(100-26)}$$

?

 

[Wubblyboofus]

I have no idea, because I don't know what you are doing. Besides, this is not relevant to your question in this thread.

well it turns out i don't need it as someone else explained to me

and google sheets is the thing that is kinda like microsoft excel that let's you make spreadsheets

 

[Wubblyboofus]

$$C_{cube}=\frac{(30)(4.184)(26-20)}{(121.5)(100-26)}$$

?

0.084

 

[Wubblyboofus]

now we just need to find it for the other two trials, average it, and then find the metal with that specific heat

thank you so much!

 

[Chestermiller]

0.084

Did I input the correct temperatures here?

 

[Wubblyboofus]

Did I input the correct temperatures here?

yes i think you did

 

[Wubblyboofus]

but i fixed the spreadsheet data and now I am getting 1.1 J/gC
calorimetry is so weird

 

[Chestermiller]

but i fixed the spreadsheet data and now I am getting 1.1 J/gC
calorimetry is so weird

Let's see your hand calculation.

 

[Wubblyboofus]

4.184*30*76.8/73.3/121.5=1.082
4.184*30*79.3/74/121.5=1.107
4.184*30*75.8/72.8/121.5=1.076

?

 

[Chestermiller]

4.184*30*76.8/73.3/121.5=1.082
4.184*30*79.3/74/121.5=1.107
4.184*30*75.8/72.8/121.5=1.076

?

is the 76.8 in degrees C or degrees F? Is the 73.3 in degrees C or degrees F? What are the actual initial and final temperatures of cube and water for this case?

 

[Wubblyboofus]

is the 76.8 in degrees C or degrees F? Is the 73.3 in degrees C or degrees F? What are the actual initial and final temperatures of cube and water for this case?

the 76.8 and 73.3 are changes in temperature

 

[Wubblyboofus]

is the 76.8 in degrees C or degrees F? Is the 73.3 in degrees C or degrees F? What are the actual initial and final temperatures of cube and water for this case?

the actual are

trial name	mass in g	ti in C	tf in C	mass water in g	ti water in C	tf water in C	ct in C	ct water in C	specific heat in J/gC
UM1	121.5	99.6	26.3	30	22.8	99.6	73.3	76.8	1.082415239

 

[Wubblyboofus]

acronyms
ti	initial temperature
tf	final temperature
g	grams
C	degrees celcius
ct	change in temperature
J	joules
UM	unknown metal trial
LT	lead trial

 

[Chestermiller]

How can the final temperature of the water be higher than the final temperature of the cube?

 

[Wubblyboofus]

the initial temp of the cube if before i put it into the boiling water
the final temp of the cube is after i put it in the boiling water for a couple minutes
the initial temp of the water is room temp (before i put the boiling cube in)
the final temp of the water is the highest temp the room temp water becomes after putting the cube in

 

[tech99]

the water ti and tf is how much the room temperature water was heated once the metal (at 212 C) was placed into it. so it goes from about 21 to 26 because the water has high specific heat so it is hard to raise its temperature even if a block of boiling metal is placed into it.
the metal ti and tf however is how much the metal was heated once placed into boiling water. so that would be from 21 to 212.

as i said earlier the procedure went as follows:
put metal into boiling water
metal is now at boiling temperature
put that same metal into room temp water
see how much the room temp water heats
calculate specific heat of metal
use that to identify the metal

You heated the water to 100C not 212C.

 

[Chestermiller]

the initial temp of the cube if before i put it into the boiling water
the final temp of the cube is after i put it in the boiling water for a couple minutes

Are you aware that this has nothing to do with the measurement you are trying to make? The only reason for putting the cube in the boiling water was to establish its starting temperature for the subsequent measurement.

 

[Wubblyboofus]

You heated the water to 100C not 212C.

yea i fixed that already
but i can't change the original post for some reason
i changed my spreadsheet though

 

[Wubblyboofus]

Are you aware that this has nothing to do with the measurement you are trying to make? The only reason for putting the cube in the boiling water was to establish its starting temperature for the subsequent measurement.

oh
so would the new one be
water:
21 --> 26
metal:
212 --> 26

 

[Wubblyboofus]

this is due tomorrow dang

 

[Wubblyboofus]

and after i predict this i have to find the percent error of my calculations

 

[Chestermiller]

oh
so would the new one be
water:
21 --> 26
metal:
212 --> 26

100 —> 26

 

[Wubblyboofus]

100 —> 26

ok let me put it all thru the calculator again ugh

 

[Wubblyboofus]

i really appreciate your guys's help by the way. i probably would have never found my mistakes without you guys
thanks