# Calorimetry Lab Analysis (predict specific heat of unknown metal)

• Wubblyboofus
0.084
Did I input the correct temperatures here?

Did I input the correct temperatures here?
yes i think you did

but i fixed the spreadsheet data and now I am getting 1.1 J/gC
calorimetry is so weird

but i fixed the spreadsheet data and now I am getting 1.1 J/gC
calorimetry is so weird

4.184*30*76.8/73.3/121.5=1.082
4.184*30*79.3/74/121.5=1.107
4.184*30*75.8/72.8/121.5=1.076

?

4.184*30*76.8/73.3/121.5=1.082
4.184*30*79.3/74/121.5=1.107
4.184*30*75.8/72.8/121.5=1.076

?
is the 76.8 in degrees C or degrees F? Is the 73.3 in degrees C or degrees F? What are the actual initial and final temperatures of cube and water for this case?

is the 76.8 in degrees C or degrees F? Is the 73.3 in degrees C or degrees F? What are the actual initial and final temperatures of cube and water for this case?
the 76.8 and 73.3 are changes in temperature

is the 76.8 in degrees C or degrees F? Is the 73.3 in degrees C or degrees F? What are the actual initial and final temperatures of cube and water for this case?
the actual are
 trial name mass in g ti in C tf in C mass water in g ti water in C tf water in C ct in C ct water in C specific heat in J/gC UM1 121.5 99.6 26.3 30 22.8 99.6 73.3 76.8 1.082415239

 acronyms ti initial temperature tf final temperature g grams C degrees celcius ct change in temperature J joules UM unknown metal trial LT lead trial

How can the final temperature of the water be higher than the final temperature of the cube?

the initial temp of the cube if before i put it into the boiling water
the final temp of the cube is after i put it in the boiling water for a couple minutes
the initial temp of the water is room temp (before i put the boiling cube in)
the final temp of the water is the highest temp the room temp water becomes after putting the cube in

the water ti and tf is how much the room temperature water was heated once the metal (at 212 C) was placed into it. so it goes from about 21 to 26 because the water has high specific heat so it is hard to raise its temperature even if a block of boiling metal is placed into it.
the metal ti and tf however is how much the metal was heated once placed into boiling water. so that would be from 21 to 212.

as i said earlier the procedure went as follows:
put metal into boiling water
metal is now at boiling temperature
put that same metal into room temp water
see how much the room temp water heats
calculate specific heat of metal
use that to identify the metal
You heated the water to 100C not 212C.

the initial temp of the cube if before i put it into the boiling water
the final temp of the cube is after i put it in the boiling water for a couple minutes
Are you aware that this has nothing to do with the measurement you are trying to make? The only reason for putting the cube in the boiling water was to establish its starting temperature for the subsequent measurement.

You heated the water to 100C not 212C.
but i can't change the original post for some reason

Are you aware that this has nothing to do with the measurement you are trying to make? The only reason for putting the cube in the boiling water was to establish its starting temperature for the subsequent measurement.
oh
so would the new one be
water:
21 --> 26
metal:
212 --> 26

this is due tomorrow dang

and after i predict this i have to find the percent error of my calculations

oh
so would the new one be
water:
21 --> 26
metal:
212 --> 26
100 —> 26

100 —> 26
ok let me put it all thru the calculator again ugh

i really appreciate your guys's help by the way. i probably would have never found my mistakes without you guys
thanks