Given that http://forums.cramster.com/Answer-Board/Image/cramster-equation-200641003458632802260985487500893.gif is the complementary function for the differential equation http://forums.cramster.com/Answer-Board/Image/cramster-equation-200641003635632802261951581250765.gif use the variation...
Use the method of variation of parameters to find a particular solution of http://forums.cramster.com/Answer-Board/Image/cramster-equation-2006491914366328020687673812501253.gif
ok i know first i do...
I'm not currently in a class, but I'm doing this for fun.. but technically I would still call it coursework, so I'm posting it here..
I'm studying Redheffer/Sokolnikoff's Mathmatics of Modern Engineering.. and I find a problem on page 75, use the method of variation of parameters to find the...
OKay everyone, this is a big f'ing problem (to me anyways) and its only worth 1 point! But I'm doing it anyways. So here was my attempt, everything seems to be working out like it should but look at what u1 came out too, what am i going to do with that mess? Also do u see any mistakes...
i'm confused about that method:
1) when proving that method works, why do you have to make u and v satisfy the 2nd condition u`y1+v`y2=0
2) when you're integrating to find yp, why do you leave out the constant that results from the integration?
I know how to solve the following ODE with variation of parameters:
y''+4y=4\sec{\left(2t\right)}.
Is there any way to solve this with undetermined coefficients? So far I have tried Yp=Acos(2t)+Bsin(2t), but that didn't work.
Thanks for the help.
I have been trying to get this for a while and can't figure it out:
if a fundamental matrix of the system x' = Ax is X(t)
\left(\begin{array}{cc}e^t&0\\0&e^{-t}\end{array}\right)
find a particular solution yp(t) of x' = Ax + [e^t, 2]^{transpose} such that yp(0) = 0
So, I got u(t) =...
I need to solve this D.E.
x^2y''-xy' + y = x^3
i'm supposed to use the variation of parameters technique.
in that technique i need to get a coeffecient of 1 in the first postion of y'' and then sove the homogenous D.E.
y''-\frac{y'}{x} +\frac{y}{x^2}=0
the above leads to...
Hello,
I'm trying to understand this concept. Jere's the problem I'm doing.
I have to find the general solution for:
y'' + 36y = -4xsin(6x)
So you then solve for your characteristic equation and get lamda = +/- 6
so y1 = e^-6x and y2 = e^6x
You get your matrix for w, w1, and w2.
w =...
the problem is fin the general solution of the differential eq :
y''+y=2sect + 3 (-pi/2 < t < pi/2)
using variation of parameters.
I just needed a check to make sure my answer was correct.
r^2+1 = 0
r= -i
r= i
y1= cost
y2= sint
g(t)= 2sect+ 3
y(t) = c1cost + c2sint + Y(t)...