Variation of parameters problem, very BIG, but i think i'm right so far Diff EQ

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SUMMARY

The forum discussion focuses on solving a variation of parameters problem in differential equations, specifically using the Lagrange formula for finding a particular solution to an inhomogeneous equation. The user expresses confusion regarding the complexity of their solution, particularly with the term u1. The Lagrange formula provided is Y(t) = -y_1 ∫(y_2 g/W(y_1,y_2))dt + y_2∫(y_1 g/W(y_1,y_2))dt, which is essential for obtaining a particular solution when y_1(t) and y_2(t) are linearly independent solutions of the corresponding homogeneous equation.

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mr_coffee
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OKay everyone, this is a big f'ing problem (to me anyways) and its only worth 1 point! But I'm doing it anyways. So here was my attempt, everything seems to be working out like it should but look at what u1 came out too, what am i going to do with that mess? Also do u see any mistakes? Thanks!
http://img86.imageshack.us/img86/6803/lastscan0rh.jpg
http://img86.imageshack.us/img86/2782/lastscan22bs.jpg
 
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That IS a lot of work. Are you sure that's how you're expected to solve these problem? Our friend Lagrange cooked up a crispy formula just for these occasions. It says that if [itex]y_1(t)[/itex] and [itex]y_2(t)[/itex] are linearly independent solution to the homogeneous equation y'' + p(t)y' + q(t)y = 0, then a particular solution to the inhomogeneous equation y'' + p(t)y' + q(t)y=g(t) is

[tex]Y(t) = -y_1 \int \frac{y_2 g}{W(y_1,y_2)}dt + y_2\int\frac{y_1 g}{W(y1,y_2)}dt[/tex]
 

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