Solving the Equation 3x^2+8xy-3y^2=1 - What's Next?

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To solve the equation 3x^2 + 8xy - 3y^2 = 1 for y as a function of x, the next step involves differentiating the equation to find dy/dx. The differentiation process yields the expression 6x dx + 8(x dy + y dx) - 6y dy = 0. After obtaining this derivative, the goal is to isolate dy/dx to express it in terms of x and y. This approach will provide insights into the behavior of y as x changes. Understanding the derivative is crucial for further analysis of the implicit function defined by the equation.
BlackJack
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I have a questions:

Given is the equation 3x^2 +8xy-3y^2 = 1
I know have to find the function x -> y:=f(x) which is implicit defined by the equation above.
I have solved the question for x1,x2 = (4x+/- sqr(25x^2+3)) / 3

My question what do I have to do now?

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I am sorry but don't you need to look for \frac {dy}{dx} first by differentiating your given equation ?

This would be something like 6xdx + 8 (xdy + ydx) - 6ydy = 0 Then solve for \frac {dy}{dx}.

marlon
 

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